Recommend the best approach to optimize the following code to increase its efficiency.
Input: int count = 0;

for(int i = 0; i < array.length; i++){
  if(array[i] == 0){
    count++;
  }
}
The best approach to optimize the given code is to replace the 'if' condition with a 'switch' condition. The switch can then be used to quickly determine which value is considered 'zero', by matching it to a particular case. This would reduce the number of comparisons required, thus increasing the efficiency of the code.
The best approach to optimize the given code is to use a counting technique instead of a loop. Instead of using a loop, use a formula that counts the number of elements that are equal to 0 in the array. This can be done with the following formula: count = array.length / (array.length - 1) * (array.length - 1) + 1, which is equivalent to the loop, but will be more efficient as it does not require the constant time complexity of a loop.