<transcript><audio_10> Il va donc falloir déterminer la primitive ici.</transcript><transcript><audio_11> Attention ici, la variable de laquelle dépend T est X, qui est l'abscisse.</transcript><transcript><audio_12> je vais utiliser les conditions limite en x égale 0, je vais placer mon origine au niveau de la surface gauche de ma paroi j'ai donc t de 0 qui est</transcript><transcript><audio_13> à k quand je remplace là-dedans x égale 0 fait que ce terme est nul et donc k est égal à t1 si maintenant je me place de l'autre côté donc côté droit c'est à dire pour x égale e j'ai t1 qui vaut t2 je suis en</transcript><transcript><audio_14> l'autre côté qui a une température T2 et donc en remplaçant T1 sera égal à moins phi sur lambda S E plus T1 et j'en déduis donc à partir de cette relation ici T1 qui est égal à T2, on va donc avoir</transcript><transcript><audio_15> égal à moins phi sur lambda s donc ma variation de température entre les deux faces entraîne un flux thermique ici et on a</transcript> t of X I want to know t of fi on lambda s x + k attention here my function the variable on which T and so determine k I will therefore use the boundary conditions at x = 0 so I will place my origin at the level of the left surface of my wall I therefore have T0 which is equal to T1 therefore T0 is equal to 4 when I  replace in there x = 0 makes this terminus and therefore KL is equal to T1 if now I place myself on the other side so right side that is to say for X = e I have you which is worth T2 I am in contact with  the other side which has a temperature T2 and therefore by replacing te will be equal to minus fi on lambda s e plus T1 and I therefore deduce from this relation here te which is equal to T2 we will therefore have T2 - T1 which  is equal to minus fi on lambda s e therefore my temperature variation between the two faces results in a thermal flow here and we have a term which
{"source": "grass-yt-cc-by.1DWkhNZhmMc|shard_10039_47|create_multimodal_data.extract_yt_and_generate_transcripts.35|shard_10039|create_multimodal_data.generate_captions.53|shard_10039|create_multimodal_data.generate_captions.44", "params": {"id": "1DWkhNZhmMc", "channel_id": "UC6fHhtnMla1f2siETlOkYkQ", "duration": 446, "view_count": 79, "age_limit": 0, "chapters": [{"start_time": 0.0, "title": "Introduction", "end_time": 66.0}, {"start_time": 66.0, "title": "Loi de Fourier", "end_time": 137.0}, {"start_time": 137.0, "title": "R\u00e9solution de l'\u00e9quation", "end_time": 236.0}, {"start_time": 236.0, "title": "Comparaison", "end_time": 298.0}, {"start_time": 298.0, "title": "R\u00e9sistance thermique d'un mat\u00e9riau", "end_time": 352.0}, {"start_time": 352.0, "title": "Flux thermique dans une cloison", "end_time": 391.0}, {"start_time": 391.0, "title": "R\u00e9sistance thermique d'une cloison", "end_time": 446}], "like_count": 1, "channel_follower_count": 1790, "license": "Creative Commons Attribution license (reuse allowed)", "uploader_id": "@phydescachim", "yt_tar_file": "/leonardo_work/EUHPC_E03_068/audio/fixed_download/grass-yt-cc-by//shard_10039/1DWkhNZhmMc.tar.gz"}}