<transcript><audio_115> l'exemple précédent de vote alternatif, on éliminait d'abord l'option E placée 0 fois en première position, puis les options C et D placées une seule fois chacune en première position, et au troisième tour, l'option A l'emportait. Maintenant,</transcript><transcript><audio_116> on doit éliminer celle qui est le plus de fois en dernière position. Quand la personne qui a voté a classé les 5 options, c'est donc l'option en 5ème position qu'on comptabilise. Mais quand la personne ne les a pas toutes classées, les plus mal classées, en fait, c'est celles que la personne a carrément</transcript><caption><image_117>The image is a screenshot of a table with the title "Méthode de Coombs : Four 1" written in French. The table is divided into four columns, each with a different option. The first column is labeled "Option A", the second column is numbered "Option B", and the third column is titled "Option C". 

The table is set against a black background with a city skyline in the background. The options are arranged in a grid-like pattern, with each option having a different color and size. The colors range from light blue to dark blue, with some being yellow, green, and red. The text is written in white and is in a modern sans-serif font.

At the bottom of the table, there is a note that reads "Nombre de demilitaires positions" which translates to "Position positions" in English.</caption> if we take the previous example of alternative voting have first eliminated the  'option up the c-zero times in first position then the options c are moved only once each in first position and in the third round the option to win now with the kums method we must eliminate those which is the most  time in last position when the person who voted to rank the five options are therefore the option in fifth position that we count but when the person has not classified them all, the worst classified in fact is the one that the person has
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