Lemma functor_on_comp {B C:category} (F:[B,C]) {b b' b'':B} (g:b'-->b'') (f:b-->b') : F ▭ (g ∘ f) = F ▭ g ∘ F ▭ f. Proof. exact (functor_comp F f g). Defined.
Require Import UniMath.MoreFoundations.Tactics.