You are an expert in writing code in many different languages. Your goal is to perform code completion for the following code, keeping in mind the rest of the code and the file meta data.
    Metadata details:
    filename: sine_of_the_times.m
    path of file: ./repos/HRTF-Individualization/model/matlabcode/functions/library/RealTimeAudioProcessor
    
    the code of the file until where you have to start completion: % [out, state_out] = sine_of_the_times(times, in, state_in)
% 
% This function works as a handle for the HandlePlayer object. Given a set
% of times, inputs, and a current state, it returns corresponding outputs
% and a final state. Here, the left output channel (channel 1) will be
% calculated as a sine wave of a certain frequency over the given time,
% while the right channel (channel 2) is calculated from the propagation of
% an input state over time (a simple harmonic oscillator). If you can't
% hear a difference between the left and right channels, then it's working!
%
% Tucker McClure @ The MathWorks
% Copyright 2012 The MathWorks, Inc
    
function works as a handle for the HandlePlayer object. Given a set
% of times, inputs, and a current state, it returns corresponding outputs
% and a final state. Here, the left output channel (channel 1) will be
% calculated as a sine wave of a certain frequency over the given time,
% while the right channel (channel 2) is calculated from the propagation of
% an input state over time (a simple harmonic oscillator). If you can't
% hear a difference between the left and right channels, then it's working!
%
% Tucker McClure @ The MathWorks
% Copyright 2012 The MathWorks, Inc.

function [out, state_out] = sine_of_the_times(times, in, state_in)

    % Frequency to use for sin and state transition matrix [rad/s]
    f = 440 * 2 * pi;
    
    % Create a sine wave directly.
    outL = sin(times * f);
    
    % Use a state space representation to create the dynamics we want.
    outR = zeros(length(times), 1);
    
    % Calculate the state transition matrix. Note that this happens every
    % time but is actually constant; this is therefore best suited to an
    % initialization routine. We could build therefore build an object
    % instead of using this 'handle' method. Alternately, we could have
    % precomputed constants passed to this function from an initialization
    % function.
    k_over_m = f^2;
    c_over_m = 0.1;
    A = [0 1; -k_over_m -c_over_m];
    dt = diff(times(1:2));
%     Phi = expm(A * dt); % Exact solution
    Phi = (eye(2) + 0.5*dt*A) / (eye(2) - 0.5*dt*A); % Bilinear transform
    
    % Propagate the state by discrete steps.
    state_out = state_in;
    for k = 1:length(times)
        state_out = Phi * state_out;
        outR(k, 1) = state_out(1);
    end