def consistent(dic1, dic2):
    """
    Check if two dictionaries with default are consistent:

    >>> consistent({'PGA': 0.05, 'SA(0.3)': 0.05}, {'default': 0.05})
    True
    >>> consistent({'SA(0.3)': 0.1, 'SA(0.6)': 0.05},
    ... {'default': 0.1, 'SA(0.3)': 0.1, 'SA(0.6)': 0.05})
    True
    """
    if dic1 == dic2:
        return True
    v1 = set(dic1.values())
    v2 = set(dic2.values())
    missing = set(dic2) - set(dic1) - {'default'}
    if len(v1) == 1 and len(v2) == 1 and v1 == v2:
        return True
    return not missing
