text: Once again , and  are all positive. The sign of the cubic term can always be chosen to be negative as we have done by reversing the sign of  if necessary.
  We analyze this free energy functional as follows: (i) For , we have a local maximum at , and since the free energy is bounded below, there must be two local minima at nonzero values  and . The cubic term ensures that  is the global minimum since it is deeper. (ii) For  just above , the minimum at  disappears, the maximum at  turns into a local minimum, but the minimum at  persists and continues to be the global minimum. As the temperature is further raised,  rises until it equals zero at some temperature . At  we get a discontinuous jump in the global minimum from  to 0. (The minima cannot coalesce for that would require the first three derivatives of  to vanish at .)
  To find , we demand that free energy be zero at  (just like the  solution), and furthermore that this point should be a local minimum. These two conditions yield two equations,
  which are satisfied when . The same equations also imply that . That is,
  As in the symmetric case the order parameter suffers a discontinuous jump from  to 0. Second, the transition temperature  is not the same as the temperature  where  vanishes.