(loc,strg)
return 1 if 0<loc<len(s) and s[loc-1] == '\n' else loc - s.rfind("\n", 0, loc)
Returns current column within a string, counting newlines as line separators.
   The first column is number 1.

   Note: the default parsing behavior is to expand tabs in the input string
   before starting the parsing process.  See
   :class:`ParserElement.parseString` for more
   information on parsing strings containing ``<TAB>`` s, and suggested
   methods to maintain a consistent view of the parsed string, the parse
   location, and line and column positions within the parsed string.
Returns current column within a string, counting newlines as line separators.
   The first column is number 1.
Returns current column within a string counting newlines as line separators . The first column is number 1 .
def col (loc,strg):
    """Returns current column within a string, counting newlines as line separators.
   The first column is number 1.

   Note: the default parsing behavior is to expand tabs in the input string
   before starting the parsing process.  See
   :class:`ParserElement.parseString` for more
   information on parsing strings containing ``<TAB>`` s, and suggested
   methods to maintain a consistent view of the parsed string, the parse
   location, and line and column positions within the parsed string.
   """
    s = strg
    return 1 if 0<loc<len(s) and s[loc-1] == '\n' else loc - s.rfind("\n", 0, loc)
def col ( loc , strg ) : s = strg return 1 if 0 < loc < len ( s ) and s [ loc - 1 ] == '\n' else loc - s . rfind ( "\n" , 0 , loc )