Thats a unique idea.You should consider the following idea to enhance your idea so that it would impact uniquely: Non-sentential utterances (e.g., short-ansrs as in "Who came to the party?"--- "Peter.") are pervasive in dialogue. As with other forms of ellipsis, the elided material is typically present in the context (e.g., the question that a short ansr ansrs).  present a machine learning approach to the novel task of identifying fragments and their antecedents in multiparty dialogue.  compare the performance of several learning algorithms, using a mixture of structural and lexical features, and show that the task of identifying antecedents given a fragment can be learnt successfully (f(0.5) = .76);  discuss why the task of identifying fragments is harder (f(0.5) = .41) and finally report on a combined task (f(0.5) = .38).
['David Schlangen']
I am writing a research paper on a idea Towards Finding and Fixing Fragments---Using ML to Identify Non-Sentential Utterances and their Antecedents in Multi-Party Dialogue
[{"from": "human", "value": "I am writing a research paper on a idea Towards Finding and Fixing Fragments---Using ML to Identify Non-Sentential Utterances and their Antecedents in Multi-Party Dialogue"}, {"from": "gpt", "value": "Thats a unique idea.You should consider the following idea to enhance your idea so that it would impact uniquely: Non-sentential utterances (e.g., short-ansrs as in \"Who came to the party?\"--- \"Peter.\") are pervasive in dialogue. As with other forms of ellipsis, the elided material is typically present in the context (e.g., the question that a short ansr ansrs).  present a machine learning approach to the novel task of identifying fragments and their antecedents in multiparty dialogue.  compare the performance of several learning algorithms, using a mixture of structural and lexical features, and show that the task of identifying antecedents given a fragment can be learnt successfully (f(0.5) = .76);  discuss why the task of identifying fragments is harder (f(0.5) = .41) and finally report on a combined task (f(0.5) = .38)."}]