Calculate iron deficit for a 50 kg person, with Hb-5g/dL. Add 1000 mg for stores.
Ans. (a) 2150 mg(Ref: Wintrobes 12ed/814)Treatment of anemia due to iron deficiency.The total dose is calculated from the amount of iron needed to restore the hemoglobin deficit plus an additional amount to replenish stores.Total iron deficit = body weight x (target Hb (15)-actual Hb) x2.4+ Iron for iron stores (depot iron) In this question: 50x(15-5)x2.4+1000=2200mg Nearest correct option is A i.e 2150 mg
2150 mg
1650 mg
1150 mg
1575 mg
Misc. (R.B.C)