<transcript><audio_8>except instead of being 12 volts it's eight volts right the thevenin amplitude but the timing is identical now with a 1000 ohm resistor and a 1 microfarad capacitor the time constant would be 1k times 1 micro or 1 millisecond</transcript><transcript><audio_9>so steady state is reached in 5 time constants or 5 milliseconds that's why i chose a 10 millisecond pulse for the source voltage here so we'll actually be able to see the capacitor</transcript><transcript><audio_10>voltage in other words v load 2 rise up in this case it should rise up to 8 volts and it should take around 5 milliseconds to do that and then when this sort source goes back to zero volts that's essentially like shorting this to ground</transcript><transcript><audio_11>now the cap will act as a source like a battery and it will discharge through our thevenin producing an inverted polarity and it's going to be plus on this side minus on that side so that's going to flip but that's going to go from</transcript><transcript><audio_12>eight volts and then work its way back towards zero right negative eight back towards zero again five milliseconds because we haven't changed the roc value any what should happen is that v load 2 and v load should be identical that's the whole point of thevenin's</transcript><transcript><audio_13>theorem so let's see what we get here right we'll just do a transient analysis on this so i'm going to run this from 0 to 20 milliseconds so we'll see that full</transcript><caption><image_14>The image is a screenshot of a computer screen with a circuit diagram in the center. The circuit diagram is a simple DC to DC converter with two resistors, one on the left side and one in the middle. The resistors are connected by green lines and are labeled with their respective values.

On the top left corner of the screen, there is a menu bar with various options such as "File", "Edit", "View", "Tools", and "Help". On the top right corner, there are several buttons and menus. The background of the image is white, and the circuit diagram appears to be in a software interface.</caption> except instead of being 12 volts it's eight volts right the thevenin amplitude but the timing is identical now with a 1000 ohm resistor and a 1 microfarad capacitor the time constant would be 1k times 1 micro or 1 millisecond so steady state is reached in 5 time constants or 5 milliseconds that's why i chose a 10 millisecond pulse for the source voltage here so we'll actually be able to see the capacitor voltage in other words v load 2 rise up in this case it should rise up to 8 volts and it should take around 5 milliseconds to do that and then when this sort source goes back to zero volts that's essentially like shorting this to ground now the cap will act as a source like a battery and it will discharge through our thevenin producing an inverted polarity and it's going to be plus on this side minus on that side so that's going to flip but that's going to go from eight volts and then work its way back towards zero right negative eight back towards zero again five milliseconds because we haven't changed the roc value any what should happen is that v load 2 and v load should be identical that's the whole point of thevenin's theorem so let's see what we get here right we'll just do a transient analysis on this so i'm going to run this from 0 to 20 milliseconds so we'll see that full
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