<caption><image_0>The image is a screenshot of a computer screen with a white background. On the right side of the screen, there is a triangle with a right angle and a left angle. The triangle is drawn in a simple, minimalist style with a thin line connecting the two sides of the triangle. The right angle is slightly tilted to the left, while the left angle is straight. At the top of the image, there are two buttons, one labeled "Constrência" and the other labeled "Código" which translates to "How to calculate the angle of a triangle".</caption><transcript><audio_1> inscrito no triângulo. Então, pretende-se um círculo que esteja dentro deste triângulo e cada um dos lados do triângulo seja tangente ao círculo. Provavelmente, a forma mais fácil de pensar nisto é imaginar</transcript><transcript><audio_2> Agora, o que é o incentro de um triângulo? O incentro de um triângulo é o ponto onde se cruzam as bissetrizes dos seus ângulos. Então, se eu tivesse uma linha que dividisse</transcript><transcript><audio_3> Estou a fazer a olho aqui. Isto seria a bissetriz do ângulo. Mas para ser um pouco mais rigoroso, com as bissetrizes dos ângulos, posso usar um compasso. Deixem-me só fazer isto um pouco mais pequeno e vou colocar o</transcript> constructs a circle inscribed in the triangle between a supposed circle that is inside this triangle and each of the sides of the triangle is attached to the circle, probably the easiest way to think about this is to imagine that the center of the circle will be in a center of the triangle Now what is the center of a triangle, Hadrian's center is the point where the bisectors of its angles intersect, so if I had a line that should be in two guarás, I'm doing my eye here, this would be the bisector of the angle, but for  to be a little more strict with the angle guidelines I can use a compass, let's just make this a little smaller and I'm going to place
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