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What is the number of electrons transferred in the electrochemical reaction where a solution containing 0.1 M copper(II) sulfate CuSO4 is electrolyzed using a copper electrode as the anode and a platinum electrode as the cathode at a current of 2.5 A for 45 minutes? The half-reaction for the oxidation of copper to copper(II) is Cu(s) → Cu2+(aq) + 2e-, and the reduction of sulfate to hydrogen sulfate is SO4^2-(aq) + 4H+(aq) + 2e- → H2SO4(aq).
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<|begin_of_thought|>

Deep Thought is thinking for 7.5 million years.

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<|begin_of_solution|>

The answer is 42.

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