(eq, limit=1)
Solves the equation `x_{1}^2 + x_{2}^2 + . . . + x_{n}^2 - k = 0`.

    Returns at most ``limit`` number of solutions. Currently there is no way to
    set ``limit`` using higher level API's like ``diophantine()`` or
    ``diop_solve()`` but that will be fixed soon.

    Usage
    =====

    ``general_sum_of_squares(eq, limit)`` : Here ``eq`` is an expression which
    is assumed to be zero. Also, ``eq`` should be in the form,
    `x_{1}^2 + x_{2}^2 + . . . + x_{n}^2 - k = 0`. At most ``limit`` number of
    solutions are returned.

    Details
    =======

    When `n = 3` if `k = 4^a(8m + 7)` for some `a, m \in Z` then there will be
    no solutions. Refer [1]_ for more details.

    Examples
    ========

    >>> from sympy.solvers.diophantine import diop_general_sum_of_squares
    >>> from sympy.abc import a, b, c, d, e, f
    >>> diop_general_sum_of_squares(a**2 + b**2 + c**2 + d**2 + e**2 - 2345)
    set([(0, 48, 5, 4, 0)])

    Reference
    =========

    .. [1] Representing an Integer as a sum of three squares, [online],
        Available:
        http://www.proofwiki.org/wiki/Integer_as_Sum_of_Three_Squares
Solves the equation `x_{1}^2 + x_{2}^2 + . . . + x_{n}^2 - k = 0`.
Solves the equation x_ { 1 } ^2 + x_ { 2 } ^2 + . . . + x_ { n } ^2 - k = 0 .
def diop_general_sum_of_squares(eq, limit=1):
    """
    Solves the equation `x_{1}^2 + x_{2}^2 + . . . + x_{n}^2 - k = 0`.

    Returns at most ``limit`` number of solutions. Currently there is no way to
    set ``limit`` using higher level API's like ``diophantine()`` or
    ``diop_solve()`` but that will be fixed soon.

    Usage
    =====

    ``general_sum_of_squares(eq, limit)`` : Here ``eq`` is an expression which
    is assumed to be zero. Also, ``eq`` should be in the form,
    `x_{1}^2 + x_{2}^2 + . . . + x_{n}^2 - k = 0`. At most ``limit`` number of
    solutions are returned.

    Details
    =======

    When `n = 3` if `k = 4^a(8m + 7)` for some `a, m \in Z` then there will be
    no solutions. Refer [1]_ for more details.

    Examples
    ========

    >>> from sympy.solvers.diophantine import diop_general_sum_of_squares
    >>> from sympy.abc import a, b, c, d, e, f
    >>> diop_general_sum_of_squares(a**2 + b**2 + c**2 + d**2 + e**2 - 2345)
    set([(0, 48, 5, 4, 0)])

    Reference
    =========

    .. [1] Representing an Integer as a sum of three squares, [online],
        Available:
        http://www.proofwiki.org/wiki/Integer_as_Sum_of_Three_Squares
    """
    var, coeff, diop_type = classify_diop(eq)

    if diop_type == "general_sum_of_squares":
        return _diop_general_sum_of_squares(var, coeff, limit)
def diop_general_sum_of_squares ( eq , limit = 1 ) : var , coeff , diop_type = classify_diop ( eq ) if diop_type == "general_sum_of_squares" : return _diop_general_sum_of_squares ( var , coeff , limit )