(x)
return T.maximum(0.1*x,x)
hard-coded leaky relu
hard-coded leaky relu
hard - coded leaky relu
def leaky_relu_01(x):
    """ hard-coded leaky relu """
    return T.maximum(0.1*x,x)
def leaky_relu_01 ( x ) : return T . maximum ( 0.1 * x , x )