You are an expert in writing code in many different languages. Your goal is to perform code completion for the following code, keeping in mind the rest of the code and the file meta data.
    Metadata details:
    filename: no_short_circuit_type_constraint_nested.rb
    path of file: ./repos/sorbet/test/testdata/infer
    
    the code of the file until where you have to start completion: # typed: true

# The problem demonstrated in this test is very similar to the one in
# no_short_circuit_type_constraint.rb. The core problem boils down to Sorbet's
# type constraints accumulating greedily.
#
# There is more context in that test. For the time being, it's not _wrong_ for
# Sorbet to infer this type, it's just not quite as narrow as you'd want it to
# be.
#
# It's also worth noting that sometimes users don't have control over how their
# nested types are created--the order may be determined by the order that
# Sorbet lubs basic block branches and glbs type tests. So sometimes the bad
# case below can happen because of no fault of the user.

module M1; end
module M2; end

module A; end
module B; end

module Main
  extend T::Sig

  # Type signature indicates that we're trying to remove the `B` from the input.
  sig do
    type_parameters(:U)
      .params(x: T.any(T.type_parameter(:U), B))
      .returns(T.type_parameter(:U))
  end
  def self.remove_the_b(x)
    case x
    when B then raise
    else x
    end
  end

  sig do
    type_parameters(:U)
      .params(x: T.all(M1, T.any(A, B), M2))
      .void
  end
  def self.test1(x)
    # Sorbet gets this type because when faced with a type like
    #
    #   X & Y  <:  A | B
    #
    # It needs to decide which comparison to do first: split the OrType:
    #   X & Y
    
  def self.test1(x)
    # Sorbet gets this type because when faced with a type like
    #
    #   X & Y  <:  A | B
    #
    # It needs to decide which comparison to do first: split the OrType:
    #   X & Y <: A   ||   X & Y <: B
    # or split the AndType:
    #   X <: A | B   ||   Y <: A | B
    # Since Sorbet's inference algorithm is greedy, one of the two choices will
    # always be wrong. In our case, `A` is actually `T.type_parameter(:U)`, and
    # the `OrType` is split first, which leads to a comparison like
    #
    #      X & Y  <:  T.type_parameter(:U)
    #   => T.all(T.all(M1, T.any(A, B)), M2)  <:  T.type_parameter(:U)
    #
    # which has the effect of recording the `B` in the type parameter, instead
    # of dropping it.
    #
    # Ideally, this would reveal `T.all(M1, A, M2)` or something similar
    inferred = remove_the_b(x)
    T.reveal_type(inferred) # error: `T.all(M1, T.any(A, B), M2)`
  end

  sig do
    type_parameters(:U)
      .params(x: T.all(M1, M2, T.any(A, B)))
      .void
  end
  def self.test2(x)
    # Written this way, things work, because we have a special case which
    # unwraps a specific case of an OrType nested inside an AndType:
    #
    #      X & (F | G)        <:  t2
    #   => (X & F) | (X & G)  <:  t2
    #
    # That is, we distribute and continue, which splits the A | B.

    inferred = remove_the_b(x)
    T.reveal_type(inferred) # error: `T.all(A, M1, M2)`
  end
end