A transpoer has a km for glucose of 45mM and a Vmas of 36 micromoles glucose sec/mg of transpoer. If the glucose concentration in peripheral blood is 15 mM, what will the rate of glucose transpo (in micromoles glucose/sec/mg transpoer) be?
Concentration of substrate is increased, the forward reaction K1 is increased, and so K3 as well as total velocity is correspondingly enhanced. The three different constants may be made into one equation, Km = K2 + K3 K1 Km is called as Michaelis Constant. It is fuher shown that Velocity (v) = Vmax Km + When concentration of substrate is made equal to Km, i.e. When = Km Velocity (v) = Vmax = Vmax = Vmax + 2 2 or v = 1/2 VmaxRef: DM Vasudevan, page no: 48
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Enzymes