(l, k, ordered=None)
Return sequence ``l`` partitioned into ``k`` bins.

    Examples
    ========

    >>> from sympy.utilities.iterables import kbins

    The default is to give the items in the same order, but grouped
    into k partitions without any reordering:

    >>> from __future__ import print_function
    >>> for p in kbins(list(range(5)), 2):
    ...     print(p)
    ...
    [[0], [1, 2, 3, 4]]
    [[0, 1], [2, 3, 4]]
    [[0, 1, 2], [3, 4]]
    [[0, 1, 2, 3], [4]]

    The ``ordered`` flag which is either None (to give the simple partition
    of the the elements) or is a 2 digit integer indicating whether the order of
    the bins and the order of the items in the bins matters. Given::

        A = [[0], [1, 2]]
        B = [[1, 2], [0]]
        C = [[2, 1], [0]]
        D = [[0], [2, 1]]

    the following values for ``ordered`` have the shown meanings::

        00 means A == B == C == D
        01 means A == B
        10 means A == D
        11 means A == A

    >>> for ordered in [None, 0, 1, 10, 11]:
    ...     print('ordered = %s' % ordered)
    ...     for p in kbins(list(range(3)), 2, ordered=ordered):
    ...         print('     %s' % p)
    ...
    ordered = None
         [[0], [1, 2]]
         [[0, 1], [2]]
    ordered = 0
         [[0, 1], [2]]
         [[0, 2], [1]]
         [[0], [1, 2]]
    ordered = 1
         [[0], [1, 2]]
         [[0], [2, 1]]
         [[1], [0, 2]]
         [[1], [2, 0]]
         [[2], [0, 1]]
         [[2], [1, 0]]
    ordered = 10
         [[0, 1], [2]]
         [[2], [0, 1]]
         [[0, 2], [1]]
         [[1], [0, 2]]
         [[0], [1, 2]]
         [[1, 2], [0]]
    ordered = 11
         [[0], [1, 2]]
         [[0, 1], [2]]
         [[0], [2, 1]]
         [[0, 2], [1]]
         [[1], [0, 2]]
         [[1, 0], [2]]
         [[1], [2, 0]]
         [[1, 2], [0]]
         [[2], [0, 1]]
         [[2, 0], [1]]
         [[2], [1, 0]]
         [[2, 1], [0]]

    See Also
    ========
    partitions, multiset_partitions
Return sequence ``l`` partitioned into ``k`` bins.
Return sequence l partitioned into k bins .
def kbins(l, k, ordered=None):
    """
    Return sequence ``l`` partitioned into ``k`` bins.

    Examples
    ========

    >>> from sympy.utilities.iterables import kbins

    The default is to give the items in the same order, but grouped
    into k partitions without any reordering:

    >>> from __future__ import print_function
    >>> for p in kbins(list(range(5)), 2):
    ...     print(p)
    ...
    [[0], [1, 2, 3, 4]]
    [[0, 1], [2, 3, 4]]
    [[0, 1, 2], [3, 4]]
    [[0, 1, 2, 3], [4]]

    The ``ordered`` flag which is either None (to give the simple partition
    of the the elements) or is a 2 digit integer indicating whether the order of
    the bins and the order of the items in the bins matters. Given::

        A = [[0], [1, 2]]
        B = [[1, 2], [0]]
        C = [[2, 1], [0]]
        D = [[0], [2, 1]]

    the following values for ``ordered`` have the shown meanings::

        00 means A == B == C == D
        01 means A == B
        10 means A == D
        11 means A == A

    >>> for ordered in [None, 0, 1, 10, 11]:
    ...     print('ordered = %s' % ordered)
    ...     for p in kbins(list(range(3)), 2, ordered=ordered):
    ...         print('     %s' % p)
    ...
    ordered = None
         [[0], [1, 2]]
         [[0, 1], [2]]
    ordered = 0
         [[0, 1], [2]]
         [[0, 2], [1]]
         [[0], [1, 2]]
    ordered = 1
         [[0], [1, 2]]
         [[0], [2, 1]]
         [[1], [0, 2]]
         [[1], [2, 0]]
         [[2], [0, 1]]
         [[2], [1, 0]]
    ordered = 10
         [[0, 1], [2]]
         [[2], [0, 1]]
         [[0, 2], [1]]
         [[1], [0, 2]]
         [[0], [1, 2]]
         [[1, 2], [0]]
    ordered = 11
         [[0], [1, 2]]
         [[0, 1], [2]]
         [[0], [2, 1]]
         [[0, 2], [1]]
         [[1], [0, 2]]
         [[1, 0], [2]]
         [[1], [2, 0]]
         [[1, 2], [0]]
         [[2], [0, 1]]
         [[2, 0], [1]]
         [[2], [1, 0]]
         [[2, 1], [0]]

    See Also
    ========
    partitions, multiset_partitions

    """

    if ordered is None:
        for p in iter_partition(l, k):
            yield p
    elif ordered == 11:
        for pl in multiset_permutations(l):
            pl = list(pl)
            for p in iter_partition(pl, k):
                yield p
    elif ordered == 00:
        for p in multiset_partitions(l, k):
            yield p
    elif ordered == 10:
        for p in multiset_partitions(l, k):
            for perm in permutations(p):
                yield list(perm)
    elif ordered == 1:
        for kgot, p in partitions(len(l), k, size=True):
            if kgot != k:
                continue
            for li in multiset_permutations(l):
                rv = []
                i = j = 0
                li = list(li)
                for size, multiplicity in sorted(p.items()):
                    for m in range(multiplicity):
                        j = i + size
                        rv.append(li[i: j])
                        i = j
                yield rv
    else:
        raise ValueError(
            'ordered must be one of 00, 01, 10 or 11, not %s' % ordered)
def kbins ( l , k , ordered = None ) : if ordered is None : for p in iter_partition ( l , k ) : yield p elif ordered == 11 : for pl in multiset_permutations ( l ) : pl = list ( pl ) for p in iter_partition ( pl , k ) : yield p elif ordered == 00 : for p in multiset_partitions ( l , k ) : yield p elif ordered == 10 : for p in multiset_partitions ( l , k ) : for perm in permutations ( p ) : yield list ( perm ) elif ordered == 1 : for kgot , p in partitions ( len ( l ) , k , size = True ) : if kgot != k : continue for li in multiset_permutations ( l ) : rv = [ ] i = j = 0 li = list ( li ) for size , multiplicity in sorted ( p . items ( ) ) : for m in range ( multiplicity ) : j = i + size rv . append ( li [ i : j ] ) i = j yield rv else : raise ValueError ( 'ordered must be one of 00, 01, 10 or 11, not %s' % ordered )