<transcript><audio_10> Então, se eu pegar uma abertura do compasso maior do que a distância de P até a reta R, I,</transcript><caption><image_11>The image shows a man writing on a green chalkboard. He is wearing a blue t-shirt and is holding a wooden stick in his right hand. The chalkboard is green and has white text written on it. The text appears to be a mathematical equation or a mathematical problem. The man is writing on the chalkboard with a marker and is focused on his work. There is a small wooden frame on the right side of the image.</caption><transcript><audio_12> traçar um pedaço de circunferência aqui, deixa eu pegar uma abertura um pouco maior, se eu fizer isso, se eu fizer isso,</transcript><transcript><audio_13> A distância de P até esses dois pontos aqui, a distância de P até esses dois pontos é a mesma. Em outras palavras,</transcript><caption><image_14>The image shows a man standing in front of a green chalkboard. He is wearing a blue t-shirt and glasses and appears to be writing on the chalkboard with a white chalk. The chalkboard has some text written in white chalk and there is a small wooden frame on the right side of the image. The text on the blackboard is in Spanish and it appears that the man is in the middle of a lesson or presentation.</caption><caption><image_15>The image shows a man standing in front of a green chalkboard. He is wearing a blue t-shirt and glasses and appears to be giving a presentation. On the chalkboard, there is a diagram of a curved line with a point at the end and a line at the bottom. The man is pointing to the right side of the image with his right hand and is gesturing with his left hand. Above the diagram, there are words written in white chalk that appear to be related to mathematical equations. The words on the greenboard are written in Spanish.</caption><transcript><audio_16> a mediatriz desse segmento. Mas, traçar a mediatriz do segmento AB é um procedimento já conhecido. Como eu já tenho um ponto por onde essa mediatriz passa, bastaria eu fazer...</transcript><caption><image_17>The image shows a man standing in front of a green chalkboard. He is wearing a blue t-shirt and glasses and is holding a wooden stick in his right hand. On the chalkboard, there is a white chalk drawing of a line with a point at the end. The line appears to be drawn in a simple, cartoon-like style. The text on the blackboard is written in white chalk and is in Spanish. The background of the image is blurred, but it seems like the man is in a classroom or a classroom setting.</caption><transcript><audio_18> maior do que a metade do segmento AB. Para cá. Isso aqui é traçar a mediatriz.</transcript><transcript><audio_19> para cá. Agora, a reta que eu estou procurando é a reta que passa por esses dois pontos aqui.</transcript><caption><image_20>The image shows a man standing in front of a green chalkboard with a mathematical equation written on it. The equation is written in white chalk and appears to be a trigonometric equation. The man is wearing a blue shirt and glasses and is pointing to the right side of the chalkboard. He is holding a wooden stick in his right hand and is looking at the equation with a focused expression. The background of the image is blurred, but it seems like the man is in a classroom or a classroom setting.</caption><transcript><audio_21> reta que passa por P e Q é a mediatriz de um segmento que está contido na reta R, essa reta P e Q é perpendicular à reta R, com</transcript> perpendicular to a segment so if I take an opening on the compass greater than the distance from p to the straight line r and with the dry tip of the compass at P draw a piece of circumference here let this  If I do this, what I have is that the distance from p here, the distance from p to these two points is the same, in other words I want to say that point P belongs to the perpendicular bisector of this segment but drawing the bisector of the  Segment AB is a well-known procedure, and as I already have a point where this perpendicular bisector passes, I would only have to make an opening here that is larger than half that of AB to this point, this is to trace the bisector that we saw.  in the last class, here's the line I'm looking for now. line that passes through p and q is the bisector of a segment that is contained in the line and R this line Because it is perpendicular to the line r as we
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