<transcript><audio_59>similarly this one would be m starting from n minus 1 i will have certain number of um multipliers and the last one would be n minus i because starting from the next one n</transcript><transcript><audio_60>minus y i minus 1 it will be reduced with denominator so it would be n minus 1 uh n minus 2 etc and minus i that would be my last</transcript><transcript><audio_61>member divided by n minus one uh i did have factor no that's wrong</transcript> similarly this one would be m starting from n minus 1 i will have certain number of um multipliers and the last one would be n minus i because starting from the next one n minus y i minus 1 it will be reduced with denominator so it would be n minus 1 uh n minus 2 etc and minus i that would be my last member divided by n minus one uh i did have factor no that's wrong
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