You are an expert in writing code in many different languages. Your goal is to perform code completion for the following code, keeping in mind the rest of the code and the file meta data.
    Metadata details:
    filename: Mindist.m
    path of file: ./repos/opt_matlab/第10章/例10.4
    
    the code of the file until where you have to start completion: function [path,dist,dist1]=Mindist(M,varargin)    %图论中求最短路
    %dist      ：最短距离矩阵
    %dist1     ：带有顶点编号的最短距离矩阵
    %M             ：图的权值矩阵
    %k1,k2　　　　　：起点和终点
    %j1,j2         :必经过的点
%（1）根据图的权值矩阵求解任意两点间的最短距离
if nargin==1
    [path,dist,dist0]=pointdist(M);  
elseif nargin==4 && varargin{3}==1     %求k1、k2之间的最短路

    
function [path,dist,dist1]=Mindist(M,varargin)    %图论中求最短路
    %dist      ：最短距离矩阵
    %dist1     ：带有顶点编号的最短距离矩阵
    %M             ：图的权值矩阵
    %k1,k2　　　　　：起点和终点
    %j1,j2         :必经过的点
%（1）根据图的权值矩阵求解任意两点间的最短距离
if nargin==1
    [path,dist,dist0]=pointdist(M);  
elseif nargin==4 && varargin{3}==1     %求k1、k2之间的最短路
     k1=varargin{1};k2=varargin{2};
     [path,dist,dist0]=pointdist(M,k1,k2); 
elseif nargin==4 && varargin{3}==2     %求k1、k2之间的次短路
     k1=varargin{1};k2=varargin{2};
     [path1,distance1,dist0]=pointdist(M,k1,k2);
     n=length(path1); %k1、k2之间的最短路上的顶点数
     distance2=inf; %赋予distance2初值为无穷大
     for i=1:n-1
         M1=M;
         %删除最短路上的一条边
         M1(path1(i),path1(i+1))=inf;
         M1(path1(i+1),path1(i))=inf;
         [path,distance]=pointdist(M1,k1,k2); %求新图的最短路――次最短路
         if distance<distance2
            distance2=distance;
            path2=path;
         end