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iknow-lab 13

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List at least 10 films that falls into the Horror category.

film refers to title; Horror category refers to category.name = 'Horror'

SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror'

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Who among the actors starred in a NC-17 rated film? Provide only the last name of the actors.

NC-17 rated refers to rating = 'NC-17'

SELECT T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rating = 'NC-17'

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Calculate the average rate of renting the film that Lucille Tracy got starred.

average rate = divide(sum(rental_rate), count(film_id))

SELECT AVG(T3.rental_rate) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'LUCILLE' AND T1.last_name = 'TRACY'

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How many films have a duration between 100 to 110 minutes?

duration between 100 to 110 minutes refers to length between 100 and 110

SELECT COUNT(film_id) FROM film WHERE length BETWEEN 100 AND 110

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List down the actor ID of actors with Dee as their last name.

SELECT actor_id FROM actor WHERE last_name = 'Dee'

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Among the active customers, how many of them have Nina as their first name?

active refers to active = 1

SELECT COUNT(customer_id) FROM customer WHERE first_name = 'Nina' AND active = 1

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In store ID 2, how many of the films are R rating?

R rating refers to rating = 'R'

SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.store_id = 2 AND T1.rating = 'R'

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List the store ID of the films starred by Reese West with a duration of 100 minutes and below?

a duration of 100 minutes and below refers to length < 100

SELECT T4.store_id FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id WHERE T3.length < 100 AND T1.first_name = 'Reese' AND T1.last_name = 'West'

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Give the duration of the film starred by Nick Wahlberg with the highest rental rate.

duration refers to length; the highest rental rate refers to max(rental_rate)

SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Nick' AND T1.last_name = 'Wahlberg' ORDER BY T3.rental_rate DESC LIMIT 1

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What are the titles of the films starred by Russell Close?

SELECT T3.title FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T2.first_name = 'Russell' AND T2.last_name = 'Close'

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List the store ID of the film titled "Amadeus Holy".

SELECT T2.store_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T1.title = 'Amadeus Holy'

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In films with a rental rate of 2.99, how many of the films are starred by Nina Soto?

a rental rate of 2.99 refers to rental_rate = 2.99

SELECT COUNT(T1.film_id) FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id WHERE T3.rental_rate = 2.99 AND T2.first_name = 'Nina' AND T2.last_name = 'Soto'

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Among the films starred by Reese West, what is the difference between the films that have store ID of 1 and store ID of 2?

result = subtract(count(film_id where store_id = 1), count(film_id where store_id = 2))

SELECT SUM(IIF(T4.film_id = 1, 1, 0)) - SUM(IIF(T4.film_id = 2, 1, 0)) AS diff FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id WHERE T2.first_name = 'Reese' AND T2.last_name = 'West'

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What is the postal code of the address 692 Joliet Street?

SELECT postal_code FROM address WHERE address = '692 Joliet Street'

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How many customers are active?

active refers to active = 1

SELECT COUNT(customer_id) FROM customer WHERE active = 1

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Among all the customers of store no.1, how many of them are active?

active refers to active = 1

SELECT COUNT(customer_id) FROM customer WHERE active = 1 AND store_id = 1

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What is the address of Mary Smith?

SELECT T1.address FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'

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Among all the active customers, how many of them live in Arlington?

active refers to active = 1; Arlington refers to city = 'Arlington'

SELECT COUNT(T2.customer_id) FROM address AS T1 INNER JOIN customer AS T2 ON T1.address_id = T2.address_id INNER JOIN city AS T3 ON T1.city_id = T3.city_id WHERE T2.active = 1 AND T3.city = 'Arlington'

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Please list the full names of all the customers who live in Italy.

full name refers to first_name, last_name; Italy refers to country = 'Italy'

SELECT T4.first_name, T4.last_name FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id WHERE T3.country = 'Italy'

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Which country does Mary Smith live in?

SELECT T3.country FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id WHERE T4.first_name = 'MARY' AND T4.last_name = 'SMITH'

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What is the biggest amount of payment for a rental made by Mary Smith?

the biggest amount refers to max(amount)

SELECT T1.amount FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' ORDER BY T1.amount DESC LIMIT 1

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How many times has Mary Smith rented a film?

SELECT COUNT(T1.customer_id) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'

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What is the total amount of money Mary Smith has spent on film rentals?

the total amount = sum(amount)

SELECT SUM(T1.amount) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH'

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Among the times Mary Smith had rented a movie, how many of them happened in June, 2005?

in June 2005 refers to year(payment_date) = 2005 and month(payment_date) = 6

SELECT COUNT(T1.customer_id) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' AND STRFTIME('%Y',T1.payment_date) = '2005' AND STRFTIME('%Y', T1.payment_date) = '6'

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Please give the full name of the customer who had made the biggest amount of payment in one single film rental.

full name refers to first_name, last_name; the biggest amount refers to max(amount)

SELECT T2.first_name, T2.last_name FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id ORDER BY T1.amount DESC LIMIT 1

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How much in total had the customers in Italy spent on film rentals?

total = sum(amount); Italy refers to country = 'Italy'

SELECT SUM(T5.amount) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id INNER JOIN payment AS T5 ON T4.customer_id = T5.customer_id WHERE T3.country = 'Italy'

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Among the payments made by Mary Smith, how many of them are over 4.99?

over 4.99 refers to amount > 4.99

SELECT COUNT(T1.amount) FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'MARY' AND T2.last_name = 'SMITH' AND T1.amount > 4.99

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What is the average amount of money spent by a customer in Italy on a single film rental?

Italy refers to country = 'Italy'; average amount = divide(sum(amount), count(customer_id)) where country = 'Italy'

SELECT AVG(T5.amount) FROM address AS T1 INNER JOIN city AS T2 ON T1.city_id = T2.city_id INNER JOIN country AS T3 ON T2.country_id = T3.country_id INNER JOIN customer AS T4 ON T1.address_id = T4.address_id INNER JOIN payment AS T5 ON T4.customer_id = T5.customer_id WHERE T3.country = 'Italy'