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data/clustering_battle-f62bcad9-19c4-430b-a7ba-aa2bfeba99dc.jsonl

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 {"tstamp": 1722419237.1568, "task_type": "clustering", "type": "bothbadvote", "models": ["", ""], "ip": "", "0_conv_id": "1e7547b40a7247f798f92e91dba29f04", "0_model_name": "embed-english-v3.0", "0_prompt": ["LHR", "BER", "DUB", "SYD", "JFK", "LTN", "FRA", "SFO", "LTN", "SIN", "IST", "DBX"], "0_ncluster": 1, "0_output": "", "0_ndim": "3D (press for 2D)", "0_dim_method": "PCA", "0_clustering_method": "KMeans", "1_conv_id": "053450d09e7d47c1ba1a39e226cdfbc4", "1_model_name": "Alibaba-NLP/gte-Qwen2-7B-instruct", "1_prompt": ["LHR", "BER", "DUB", "SYD", "JFK", "LTN", "FRA", "SFO", "LTN", "SIN", "IST", "DBX"], "1_ncluster": 1, "1_output": "", "1_ndim": "3D (press for 2D)", "1_dim_method": "PCA", "1_clustering_method": "KMeans"}
+{"tstamp": 1722419487.8862, "task_type": "clustering", "type": "bothbadvote", "models": ["", ""], "ip": "", "0_conv_id": "346e5cbb1f934cf6911d6ce7bfa3d236", "0_model_name": "mixedbread-ai/mxbai-embed-large-v1", "0_prompt": ["LHR", "BER", "DUB", "SYD", "JFK", "LTN", "FRA", "SFO", "LTN", "SIN", "IST", "DBX"], "0_ncluster": 3, "0_output": "", "0_ndim": "3D (press for 2D)", "0_dim_method": "PCA", "0_clustering_method": "KMeans", "1_conv_id": "ba8218c6c5ce4b98ae2e8e4e97573696", "1_model_name": "intfloat/e5-mistral-7b-instruct", "1_prompt": ["LHR", "BER", "DUB", "SYD", "JFK", "LTN", "FRA", "SFO", "LTN", "SIN", "IST", "DBX"], "1_ncluster": 3, "1_output": "", "1_ndim": "3D (press for 2D)", "1_dim_method": "PCA", "1_clustering_method": "KMeans"}

data/retrieval_individual-f62bcad9-19c4-430b-a7ba-aa2bfeba99dc.jsonl

@@ -133,3 +133,5 @@
 {"tstamp": 1722417994.5447, "task_type": "retrieval", "type": "chat", "model": "intfloat/multilingual-e5-large-instruct", "gen_params": {}, "start": 1722417992.3387, "finish": 1722417994.5447, "ip": "", "conv_id": "f3bcc1930bfe4f1489adccdc43648247", "model_name": "intfloat/multilingual-e5-large-instruct", "prompt": "Which test was devised to determine whether robots can think?", "output": [["Which test was devised to determine whether robots can think?", "Turing test\n\nThe test was introduced by Turing in his 1950 paper \"Computing Machinery and Intelligence\" while working at the University of Manchester. It opens with the words: \"I propose to consider the question, 'Can machines think? Because \"thinking\" is difficult to define, Turing chooses to \"replace the question by another, which is closely related to it and is expressed in relatively unambiguous words.\" Turing describes the new form of the problem in terms of a three-person game called the \"imitation game\", in which an interrogator asks questions of a man and a woman in another room in order to determine the correct sex of the two players. Turing's new question is: \"Are there imaginable digital computers which would do well in the imitation game?\" This question, Turing believed, was one that could actually be answered. In the remainder of the paper, he argued against all the major objections to the proposition that \"machines can think\".\nSince Turing introduced his test, it has been both highly influential and widely criticized, and has become an important concept in the philosophy of artificial intelligence. Philosopher John Searle would comment on the Turing test in his Chinese room argument, a thought experiment that stipulates that a machine cannot have a \"mind\", \"understanding\", or \"consciousness\", regardless of how intelligently or human-like the program may make the computer behave. Searle criticizes Turing's test and claims it is insufficient to detect the presence of consciousness.\nHistory"]], "corpus": "wikipedia"}
 {"tstamp": 1722418019.3162, "task_type": "retrieval", "type": "chat", "model": "jinaai/jina-embeddings-v2-base-en", "gen_params": {}, "start": 1722418019.1398, "finish": 1722418019.3162, "ip": "", "conv_id": "16e0d02092a74e6e9b9e2324ec643d8d", "model_name": "jinaai/jina-embeddings-v2-base-en", "prompt": "Find me a planet near α 23h 06m 29.368s and δ −05° 02′ 29.04″ that could be habitable.", "output": [["Find me a planet near α 23h 06m 29.368s and δ −05° 02′ 29.04″ that could be habitable.", "Planetary habitability\n\nPlanetary habitability is the measure of a planet's or a natural satellite's potential to develop and maintain environments hospitable to life. Life may be generated directly on a planet or satellite endogenously or be transferred to it from another body, through a hypothetical process known as panspermia. Environments do not need to contain life to be considered habitable nor are accepted habitable zones (HZ) the only areas in which life might arise."]], "corpus": "wikipedia"}
 {"tstamp": 1722418019.3162, "task_type": "retrieval", "type": "chat", "model": "BAAI/bge-large-en-v1.5", "gen_params": {}, "start": 1722418019.1398, "finish": 1722418019.3162, "ip": "", "conv_id": "04128e2f519a462fad781cf2ce9f75a4", "model_name": "BAAI/bge-large-en-v1.5", "prompt": "Find me a planet near α 23h 06m 29.368s and δ −05° 02′ 29.04″ that could be habitable.", "output": [["Find me a planet near α 23h 06m 29.368s and δ −05° 02′ 29.04″ that could be habitable.", "Habitable zone\n\nK2-18b is an exoplanet 124 light-years away, orbiting in the habitable zone of the K2-18, a red dwarf. This planet is significant for water vapor found in its atmosphere; this was announced on September 17, 2019.\nIn September 2020, astronomers identified 24 superhabitable planet (planets better than Earth) contenders, from among more than 4000 confirmed exoplanets at present, based on astrophysical parameters, as well as the natural history of known life forms on the Earth.\nHabitability outside the HZ\nLiquid-water environments have been found to exist in the absence of atmospheric pressure and at temperatures outside the HZ temperature range. For example, Saturn's moons Titan and Enceladus and Jupiter's moons Europa and Ganymede, all of which are outside the habitable zone, may hold large volumes of liquid water in subsurface oceans.\nOutside the HZ, tidal heating and radioactive decay are two possible heat sources that could contribute to the existence of liquid water. Abbot and Switzer (2011) put forward the possibility that subsurface water could exist on rogue planets as a result of radioactive decay-based heating and insulation by a thick surface layer of ice.\nWith some theorising that life on Earth may have actually originated in stable, subsurface habitats, it has been suggested that it may be common for wet subsurface extraterrestrial habitats such as these to 'teem with life'. On Earth itself, living organisms may be found more than  below the surface."]], "corpus": "wikipedia"}
+{"tstamp": 1722419534.8414, "task_type": "retrieval", "type": "chat", "model": "BAAI/bge-large-en-v1.5", "gen_params": {}, "start": 1722419532.405, "finish": 1722419534.8414, "ip": "", "conv_id": "a33035b5460343c8a818ccb61691c9cd", "model_name": "BAAI/bge-large-en-v1.5", "prompt": "I have two children. One of them is a boy born on a Tuesday. What is the probability that I have two boys?", "output": [["I have two children. One of them is a boy born on a Tuesday. What is the probability that I have two boys?", "Boy or girl paradox\n\nAssume that the probability of being born on a Tuesday is ε =  which will be set after arriving at the general solution. The second factor in the numerator is simply , the probability of having two boys. The first term in the numerator is the probability of at least one boy born on Tuesday, given that the family has two boys, or  (one minus the probability that neither boy is born on Tuesday). For the denominator, let us decompose:.\nEach term is weighted with probability . The first term is already known by the previous remark, the last term is 0 (there are no boys).  and  is ε, there is one and only one boy, thus he has ε chance of being born on Tuesday. Therefore, the full equation is:\nFor , this reduces to\nIf ε is now set to , the probability becomes , or about 0.48. In fact, as ε approaches 0, the total probability goes to , which is the answer expected when one child is sampled (e.g. the oldest child is a boy) and is thus removed from the pool of possible children. In other words, as more and more details about the boy child are given (for instance: born on January 1), the chance that the other child is a girl approaches one half."]], "corpus": "wikipedia"}
+{"tstamp": 1722419534.8414, "task_type": "retrieval", "type": "chat", "model": "voyage-multilingual-2", "gen_params": {}, "start": 1722419532.405, "finish": 1722419534.8414, "ip": "", "conv_id": "2cf2632be84d4967a97e0bcfbf3a8748", "model_name": "voyage-multilingual-2", "prompt": "I have two children. One of them is a boy born on a Tuesday. What is the probability that I have two boys?", "output": [["I have two children. One of them is a boy born on a Tuesday. What is the probability that I have two boys?", "Boy or girl paradox\n\nAssume that the probability of being born on a Tuesday is ε =  which will be set after arriving at the general solution. The second factor in the numerator is simply , the probability of having two boys. The first term in the numerator is the probability of at least one boy born on Tuesday, given that the family has two boys, or  (one minus the probability that neither boy is born on Tuesday). For the denominator, let us decompose:.\nEach term is weighted with probability . The first term is already known by the previous remark, the last term is 0 (there are no boys).  and  is ε, there is one and only one boy, thus he has ε chance of being born on Tuesday. Therefore, the full equation is:\nFor , this reduces to\nIf ε is now set to , the probability becomes , or about 0.48. In fact, as ε approaches 0, the total probability goes to , which is the answer expected when one child is sampled (e.g. the oldest child is a boy) and is thus removed from the pool of possible children. In other words, as more and more details about the boy child are given (for instance: born on January 1), the chance that the other child is a girl approaches one half."]], "corpus": "wikipedia"}