(x)
return T.maximum(0.01*x,x)
hard-coded leaky relu
hard-coded leaky relu
hard - coded leaky relu
def leaky_relu_001(x):
    """ hard-coded leaky relu """
    return T.maximum(0.01*x,x)
def leaky_relu_001 ( x ) : return T . maximum ( 0.01 * x , x )