(loc,strg)
return 1 if 0<loc<len(s) and s[loc-1] == '\n' else loc - s.rfind("\n", 0, loc)
Returns current column within a string, counting newlines as line separators.
   The first column is number 1.

   Note: the default parsing behavior is to expand tabs in the input string
   before starting the parsing process.  See L{I{ParserElement.parseString}<ParserElement.parseString>} for more information
   on parsing strings containing C{<TAB>}s, and suggested methods to maintain a
   consistent view of the parsed string, the parse location, and line and column
   positions within the parsed string.
Returns current column within a string, counting newlines as line separators.
   The first column is number 1.
Returns current column within a string counting newlines as line separators . The first column is number 1 .
def col (loc,strg):
    """Returns current column within a string, counting newlines as line separators.
   The first column is number 1.

   Note: the default parsing behavior is to expand tabs in the input string
   before starting the parsing process.  See L{I{ParserElement.parseString}<ParserElement.parseString>} for more information
   on parsing strings containing C{<TAB>}s, and suggested methods to maintain a
   consistent view of the parsed string, the parse location, and line and column
   positions within the parsed string.
   """
    s = strg
    return 1 if 0<loc<len(s) and s[loc-1] == '\n' else loc - s.rfind("\n", 0, loc)
def col ( loc , strg ) : s = strg return 1 if 0 < loc < len ( s ) and s [ loc - 1 ] == '\n' else loc - s . rfind ( "\n" , 0 , loc )