E half-cell = E o − 0.05918   V ν e log 10 ⁡ {\displaystyle E_{\text{half-cell}}=E^{o}-{\frac {0.05918\ {\text{V}}}{\nu _{e}}}\log _{10}\left} These calculations are based on the assumption that all chemical reactions are in equilibrium.
E half-cell = E 0 − 0.05918 V n log 10 ⁡ {\displaystyle E_{\text{half-cell}}=E^{0}-{\frac {0.05918V}{n}}\log _{10}} Αυτοί οι υπολογισμοί βασίζονται στην υπόθεση ότι όλες οι χημικές αντιδράσεις είναι σε ισορροπία.