def bbox_contains(one, two):
    """
    Returns ``True`` if `one` contains `two`.

    >>> bbox_contains([0, 0, 10, 10], [2, 2, 4, 4])
    True
    >>> bbox_contains([0, 0, 10, 10], [0, 0, 11, 10])
    False

    Allow tiny rounding errors:

    >>> bbox_contains([0, 0, 10, 10], [0.000001, 0.0000001, 10.000001, 10.000001])
    False
    >>> bbox_contains([0, 0, 10, 10], [0.0000000000001, 0.0000000000001, 10.0000000000001, 10.0000000000001])
    True
    """
    a_x0, a_y0, a_x1, a_y1 = one
    b_x0, b_y0, b_x1, b_y1 = two
    x_delta = abs(a_x1 - a_x0) / 10000000000000.0
    y_delta = abs(a_y1 - a_y0) / 10000000000000.0
    if (a_x0 <= b_x0 + x_delta and a_x1 >= b_x1 - x_delta and a_y0 <= b_y0 +
        y_delta and a_y1 >= b_y1 - y_delta):
        return True
    return False
