hat
Angle ∠ B = β = 53.13301023542° = 53°7'48″ = 0.9277295218 rad
fra
T=chc2 c=2 Thc=2⋅ 18150132=275T = \dfrac{ c h_c }{ 2 } \ \\ \ \\ c = \dfrac{ 2 \ T }{ h_c } = \dfrac{ 2 \cdot \ 18150 }{ 132 } = 275T=2chc​​ c=hc​2 T​=1322⋅ 18150​=275