You are an expert in writing code in many different languages. Your goal is to perform code completion for the following code, keeping in mind the rest of the code and the file meta data.
    Metadata details:
    filename: d.go
    path of file: ./repos/codeforces-go/leetcode/weekly/346/d
    
    the code of the file until where you have to start completion: package main

import "math"

// https://space.bilibili.com/206214
func modifiedGraphEdges(n int, edges [][]int, source, destination, target int) [][]int {
	type edge struct{ to, eid int }
	g := make([][]edge, n)
	for i, e := range edges {
		x, y := e[0], e[1]
		g[x] = append(g[x], edge{y, i})
		g[y] = append(g[y], edge{x, i}) // 建图，额外保存边的编号
	}

	var delta int
	dis := make([][2]int, n)
	for i := range dis {
		dis[i][0] = math.MaxInt32 / 2
		dis[i][1] = math.MaxInt32 / 2
	}
	dis[source] = [2]int{}
	dijkstra := func(k int) {
		vis := make([]bool, n)
		for {
			// 找一个最短路最小并且还没有 vis 的点（第一轮循环找的是起点 source）
			x := -1
			for y, b := range vis {
				if !b && (x < 0 || dis[y][k] < dis[x][k]) {
					x = y
				}
			}
			if x == destination { // 起点 source 到终点 destination 的最短路已确定
				return
			}
			vis[x] = true // 标记，在后续的循环中无需反复更新 x 到其余点的最短路长度
			for _, e := range g[x] {
				y, wt := e.to, edges[e.eid][2]
				if wt == -1 {
					wt = 1 // -1 改成 1
				}
				if k == 1 && edges[e.eid][2] == -1 {
					// 第二次 Dijkstra，改成 w
					w := delta + dis[y][0] - dis[x][1]
					if w > wt {
						wt = w
						edges[e.eid][2] = w // 直接在 edges 上修改
					}
				}
				// 更新最短路
				dis[y][k] = min(dis[y][k], dis[x][k]+wt)
			}
		}
	}

	dijkstra(0)
	delta = target - dis[destination][0]
	if delta
    
func modifiedGraphEdges(n int, edges [][]int, source, destination, target int) [][]int {
	type edge struct{ to, eid int }
	g := make([][]edge, n)
	for i, e := range edges {
		x, y := e[0], e[1]
		g[x] = append(g[x], edge{y, i})
		g[y] = append(g[y], edge{x, i}) // 建图，额外保存边的编号
	}

	var delta int
	dis := make([][2]int, n)
	for i := range dis {
		dis[i][0] = math.MaxInt32 / 2
		dis[i][1] = math.MaxInt32 / 2
	}
	dis[source] = [2]int{}
	dijkstra := func(k int) {
		vis := make([]bool, n)
		for {
			// 找一个最短路最小并且还没有 vis 的点（第一轮循环找的是起点 source）
			x := -1
			for y, b := range vis {
				if !b && (x < 0 || dis[y][k] < dis[x][k]) {
					x = y
				}
			}
			if x == destination { // 起点 source 到终点 destination 的最短路已确定
				return
			}
			vis[x] = true // 标记，在后续的循环中无需反复更新 x 到其余点的最短路长度
			for _, e := range g[x] {
				y, wt := e.to, edges[e.eid][2]
				if wt == -1 {
					wt = 1 // -1 改成 1
				}
				if k == 1 && edges[e.eid][2] == -1 {
					// 第二次 Dijkstra，改成 w
					w := delta + dis[y][0] - dis[x][1]
					if w > wt {
						wt = w
						edges[e.eid][2] = w // 直接在 edges 上修改
					}
				}
				// 更新最短路
				dis[y][k] = min(dis[y][k], dis[x][k]+wt)
			}
		}
	}

	dijkstra(0)
	delta = target - dis[destination][0]
	if delta < 0 { // -1 全改为 1 时，最短路比 target 还大
		return nil
	}

	dijkstra(1)
	if dis[destination][1] < target { // 最短路无法再变大，无法达到 target
		return nil
	}

	for _, e := range edges {
		if e[2] == -1 { // 剩余没修改的边全部改成 1
			e[2] = 1
		}
	}
	return edges
}