(x)
return T.maximum(0.3*x,x)
hard-coded leaky relu
hard-coded leaky relu
hard - coded leaky relu
def leaky_relu_03(x):
    """ hard-coded leaky relu """
    return T.maximum(0.3*x,x)
def leaky_relu_03 ( x ) : return T . maximum ( 0.3 * x , x )