Proposition eq_profunctor_square {C₁ C₂ D₁ D₂ : category} {F : C₁ ⟶ C₂} {G : D₁ ⟶ D₂} {P : D₁ ↛ C₁} {Q : D₂ ↛ C₂} {τ τ' : profunctor_square F G P Q} (p : ∏ (y : C₁) (x : D₁) (h : P y x), τ y x h = τ' y x h) : τ = τ'. Proof. use eq_profunctor_nat_trans. exact p. Qed.
Require Import UniMath.Foundations.All. Require Import UniMath.MoreFoundations.All. Require Import UniMath.CategoryTheory.Core.Prelude. Require Import UniMath.CategoryTheory.Categories.HSET.All. Require Import UniMath.CategoryTheory.Categories.HSET.SetCoends. Require Import UniMath.CategoryTheory.Profunctors.Core. Require Import UniMath.CategoryTheory.Profunctors.Examples. Require Import UniMath.CategoryTheory.Profunctors.Transformation.