(self, query, pagenum, pagelen=10, **kwargs)
return ResultsPage(results, pagenum, pagelen)
This method is Like the :meth:`Searcher.search` method, but returns
        a :class:`ResultsPage` object. This is a convenience function for
        getting a certain "page" of the results for the given query, which is
        often useful in web search interfaces.

        For example::

            querystring = request.get("q")
            query = queryparser.parse("content", querystring)

            pagenum = int(request.get("page", 1))
            pagelen = int(request.get("perpage", 10))

            results = searcher.search_page(query, pagenum, pagelen=pagelen)
            print("Page %d of %d" % (results.pagenum, results.pagecount))
            print("Showing results %d-%d of %d"
                  % (results.offset + 1, results.offset + results.pagelen + 1,
                     len(results)))
            for hit in results:
                print("%d: %s" % (hit.rank + 1, hit["title"]))

        (Note that results.pagelen might be less than the pagelen argument if
        there aren't enough results to fill a page.)

        Any additional keyword arguments you supply are passed through to
        :meth:`Searcher.search`. For example, you can get paged results of a
        sorted search::

            results = searcher.search_page(q, 2, sortedby="date", reverse=True)

        Currently, searching for page 100 with pagelen of 10 takes the same
        amount of time as using :meth:`Searcher.search` to find the first 1000
        results. That is, this method does not have any special optimizations
        or efficiencies for getting a page from the middle of the full results
        list. (A future enhancement may allow using previous page results to
        improve the efficiency of finding the next page.)

        This method will raise a ``ValueError`` if you ask for a page number
        higher than the number of pages in the resulting query.

        :param query: the :class:`whoosh.query.Query` object to match.
        :param pagenum: the page number to retrieve, starting at ``1`` for the
            first page.
        :param pagelen: the number of results per page.
        :returns: :class:`ResultsPage`
This method is Like the :meth:`Searcher.search` method, but returns
        a :class:`ResultsPage` object. This is a convenience function for
        getting a certain "page" of the results for the given query, which is
        often useful in web search interfaces.
This method is Like the : meth : Searcher . search method but returns a : class : ResultsPage object . This is a convenience function for getting a certain page of the results for the given query which is often useful in web search interfaces .
def search_page(self, query, pagenum, pagelen=10, **kwargs):
        """This method is Like the :meth:`Searcher.search` method, but returns
        a :class:`ResultsPage` object. This is a convenience function for
        getting a certain "page" of the results for the given query, which is
        often useful in web search interfaces.

        For example::

            querystring = request.get("q")
            query = queryparser.parse("content", querystring)

            pagenum = int(request.get("page", 1))
            pagelen = int(request.get("perpage", 10))

            results = searcher.search_page(query, pagenum, pagelen=pagelen)
            print("Page %d of %d" % (results.pagenum, results.pagecount))
            print("Showing results %d-%d of %d"
                  % (results.offset + 1, results.offset + results.pagelen + 1,
                     len(results)))
            for hit in results:
                print("%d: %s" % (hit.rank + 1, hit["title"]))

        (Note that results.pagelen might be less than the pagelen argument if
        there aren't enough results to fill a page.)

        Any additional keyword arguments you supply are passed through to
        :meth:`Searcher.search`. For example, you can get paged results of a
        sorted search::

            results = searcher.search_page(q, 2, sortedby="date", reverse=True)

        Currently, searching for page 100 with pagelen of 10 takes the same
        amount of time as using :meth:`Searcher.search` to find the first 1000
        results. That is, this method does not have any special optimizations
        or efficiencies for getting a page from the middle of the full results
        list. (A future enhancement may allow using previous page results to
        improve the efficiency of finding the next page.)

        This method will raise a ``ValueError`` if you ask for a page number
        higher than the number of pages in the resulting query.

        :param query: the :class:`whoosh.query.Query` object to match.
        :param pagenum: the page number to retrieve, starting at ``1`` for the
            first page.
        :param pagelen: the number of results per page.
        :returns: :class:`ResultsPage`
        """

        if pagenum < 1:
            raise ValueError("pagenum must be >= 1")

        results = self.search(query, limit=pagenum * pagelen, **kwargs)
        return ResultsPage(results, pagenum, pagelen)
def search_page ( self , query , pagenum , pagelen = 10 , * * kwargs ) : if pagenum < 1 : raise ValueError ( "pagenum must be >= 1" ) results = self . search ( query , limit = pagenum * pagelen , * * kwargs ) return ResultsPage ( results , pagenum , pagelen )