def remove_urls(text, remove=set(' )({}[];:')):
    """
    Removes (without returning) all urls present in a text
    :param text: text to clean urls from
    :param remove: break characters for url
    :return: text clean of urls
    """
    ind = text.find('http')
    while ind > -1:
        length = len(text)
        for i in range(ind + 7, length):
            if text[i] in remove:
                break
        else:
            i = length - 1
        text = text[:ind] + text[i:]
        ind = text.find('http')
    return text
