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movie_3 | List the actors' IDs who have "KILMER" as last name. | SELECT actor_id FROM actor WHERE last_name = 'KILMER' | 9,200 | ||
movie_3 | List down the films titles with the lowest replacement cost under the general audiences rating. | lowest replacement cost refers to Min(replacement_cost); under general audience rating refers to rating = G | SELECT title FROM film WHERE replacement_cost = ( SELECT MIN(replacement_cost) FROM film ) | 9,201 | |
movie_3 | Among the films with the longest duration, list any five title with their descriptions and special features. | longest duration of film refers to Max(length) | SELECT title, description, special_features FROM film WHERE length = ( SELECT MAX(length) FROM film ) LIMIT 5 | 9,202 | |
movie_3 | How many films rented on 26th May, 2005 were returned on 30th May, 2005? | rented on 26th May 2005 refers to rental_date = '2005-05-26'; return on 30th May, 2005 refers to return_date = '2005-05-30'; number of rented film refers to Count (rental_id) | SELECT COUNT(DISTINCT rental_id) FROM rental WHERE date(rental_date) BETWEEN '2005-05-26' AND '2005-05-30' | 9,203 | |
movie_3 | Calculate the average payment amount per customer. | average payment refers to AVG(amount) | SELECT AVG(amount) FROM payment GROUP BY customer_id | 9,204 | |
movie_3 | What is the name and email of the staff in store ID 2? | name refers to first_name, last_name | SELECT first_name, last_name, email FROM staff WHERE store_id = 2 | 9,205 | |
movie_3 | How many percent of customers were inactive? | inactive refers to active = 0; percent = Divide (Count (customer_id where active = 0), Count(customer_id)) * 100 | SELECT CAST(SUM(IIF(active = 0, 1, 0)) AS REAL) * 100 / COUNT(customer_id) FROM customer | 9,206 | |
movie_3 | What is the description and film title of ID 996? | ID 996 refers to film_id = 996 | SELECT description, title FROM film_text WHERE film_id = 996 | 9,207 | |
movie_3 | Calculate customers' total payment amount in August, 2005. | in August 2005 refers to payment_date like '2005-08%'; total payment amount refers to Sum(amount) | SELECT SUM(amount) FROM payment WHERE SUBSTR(payment_date, 1, 7) = '2005-08' | 9,208 | |
movie_3 | List down the film titles performed by Emily Dee. | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Emily' AND T1.last_name = 'Dee' | 9,209 | ||
movie_3 | List down the actors' full names who performed in "CHOCOLATE DUCK" film. | "CHOCOLATE DUCK" is the title of film; full name refers to first_name, last_name | SELECT T3.first_name, T3.last_name FROM film_actor AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id INNER JOIN actor AS T3 ON T1.actor_id = T3.actor_id WHERE T2.title = 'CHOCOLATE DUCK' | 9,210 | |
movie_3 | How many films in the horror category were included in PG-13-rated? | "Horror" is the name of category; PG-13 rated refers to rating = 'PG-13' | SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Horror' AND T1.rating = 'PG-13' | 9,211 | |
movie_3 | Distinguish the films performed by Judy Dean according to category. | films performed refers to film | SELECT T5.name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN film_category AS T4 ON T2.film_id = T4.film_id INNER JOIN category AS T5 ON T4.category_id = T5.category_id WHERE T1.first_name = 'Judy' AND T1.last_name = 'Dean' | 9,212 | |
movie_3 | Write down any five film names under the documentary category. | "Documentary" is the name of category; film name refers to title | SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Documentary' LIMIT 5 | 9,213 | |
movie_3 | Mention the language of Untouchables Sunrise film and calculate its rental cost per day. | "UNTOUCHABLES SUNRISE" is the title of film; language refers to name; rental cost per day = Divide (rental_cost, rental_duration) | SELECT T2.name, T1.replacement_cost / T1.rental_duration AS cost FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T1.title = 'UNTOUCHABLES SUNRISE' | 9,214 | |
movie_3 | List the films' titles which were rented on 24th May,2005. | rented on 24th May 2005 refers to rental_date = '2005-05-24%' | SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id WHERE SUBSTR(T3.rental_date, 1, 10) = '2005-05-24' | 9,215 | |
movie_3 | List the films' titles which were rented by Brian Wyman in July, 2005. | rented in July 2005 refers to year (rental_date) = 2005 and month (rental_date) = 7 | SELECT T4.title FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'BRIAN' AND T1.last_name = 'WYMAN' AND STRFTIME('%Y', T2.rental_date) = '2005' AND STRFTIME('%m',T2.rental_date) = '7' | 9,216 | |
movie_3 | Write down the inventories' IDs and actors' names of "STREETCAR INTENTIONS". | "STREETCAR INTENTIONS" is the title of film; actor's names refers to first_name, last_name | SELECT T4.inventory_id, T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN inventory AS T4 ON T2.film_id = T4.film_id WHERE T3.title = 'STREETCAR INTENTIONS' | 9,217 | |
movie_3 | Among the films rented by Natalie Meyer, describe the titles and categories of the films which were rented in February 2006. | category refers to name; rented in February 2006 refers to year(rental_date) = 2006 and month (rental_rate) = 2 | SELECT T3.title, T2.name FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id INNER JOIN film AS T3 ON T1.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id INNER JOIN customer AS T5 ON T4.store_id = T5.store_id INNER JOIN rental AS T6 ON T4.inventory_id = T6.inventory_id WHERE T5.first_name = 'Natalie' AND T5.last_name = 'Meyer' AND STRFTIME('%Y',T3.rental_rate) = '2006' AND STRFTIME('%m',T3.rental_rate) = '2' | 9,218 | |
movie_3 | How many rental IDs belong to Eleanor Hunt? | 'Eleanor Hunt' is the full name of a customer; full name refers to first_name, last_name | SELECT COUNT(T1.rental_id) FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'Eleanor' AND T2.last_name = 'Hunt' | 9,219 | |
movie_3 | Describe the full names and cities of the customers who rented "DREAM PICKUP". | full name refers to first_name, last_name; 'DREAM PICKUP' is a title of film | SELECT T4.first_name, T4.last_name, T6.city FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id INNER JOIN rental AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN customer AS T4 ON T3.customer_id = T4.customer_id INNER JOIN address AS T5 ON T4.address_id = T5.address_id INNER JOIN city AS T6 ON T5.city_id = T6.city_id WHERE T1.title = 'DREAM PICKUP' | 9,220 | |
movie_3 | Calculate how many percent of customers were located in India. | 'India' is a country; calculation = DIVIDE(SUM(country = 'India'), COUNT(customer_id)) * 100 | SELECT CAST(SUM(IIF(T1.country = 'India', 1, 0)) AS REAL) * 100 / COUNT(T4.customer_id) FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id INNER JOIN customer AS T4 ON T3.address_id = T4.address_id | 9,221 | |
movie_3 | How much percentage of the film did Mary Keitel perform more than Angela Witherspoon? | 'Mary Keitel' AND 'Angela Witherspoon' are full name of actors; full name refers to FirstName, LastName; calculation = DIVIDE(SUBTRACT(SUM('Mary Keitel'), SUM('Angela Witherspoon')), SUM('Angela Witherspoon')) * 100 | SELECT CAST((SUM(IIF(T1.first_name = 'ANGELA' AND T1.last_name = 'WITHERSPOON', 1, 0)) - SUM(IIF(T1.first_name = 'MARY' AND T1.last_name = 'KEITEL', 1, 0))) AS REAL) * 100 / SUM(IIF(T1.first_name = 'MARY' AND T1.last_name = 'KEITEL', 1, 0)) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id | 9,222 | |
movie_3 | Provide the email, address, city, and country of the customer Lillie Kim. | 'Lillie Kim' is the full name of a customer; full name refers to first_name, last_name | SELECT T1.email, T2.address, T3.city, T4.country FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id INNER JOIN city AS T3 ON T2.city_id = T3.city_id INNER JOIN country AS T4 ON T3.country_id = T4.country_id WHERE T1.first_name = 'Lillie' AND T1.last_name = 'Kim' | 9,223 | |
movie_3 | Provide any 5 customers' full names who have rented from Mike Hillyer. | full name refers to first_name, last_name; 'Mike Hillyer' is a full name of a staff; | SELECT T3.first_name, T3.last_name FROM staff AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id WHERE T1.first_name = 'Mike' AND T1.last_name = 'Hillyer' LIMIT 5 | 9,224 | |
movie_3 | Calculate the total payment amount by Diane Collins. | 'Diane Collins' is a full name of a customer; full name refers to first_name, last_name | SELECT SUM(T2.amount) FROM customer AS T1 INNER JOIN payment AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'Diane' AND T1.last_name = 'Collins' | 9,225 | |
movie_3 | Provide the full names and emails of customers whose payments were greater than 70% of the average. | full name refers to first_name, last_name; average payment refers to AVG(amount); payments were greater than 70% of the average refers to amount > (AVG(amount) MULTIPLY 0.7) | SELECT DISTINCT T2.first_name, T2.last_name, T2.email FROM payment AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id INNER JOIN address AS T3 ON T2.address_id = T3.address_id WHERE T1.amount > ( SELECT AVG(amount) FROM payment ) * 0.7 | 9,226 | |
movie_3 | How many films have a rental rate of 0.99? | SELECT COUNT(film_id) FROM film WHERE rental_rate = 0.99 | 9,227 | ||
movie_3 | Among the customers with customer ID of 100 and below, how many of them have Thomas as their last name? | customer ID of 100 and below refers to customer_id < 100 | SELECT COUNT(customer_id) FROM customer WHERE last_name = 'Thomas' AND customer_id < 100 | 9,228 | |
movie_3 | List the actor's last name that starred the film with the description of "A Thoughtful Drama of a Composer And a Feminist who must Meet a Secret Agent in The Canadian Rockies". | SELECT T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.description = 'A Thoughtful Drama of a Composer And a Feminist who must Meet a Secret Agent in The Canadian Rockies' | 9,229 | ||
movie_3 | Give the title of the film starred by Liza Bergman with the highest replacement cost. | Liza Bergman' is a full name; full name refers to first_name, last_name; highest replacement cost refers to MAX(replacement_cost) | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Liza' AND T1.last_name = 'Bergman' ORDER BY replacement_cost DESC LIMIT 1 | 9,230 | |
movie_3 | Among films with store ID of 2, list the title of films with the highest rental rate. | highest rental rate refers to MAX(rental_rate) | SELECT T1.title FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.store_id = 2 ORDER BY rental_rate DESC LIMIT 1 | 9,231 | |
movie_3 | Among the films starred by Angelina Astaire, what is the title of the film with a replacement cost of 27.99? | Angelina Astaire' is a full name of an actor; full name refers to first_name, last_name | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Angelina' AND T1.last_name = 'Astaire' AND T3.replacement_cost = 27.99 | 9,232 | |
movie_3 | List the inventory ID of the film titled "African Egg". | 'African Egg' is a title of a film | SELECT T2.inventory_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T1.title = 'African Egg' | 9,233 | |
movie_3 | In films with a length duration of 113 minutes, how many of the films are starred by Kirk Jovovich? | length duration of 113 minutes refers to length = 113; 'Kirk Jovovich' is a full name of an actor; full name refers to first_name, last_name | SELECT COUNT(T1.actor_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.length = 113 AND T1.first_name = 'Kirk' AND T1.last_name = 'Jovovich' | 9,234 | |
movie_3 | In the film with an inventory ID between 20 to 60, how many of the films have a G rating? | G rating refers to rating = 'G' | SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T2.inventory_id BETWEEN 20 AND 60 AND T1.rating = 'G' | 9,235 | |
movie_3 | Among films with a rental rate of 4.99, what is the total number of films starred by Bob Fawcett? | Bob Fawcett' is a full name of an actor; full name refers to first_name, last_name | SELECT COUNT(T1.actor_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rental_rate = 4.99 AND T1.first_name = 'Bob' AND T1.last_name = 'Fawcett' | 9,236 | |
movie_3 | What is the inventory ID of the films starred by Russell Close with a duration between 110 to 150 minutes? | 'Russell Close' is a full name of an actor; full name refers to first_name, last_name; duration between 110 to 150 minutes refers to length BETWEEN 110 AND 150 | SELECT T4.inventory_id FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id WHERE T3.length BETWEEN 110 AND 150 AND T1.first_name = 'Russell' AND T1.last_name = 'Close' | 9,237 | |
movie_3 | What is the store and inventory ID of the film with the longest duration? | the longest duration refers to MAX(length) | SELECT T2.store_id, T2.inventory_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id ORDER BY T1.length DESC LIMIT 1 | 9,238 | |
movie_3 | List the titles of the films starred by Elvis Marx. | 'Elvis Marx' is a full name of a film; full name refers to first_name, last_name | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.length BETWEEN 110 AND 150 AND T1.first_name = 'Russell' AND T1.last_name = 'Close' | 9,239 | |
movie_3 | In films with rental rate of 4.99, list down the inventory ID of the films starred by Lucille Dee. | 'Lucille Dee' is a full name of an actor; full name refers to first_name, last_name | SELECT T4.inventory_id FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN inventory AS T4 ON T3.film_id = T4.film_id WHERE T1.first_name = 'Lucille' AND T1.last_name = 'Dee' AND T3.rental_rate = 4.99 | 9,240 | |
movie_3 | List the store ID of the films with a rental rate greater than the 60% of average rental rate of all listed films. | average rental rate of all listed films refers to AVG(rental_rate); rental rate greater than the 60% of average rental rate refers to rental_rate > (AVG(rental_rate)) MULTIPLY 0.6 | SELECT T2.store_id FROM film AS T1 INNER JOIN inventory AS T2 ON T1.film_id = T2.film_id WHERE T1.rental_rate > ( SELECT AVG(T1.rental_rate) * 0.6 FROM film AS T1 ) | 9,241 | |
movie_3 | Among the films starred by Nick Wahlberg, what is the percentage of the films with G rating? | 'Nick Wahlberg' is a full name of an actor; full name refers to first_name, last_name; G rating refers to rating = 'G'; calculation = DIVIDE(SUM(rating = 'G'), SUM(rating)) * 100 | SELECT CAST(SUM(IIF(T3.rating = 'G', 1, 0)) AS REAL) / COUNT(T3.film_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Elvis' AND T1.last_name = 'Marx' | 9,242 | |
movie_3 | List the address in Texas in the ascending order of city id. | 'Texas' is a district | SELECT address FROM address WHERE district = 'Texas' AND city_id = ( SELECT MIN(city_id) FROM address WHERE district = 'Texas' ) | 9,243 | |
movie_3 | Find the full name and email address of inactive customers whose record was created in 2006. | full name refers to first_name, last_name; record created in 2006 refers to create_date = 2006; inactive customers refers to active = 0 | SELECT first_name, last_name, email FROM customer WHERE STRFTIME('%Y',create_date) = '2006' AND active = 0 | 9,244 | |
movie_3 | What percentage of the movies are PG-13? | PG-13 is a rating; calculation = DIVIDE(SUM(rating = PG-13), SUM(rating)) * 100 | SELECT CAST(SUM(IIF(rating = 'PG-13', 1, 0)) AS REAL) * 100 / COUNT(film_id) FROM film | 9,245 | |
movie_3 | Please list the top ten movies with the most price per day in descending order of price per day. | movies with the most price per day refers to MAX(rental_rate) | SELECT title FROM film ORDER BY rental_rate / rental_duration DESC LIMIT 10 | 9,246 | |
movie_3 | Calculate the average rent amount paid by the customer with customer id 15. | average rent amount refers to AVG(amount) | SELECT AVG(amount) FROM payment WHERE customer_id = 15 | 9,247 | |
movie_3 | How many customers rented for an above-average period? | rented period refers to SUBTRACT(return_date, rental_date); calculation = rented period > (AVG(rented period)) | SELECT COUNT(customer_id) FROM rental WHERE return_date - rental_date > ( SELECT AVG(return_date - rental_date) FROM rental ) | 9,248 | |
movie_3 | Among the movies, what percentage are horror? | horror is a name of film category; calculation = DIVIDE(COUNT('horror'), COUNT(category_id)) * 100 | SELECT CAST(SUM(IIF(T2.name = 'horror', 1, 0)) AS REAL) * 100 / COUNT(T2.category_id) FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id | 9,249 | |
movie_3 | Give the full name of the actor who acted in the most number of movies? | full name refers to first_name, last_name; acted in the most number of movies refers to MAX(COUNT(film_id)) | SELECT T.first_name, T.last_name FROM ( SELECT T2.first_name, T2.last_name, COUNT(T1.film_id) AS num FROM film_actor AS T1 INNER JOIN actor AS T2 ON T1.actor_id = T2.actor_id GROUP BY T2.first_name, T2.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,250 | |
movie_3 | Give the full name of the actor who acted the most in drama movies? | full name refers to first_name, last_name; drama is a category of a film; acted the most in a movies refers to MAX(COUNT(film_id)) | SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T2.film_id) AS num FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film_category AS T3 ON T2.film_id = T3.film_id WHERE T3.category_id = 7 GROUP BY T1.first_name, T1.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,251 | |
movie_3 | What is the difference in the average number of films rented each day in Australia and Canada? | 'Australia' AND 'Canada' are country; average number of films refers to AVG('Australia') AND AVG('Canada'); calculation = SUBTRACT(AVG('Australia'), AVG('Canada')) | SELECT AVG(IIF(T4.country = 'Australia', 1, 0)) - AVG(IIF(T4.country = 'Canada', 1, 0)) AS diff FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id INNER JOIN city AS T3 ON T2.city_id = T3.city_id INNER JOIN country AS T4 ON T3.country_id = T4.country_id | 9,252 | |
movie_3 | Of the movies in which Reese Kilmer acted, what percentage are action movies? | 'Reese Kilmer' is a full name of an actor; 'action' is the name of the category; calculation = DIVIDE(COUNT('action'), COUNT(category_id)) * 100 | SELECT CAST(SUM(IIF(T4.name = 'Action', 1, 0)) AS REAL) * 100 / COUNT(T1.actor_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film_category AS T3 ON T2.film_id = T3.film_id INNER JOIN category AS T4 ON T3.category_id = T4.category_id WHERE T1.first_name = 'Reese' AND T1.last_name = 'Kilmer' | 9,253 | |
movie_3 | Give the total amount of rent for the movie Clockwork Paradice. | 'Clockwork Paradice' is a title of a film | SELECT SUM(T1.amount) FROM payment AS T1 INNER JOIN rental AS T2 ON T1.rental_id = T2.rental_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id WHERE T4.title = 'CLOCKWORK PARADICE' | 9,254 | |
movie_3 | Find and list the full name of customers who rented more than five types of movies. | full name refers to first_name, last_name; types of movies means category of movies;
rented more than five types of movies refers to COUNT(film_category) > 5 | SELECT T.first_name, T.last_name FROM ( SELECT T1.first_name, T1.last_name, COUNT(T1.customer_id) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id INNER JOIN film_category AS T5 ON T4.film_id = T5.film_id GROUP BY T1.first_name, T1.last_name ) AS T WHERE T.num > 5 | 9,255 | |
movie_3 | What is the average number of actors acted in comedy movies? | comedy is the name of a category; average number of actors refers to AVG(actor_id) | SELECT AVG(T1.actor_id) FROM film_actor AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id INNER JOIN actor AS T4 ON T4.actor_id = T1.actor_id WHERE T3.name = 'comedy' | 9,256 | |
movie_3 | In children's movies, which was rented the most? | children is the name of the category; rented the most refers to MAX(COUNT(title)) | SELECT T.title FROM ( SELECT T4.title, COUNT(T4.title) AS num FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film AS T4 ON T3.film_id = T4.film_id INNER JOIN film_category AS T5 ON T4.film_id = T5.film_id INNER JOIN category AS T6 ON T5.category_id = T6.category_id WHERE T6.name = 'Children' GROUP BY T4.title ) AS T ORDER BY T.num DESC LIMIT 1 | 9,257 | |
movie_3 | Calculate the percentage of customers who paid more than the average rent amount in store 1. | store 1 refers to store_id = 1; average rent amount refers to AVG(amount); calculation = DIVIDE(amount > AVG(amount), COUNT(customer_id)) * 100 | SELECT CAST(( SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN payment AS T2 ON T1.customer_id = T2.customer_id WHERE T2.amount > ( SELECT AVG(amount) FROM payment ) ) AS REAL) * 100 / ( SELECT COUNT(customer_id) FROM customer ) | 9,258 | |
movie_3 | Find and list the full name of customers who rented more family movies than Sci-Fi movies. | full name refers to first_name, last_name; 'family' AND 'Sci-Fi' are names of the category; customers who rented more family movies than Sci-Fi movies refers to count(name = 'Family') > count(name = 'Sci-Fi') | SELECT DISTINCT IIF(SUM(IIF(T5.name = 'Family', 1, 0)) - SUM(IIF(T5.name = 'Sci-Fi', 1, 0)) > 0, T1.first_name, 0) FROM customer AS T1 INNER JOIN rental AS T2 ON T1.customer_id = T2.customer_id INNER JOIN inventory AS T3 ON T2.inventory_id = T3.inventory_id INNER JOIN film_category AS T4 ON T4.film_id = T3.film_id INNER JOIN category AS T5 ON T4.category_id = T5.category_id GROUP BY T1.customer_id | 9,259 | |
movie_3 | Indicate the title of all the films rated as 'Adults Only'. | 'Adults Only' refers to rating = 'NC-17' | SELECT title FROM film WHERE rating = 'NC-17' | 9,260 | |
movie_3 | How many actors with the surname Kilmer are there? | surname means last_name; | SELECT COUNT(actor_id) FROM actor WHERE last_name = 'Kilmer' | 9,261 | |
movie_3 | How many movies have a length longer than 100? | length longer than 100 refers to length > 100 | SELECT COUNT(film_id) FROM film WHERE length > 100 | 9,262 | |
movie_3 | How many payments were made throughout the month of August 2005? | payments made refers to amount; throughout the month of August 2005 refers to payment_date like '2005-08%' | SELECT SUM(amount) FROM payment WHERE payment_date LIKE '2005-08%' | 9,263 | |
movie_3 | To which country does the address '1386 Nakhon Sawan Boulevard' belong? | SELECT T1.country FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id INNER JOIN address AS T3 ON T2.city_id = T3.city_id WHERE T3.address = '1386 Nakhon Sawan Boulevard' | 9,264 | ||
movie_3 | What language was the most used in movies released in 2006? | released in 2006 refers to release_year = 2006; the most used language refers to MAX(COUNT(language_id)) | SELECT T.language_id FROM ( SELECT T1.language_id, COUNT(T1.language_id) AS num FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE STRFTIME('%Y',T1.release_year) = '2006' GROUP BY T1.language_id ) AS T ORDER BY T.num DESC LIMIT 1 | 9,265 | |
movie_3 | Indicate the title of all the films that are in the Classics category. | 'classics' is the name of category | SELECT T2.title FROM film_category AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T1.category_id = T3.category_id WHERE T3.name = 'Classics' | 9,266 | |
movie_3 | How many rentals did Ella Oliver hire in June 2016? | 'Ella Oliver' is a full name of a customer; full name refers to first_name, last_name; rental hired in June 2016 refers to rental_date BETWEEN '2005-06-01' AND '2005-06-30' | SELECT COUNT(T1.rental_id) FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = 'ELLA' AND T2.last_name = 'ELLA' AND date(T1.rental_date) BETWEEN '2005-06-01' AND '2005-06-30' | 9,267 | |
movie_3 | How many different clients have rented materials from Jon Stephens? | 'Jon Stephens' is a full name of a customer; full name refers to first_name, last_name; | SELECT COUNT(T1.customer_id) FROM rental AS T1 INNER JOIN staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = 'Jon' AND T2.last_name = 'Stephens' | 9,268 | |
movie_3 | What is the total amount paid for rentals made on July 29, 2005? | July 29, 2005 refers to rental_date like '2005-07-29' | SELECT SUM(T2.amount) FROM rental AS T1 INNER JOIN payment AS T2 ON T1.rental_id = T2.rental_id WHERE date(T1.rental_date) = '2005-07-29%' | 9,269 | |
movie_3 | What is the first name of the customers whose address is in the postal code that begins with 76? | postal code that begins with 76 refers to postal_code like '76%' | SELECT T1.first_name FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id WHERE SUBSTR(T2.postal_code, 1, 2) = '76' | 9,270 | |
movie_3 | On what date was the rented material for the movie BLOOD ARGONAUTS returned? | 'BLOOD ARGONAUTS' is a title of a film; date a movie was returned refers to return_date | SELECT T1.rental_date FROM rental AS T1 INNER JOIN inventory AS T2 ON T1.inventory_id = T2.inventory_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'BLOOD ARGONAUTS' | 9,271 | |
movie_3 | What is the title of the films in which Cuba Allen acted? | 'Cuba Allen' is a full name of an actor; full name refers to first_name, last_name | SELECT T3.title FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T1.first_name = 'Cuba' AND T1.last_name = 'Allen' | 9,272 | |
movie_3 | How many actors acted in movies in the Music category? | Music' is a name of a category | SELECT COUNT(T1.actor_id) FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id INNER JOIN film_category AS T4 ON T3.film_id = T4.film_id INNER JOIN category AS T5 ON T4.category_id = T5.category_id WHERE T5.name = 'Music' | 9,273 | |
movie_3 | What is the full name of the actor who has acted the most times in comedy films? | full name refers to first_name, last_name; 'comedy' is a name of a category; | SELECT T.first_name, T.last_name FROM ( SELECT T4.first_name, T4.last_name, COUNT(T2.actor_id) AS num FROM film_category AS T1 INNER JOIN film_actor AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T1.category_id = T3.category_id INNER JOIN actor AS T4 ON T2.actor_id = T4.actor_id WHERE T3.name = 'Comedy' GROUP BY T4.first_name, T4.last_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,274 | |
movie_3 | How many customers did not rent material at Mike's store? | not at Mike's store refers to staff.first_name ! = 'Mike' | SELECT COUNT(T1.customer_id) FROM customer AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id INNER JOIN staff AS T3 ON T2.manager_staff_id = T3.staff_id WHERE T3.first_name != 'Mike' | 9,275 | |
movie_3 | Indicate the name of the actors of the films rated as 'Parents Strongly Precautioned' with the highest replacement cost. | name refers to first_name, last_name; Parents Strongly Precautioned' refers to rating = 'PG-13';
highest replacement cost refers to MAX(replacement_cost) | SELECT T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.rating = 'PG-13' ORDER BY T3.replacement_cost DESC LIMIT 1 | 9,276 | |
movie_3 | What is the name of the client who has the largest quantity of rented material without returning it? | name refers to first_name, last_name; without returning a rented material refers to return_date is null | SELECT T.first_name FROM ( SELECT T2.first_name, COUNT(T1.rental_date) AS num FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.first_name ) AS T ORDER BY T.num DESC LIMIT 1 | 9,277 | |
movie_3 | How many customers live in the city of Miyakonojo? | SELECT COUNT(T3.customer_id) FROM city AS T1 INNER JOIN address AS T2 ON T1.city_id = T2.city_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id WHERE T1.city = 'Miyakonojo' | 9,278 | ||
movie_3 | How many non-active clients have not returned the rented material? | non-active clients refers to active = 0; not returning a rented material refers to rental_date is null | SELECT COUNT(T2.customer_id) FROM rental AS T1 INNER JOIN customer AS T2 ON T1.customer_id = T2.customer_id WHERE T2.active = 0 | 9,279 | |
movie_3 | What is the title of the animated films that have the shortest length? | animated film means animation; animation is a name of a category | SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id ORDER BY T1.length LIMIT 1 | 9,280 | |
movie_3 | In which country is the store where Hector Poinexter rents equipment located? | 'Hector Poinexter' is a full name of a customer; full name refers to first_name, last_name; | SELECT T5.country FROM customer AS T1 INNER JOIN store AS T2 ON T1.store_id = T2.store_id INNER JOIN address AS T3 ON T2.address_id = T3.address_id INNER JOIN city AS T4 ON T3.city_id = T4.city_id INNER JOIN country AS T5 ON T4.country_id = T5.country_id WHERE T1.first_name = 'HECTOR' AND T1.last_name = 'POINDEXTER' | 9,281 | |
movie_3 | What is the average rental payment in Horror movies? | 'Horror' is a name of a category; average rental payment refers to AVG(amount) | SELECT AVG(T5.amount) FROM category AS T1 INNER JOIN film_category AS T2 ON T1.category_id = T2.category_id INNER JOIN inventory AS T3 ON T2.film_id = T3.film_id INNER JOIN rental AS T4 ON T3.inventory_id = T4.inventory_id INNER JOIN payment AS T5 ON T4.rental_id = T5.rental_id WHERE T1.name = 'Horror' | 9,282 | |
movie_3 | What is the average amount of rent that Christy Vargas paid? | 'Christy Vargas' is a full name of a customer; full name refers to first_name, last_name; average amount of rent refers to AVG(amount) | SELECT AVG(T2.amount) FROM customer AS T1 INNER JOIN payment AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'CHRISTY' AND T1.Last_name = 'VARGAS' | 9,283 | |
movie_3 | What percentage of films with a length of less than 100 belong to the Drama category? | Drama' is a name of a category; calculation = DIVIDE(SUM(length < 100 AND name = 'Drama'), COUNT(film_id)) * 100 | SELECT CAST(SUM(IIF(T2.length < 100 AND T3.name = 'Drama', 1, 0)) AS REAL) * 100 / COUNT(T1.film_id) FROM film_category AS T1 INNER JOIN film AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T1.category_id = T3.category_id | 9,284 | |
movie_3 | What are the actors that have the same forename as Johnny? Please include in your answer the full names of these actors. | forename means first_name; full name refers to first_name, last_name | SELECT first_name, last_name FROM actor WHERE first_name = 'Johnny' | 9,285 | |
movie_3 | What are the address numbers that are located in Gansu district? | address numbers refers to address_id; | SELECT address_id FROM address WHERE district = 'Gansu' | 9,286 | |
movie_3 | Please list three types of film along with their IDs and the latest update. | types of film refers to the name of a category; IDs refers to category_id; latest update refers to last_update. | SELECT DISTINCT name, category_id, last_update FROM category LIMIT 3 | 9,287 | |
movie_3 | Please list the full names of any three inactive customers. | full name refers to first_name, last_name; inactive customers refers to active = 0 | SELECT first_name, last_name FROM customer WHERE active = 0 LIMIT 3 | 9,288 | |
movie_3 | What is the rental price per day for Airplane Sierra? | rental price per day refers to DIVIDE(rental_price, rental_duration); 'Airplane Sierra' is a title of a film | SELECT rental_rate / rental_duration AS result FROM film WHERE title = 'AIRPLANE SIERRA' | 9,289 | |
movie_3 | Where is store number 2 located? | store number 2 refers to store_id = 2; where is a store located refers to address, address2, district | SELECT T1.address, T1.address2, T1.district FROM address AS T1 INNER JOIN store AS T2 ON T1.address_id = T2.address_id WHERE T2.store_id = 2 | 9,290 | |
movie_3 | Which city does the address 1623 Kingstown Drive belong to? | SELECT T1.city FROM city AS T1 INNER JOIN address AS T2 ON T2.city_id = T1.city_id WHERE T2.address = '1623 Kingstown Drive' | 9,291 | ||
movie_3 | Please name three cities that belong to Algeria. | Algeria is a country | SELECT T2.city FROM country AS T1 INNER JOIN city AS T2 ON T1.country_id = T2.country_id WHERE T1.country = 'Algeria' | 9,292 | |
movie_3 | What is the category of the film Agent Truman? | 'Agent Truman' is a title of a film; category refers to name | SELECT T3.name FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T1.title = 'AGENT TRUMAN' | 9,293 | |
movie_3 | Please list the titles of any three action films. | action is a name of category | SELECT T1.title FROM film AS T1 INNER JOIN film_category AS T2 ON T1.film_id = T2.film_id INNER JOIN category AS T3 ON T2.category_id = T3.category_id WHERE T3.name = 'Action' LIMIT 3 | 9,294 | |
movie_3 | What is the difference between the number of children's films and action films? | 'children' AND 'action' are names of a category; Calculation = SUBTRACT(AVG('children'), AVG('action')) | SELECT SUM(IIF(T2.name = 'Children', 1, 0)) - SUM(IIF(T2.name = 'Action', 1, 0)) AS diff FROM film_category AS T1 INNER JOIN category AS T2 ON T1.category_id = T2.category_id | 9,295 | |
movie_3 | Which district does Maria Miller live in? | 'Maria Miller' is a name of a customer; full name refers to first_name, last_name | SELECT T2.district FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = 'Maria' AND T1.last_name = 'Miller' | 9,296 | |
movie_3 | Who is the customer that is active and lives at 1795 Santiago de Compostela Way, Texas? | active refers to active = 1; '1795 Santiago de Compostela Way' is an address; Texas is a district; who refers to first_name, last_name | SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T2.address = '1795 Santiago de Compostela Way' AND T1.active = 1 | 9,297 | |
movie_3 | How many English films have a duration of over 50 minutes and the cost of replacement are under 10.99? | English is a name of a language; duration of over 50 minutes refers to length > 50; cost of replacement are under 10.99 refers to replacement_cost < 10.99 | SELECT COUNT(T1.film_id) FROM film AS T1 INNER JOIN language AS T2 ON T1.language_id = T2.language_id WHERE T2.name = 'English' AND T1.length > 50 AND T1.replacement_cost < 10.99 | 9,298 | |
movie_3 | Who are the actors that act in the ACADEMY DINOSAUR film? | Who are the actors refers to full name; full name refers to first_name, last_name; 'ACADEMY DINOSAUR' is a title of a film | SELECT T1.first_name, T1.last_name FROM actor AS T1 INNER JOIN film_actor AS T2 ON T1.actor_id = T2.actor_id INNER JOIN film AS T3 ON T2.film_id = T3.film_id WHERE T3.title = 'ACADEMY DINOSAUR' | 9,299 |