How many base pairs are encoded by a prokaryotic polypeptide of 250 amino acids?
A prokaryotic DNA does not contain any introns and the base sequence is exactly collinear with the amino acid sequence of proteins. Each amino acid is represented by a 3 base codon, therefore 250 amino acid protein will require 750 base pairs (250 x 3 = 750).
250 bp
500 bp
750 bp
1000 bp
Translation