<transcript><audio_102>off we can swing from Q over to saturation which is the smaller swing so looking at this we can just say okay the smaller of these two sets the compliance</transcript><transcript><audio_103>alright it sets the peak output swing okay so you can use that as a general operative wherever the cue point is look</transcript><transcript><audio_104>at this equation figure out which one is smaller that's the peak value you could then use your RMS fudge factor if you will the RMS is approximately equal to</transcript><transcript><audio_105>the peak times 0.707 remember that's 1 over the square root of 2 times point zero 707 and you can use that value then to calculate your power all right</transcript><transcript><audio_106>ok so that would be the precise value if you had something like a follower if you had a heavily swamped amplifier common emitter amplifier there will be a small voltage divider effect between the swapping resistor re and RC so properly</transcript><transcript><audio_107>speaking you really should compensate for that do a little voltage divider and then use that slightly smaller voltage as your peak value and then you can compute your RMS value off of that the other thing that we won't want to</transcript><caption><image_108>The image is a whiteboard with various mathematical equations and diagrams written on it. The equations are written in black marker and are arranged in a grid-like pattern. 

On the left side of the whiteboard, there is a diagram of a circuit with various components such as resistors, capacitors, and transistors. On the right side, there are two graphs, one labeled "AC Loadline" and the other labeled "Clipping". The graph on the left shows the current and voltage levels of the circuit, while the graph in the middle shows the voltage levels.

In the center of the diagram, there appears to be a diagram that shows the flow of data between the components. The graph shows that the current is higher than the voltage level, and the voltage is lower than the current level. The diagram also shows a line graph that shows a downward trend, indicating a decrease in the voltage. The text on the white board is written in blue marker and is not visible in the image.</caption><transcript><audio_109>remember is that when we calculate load power the key here is to use the load resistor not the AC equivalent value because the AC equivalent value include foods the biasing resistor so for</transcript> off we can swing from Q over to saturation which is the smaller swing so looking at this we can just say okay the smaller of these two sets the compliance alright it sets the peak output swing okay so you can use that as a general operative wherever the cue point is look at this equation figure out which one is smaller that's the peak value you could then use your RMS fudge factor if you will the RMS is approximately equal to the peak times 0.707 remember that's 1 over the square root of 2 times point zero 707 and you can use that value then to calculate your power all right ok so that would be the precise value if you had something like a follower if you had a heavily swamped amplifier common emitter amplifier there will be a small voltage divider effect between the swapping resistor re and RC so properly speaking you really should compensate for that do a little voltage divider and then use that slightly smaller voltage as your peak value and then you can compute your RMS value off of that the other thing that we won't want to remember is that when we calculate load power the key here is to use the load resistor not the AC equivalent value because the AC equivalent value include foods the biasing resistor so for
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