(manager, resource_name)
Return a true filesystem path for `resource_name`

        `manager` must be an ``IResourceManager``
Return a true filesystem path for `resource_name`
Return a true filesystem path for resource_name
def get_resource_filename(manager, resource_name):
        """Return a true filesystem path for `resource_name`

        `manager` must be an ``IResourceManager``"""
def get_resource_filename ( manager , resource_name ) :