(pattern)
return "".join(parts)
Convert a pattern containing <type:name> syntax to a regex.
    Based on similar code in Django. This is trivially cacheable
    as the same input pattern will always return the same regex.
Convert a pattern containing <type:name> syntax to a regex.
    Based on similar code in Django. This is trivially cacheable
    as the same input pattern will always return the same regex.
Convert a pattern containing <type : name > syntax to a regex . Based on similar code in Django . This is trivially cacheable as the same input pattern will always return the same regex .
def pattern_to_regex(pattern):
    """
    Convert a pattern containing <type:name> syntax to a regex.
    Based on similar code in Django. This is trivially cacheable
    as the same input pattern will always return the same regex.
    """
    parts = ["^"]
    while True:
        match = PATTERN_COMPONENT_RE.search(pattern)
        if not match:
            parts.append(re.escape(pattern))
            break
        parts.append(re.escape(pattern[: match.start()]))
        pattern = pattern[match.end() :]
        param_type, param_name = match.group("param_type", "param_name")
        param_regex = PATTERN_PARAM_TYPES[param_type]
        parts.append(f"(?P<{param_name}>{param_regex})")
    parts.append("$")
    return "".join(parts)
def pattern_to_regex ( pattern ) : parts = [ "^" ] while True : match = PATTERN_COMPONENT_RE . search ( pattern ) if not match : parts . append ( re . escape ( pattern ) ) break parts . append ( re . escape ( pattern [ : match . start ( ) ] ) ) pattern = pattern [ match . end ( ) : ] param_type , param_name = match . group ( "param_type" , "param_name" ) param_regex = PATTERN_PARAM_TYPES [ param_type ] parts . append ( f"(?P<{param_name}>{param_regex})" ) parts . append ( "$" ) return "" . join ( parts )