You are an expert in writing code in many different languages. Your goal is to perform code completion for the following code, keeping in mind the rest of the code and the file meta data.
    Metadata details:
    filename: user_authorization_test.go
    path of file: ./repos/nats-server/test
    
    the code of the file until where you have to start completion: // Copyright 2016-2019 The NATS Authors
// Licensed under the Apache License, Version 2.0 (the "License");
// you may not use this file except in compliance with the License.
// You may obtain a copy of the License at
//
// http://www.apache.org/licenses/LICENSE-2.0
//
// Unless required by applicable law or agreed to in writing, software
// distributed under the License is distributed on an "AS IS" BASIS,
// WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
// See the License for the specific language governing permissions and
// limitations under the License.

package test

import (
	"regexp"
	"testing"
	"time"
)

const DefaultPass = "foo"

var permErrRe = regexp.MustCompile(`\A\-ERR\s+'Permissions Violation([^\r\n]+)\r\
    
func TestUserAuthorizationAllowResponses(t *testing.T) {
	srv, opts := RunServerWithConfig("./configs/authorization.conf")
	defer srv.Shutdown()

	// Alice can do anything, so she will be our requestor
	rc := createClientConn(t, opts.Host, opts.Port)
	defer rc.Close()
	expectAuthRequired(t, rc)
	doAuthConnect(t, rc, "", "alice", DefaultPass)
	expectResult(t, rc, okRe)

	// MY_SERVICE can subscribe to a single request subject but can
	// respond to any reply subject that it receives, but only
	// for one response.
	c := createClientConn(t, opts.Host, opts.Port)
	defer c.Close()
	expectAuthRequired(t, c)
	doAuthConnect(t, c, "", "svca", DefaultPass)
	expectResult(t, c, okRe)

	sendProto(t, c, "SUB my.service.req 1\r\n")
	expectResult(t, c, okRe)

	sendProto(t, rc, "PUB my.service.req resp.bar.22 2\r\nok\r\n")
	expectResult(t, rc, okRe)

	matches := msgRe.FindAllSubmatch(expectResult(t, c, msgRe), -1)
	checkMsg(t, matches[0], "my.service.req", "1", "resp.bar.22", "2", "ok")

	// This should be allowed
	sendProto(t, c, "PUB resp.bar.22 2\r\nok\r\n")
	expectResult(t, c, okRe)

	// This should not be allowed
	sendProto(t, c, "PUB resp.bar.33 2\r\nok\r\n")
	expectResult(t, c, errRe)

	// This should also not be allowed now since we already sent a response and max is 1.
	sendProto(t, c, "PUB resp.bar.22 2\r\nok\r\n")
	expectResult(t, c, errRe)

	c.Close() // from MY_SERVICE

	// MY_STREAM_SERVICE can subscribe to a single request subject but can
	// respond to any reply subject that it receives, and send up to 10 responses.
	// Each permission for a response can last up to 10ms.
	c = createClientConn(t, opts.Host, opts.Port)
	defer c.Close()
	expectAuthRequired(t, c)
	doAuthConnect(t, c, "", "svcb", DefaultPass)
	expectResult(t, c, okRe)

	sendProto(t, c, "SUB my.service.req 1\r\n")
	expectResult(t, c, okRe)

	// Same rules as above.
	sendProto(t, rc, "PUB my.service.req resp.bar.22 2\r\nok\r\n")
	expectResult(t, rc, okRe)

	matches = msgRe.FindAllSubmatch(expectResult(t, c, msgRe), -1)
	checkMsg(t, matches[0], "my.service.req", "1", "resp.bar.22", "2", "ok")

	// This should be allowed
	sendProto(t, c, "PUB resp.bar.22 2\r\nok\r\n")
	expectResult(t, c, okRe)

	// This should not be allowed
	sendProto(t, c, "PUB resp.bar.33 2\r\nok\r\n")
	expectResult(t, c, errRe)

	// We should be able to send 9 more here since we are allowed 10 total
	for i := 0; i < 9; i++ {
		sendProto(t, c, "PUB resp.bar.22 2\r\nok\r\n")
		expectResult(t, c, okRe)
	}
	// Now this should fail since we already sent 10 responses.
	sendProto(t, c, "PUB resp.bar.22 2\r\nok\r\n")
	expectResult(t, c, errRe)

	// Now test timeout.
	sendProto(t, rc, "PUB my.service.req resp.bar.11 2\r\nok\r\n")
	expectResult(t, rc, okRe)

	matches = msgRe.FindAllSubmatch(expectResult(t, c, msgRe), -1)
	checkMsg(t, matches[0], "my.service.req", "1", "resp.bar.11", "2", "ok")

	time.Sleep(100 * time.Millisecond)

	sendProto(t, c, "PUB resp.bar.11 2\r\nok\r\n")
	expectResult(t, c, errRe)
}