<caption><image_29>The image shows a man standing in front of a green chalkboard and writing on it. He is wearing a black t-shirt and appears to be a teacher or a student. The chalkboard is filled with mathematical equations and formulas written in white chalk. The man is pointing to one of the equations with his right hand, as if he is explaining them. The equations are written in Spanish and appear to be related to mathematics. The background of the image is a classroom or classroom setting.</caption><transcript><audio_30> Mas pelo pequeno teorema de Fermat, 2 elevado a 6 módulo 7 é 1. Então tudo isso aqui vira 1 módulo.</transcript><transcript><audio_31> a 8, que é 2 elevado a 3. Só que como eu estou no módulo 7, o 8, por sua vez, é congruente a 1. Então a classe de equivalência...</transcript><transcript><audio_32> 2 elevado a 327 módulo 7 é 1 na sequência a gente vai calcular a classe de equivalência de 2 elevado a 327 módulo 11 perceba que mais uma vez o fato</transcript><transcript><audio_33> me permite usar o pequeno teorema de Fermat. Então, nós vamos dividir 327 por P menos 1, que nesse caso é 10, e faz a conta ficar bem fácil. Aqui vai dar 32 e o resto 7. Isso...</transcript><transcript><audio_34> número como 2 elevado a 10, que por sua vez está elevado a 32, vezes 2 elevado a 7. Pelo pequeno teorema de Fermat, 2 elevado a 10 é congruente</transcript> 54 ve 2 elev 3 But by the small theorem of establishing 2 elev 6 module 7 is 1 So all of this here becomes 1 and the expression is congruent to 8 which is 2 raised to 3 but as I am  module 7, 8 in turn is congruent to 1, so the equivalence class of our number 2 to the power 327 module 7 is 1, in the sequence we will calculate the equivalence class of 2 to the power of 3 X 27 module 11, notice that once again the  The fact that this number is prime allows me to use the little firming theorem. So we are going to divide 327 by P - 1 which in this case is 10 and makes the math very easy, here it will be 32 and the remainder 7, this allows us to write this number as 2  to the power of 10 which in turn is to the power of 32 x 2 to the power of 7 by Fermar's little theorem 2 to the power of 10 is
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