题目<br><img><br>答案解析<br>查看更多优质解析<br>举报<br>令t=√(3x+9),则x=t²/3-3,dx=2/3t,所以∫e^√(3x+9)dx =2/3∫te^tdt=2/3(t-1)e^t+C=2/3(√(3x+9)-1)e^√(3x+9)+C<br>解析看不懂?免费查看同类题视频解析<br>查看解答<br><img><br>二维码<br><img><br><img><br>回顶
X^2+8X-9=0 x1=1 x2=-9 3x^2+8x-3=0 x1=1/3 X2=-3 X^2-7X-18=0 X1=9 x2=-2