(sources_groups, targets)
return n_sources, n_targets
Walk both arguments in parallel, testing if each source group is newer
    than its corresponding target. Returns a pair of lists (sources_groups,
    targets) where sources is newer than target, according to the semantics
    of 'newer_group()'.
Walk both arguments in parallel, testing if each source group is newer
    than its corresponding target. Returns a pair of lists (sources_groups,
    targets) where sources is newer than target, according to the semantics
    of 'newer_group()'.
Walk both arguments in parallel testing if each source group is newer than its corresponding target . Returns a pair of lists ( sources_groups targets ) where sources is newer than target according to the semantics of newer_group () .
def newer_pairwise_group(sources_groups, targets):
    """Walk both arguments in parallel, testing if each source group is newer
    than its corresponding target. Returns a pair of lists (sources_groups,
    targets) where sources is newer than target, according to the semantics
    of 'newer_group()'.
    """
    if len(sources_groups) != len(targets):
        raise ValueError("'sources_group' and 'targets' must be the same length")

    # build a pair of lists (sources_groups, targets) where source is newer
    n_sources = []
    n_targets = []
    for i in range(len(sources_groups)):
        if newer_group(sources_groups[i], targets[i]):
            n_sources.append(sources_groups[i])
            n_targets.append(targets[i])

    return n_sources, n_targets
def newer_pairwise_group ( sources_groups , targets ) : if len ( sources_groups ) != len ( targets ) : raise ValueError ( "'sources_group' and 'targets' must be the same length" ) # build a pair of lists (sources_groups, targets) where source is newer n_sources = [ ] n_targets = [ ] for i in range ( len ( sources_groups ) ) : if newer_group ( sources_groups [ i ] , targets [ i ] ) : n_sources . append ( sources_groups [ i ] ) n_targets . append ( targets [ i ] ) return n_sources , n_targets