## PRODUZA CALCULOS A MÃO COM A BIBLIOTECA HANDCALCS


```python
from math  import sqrt 
import sympy   as sp 
import handcalcs.render 
```


```python
%%render   # código mágico jupyter 
#PARAMETROS 
a = 2  
b = -5 
c = 3
```


\[
\begin{aligned}
a &= 2 \; 
\\[10pt]
b &= -5 \; 
\\[10pt]
c &= 3 \; 
\end{aligned}
\]


## FORMULA DE BHASKARA 


```python
%%render
x = (-b + sqrt(b**2 - 4*a*c) / (2*a))
```


\[
\begin{aligned}
x &= \left( \left( - b \right) + \frac{ \sqrt { \left( b \right) ^{ 2 } - 4 \cdot a \cdot c } }{ 2 \cdot a } \right)  = \left( \left( - -5 \right) + \frac{ \sqrt { \left( -5 \right) ^{ 2 } - 4 \cdot 2 \cdot 3 } }{ 2 \cdot 2 } \right) &= 5.25  
\end{aligned}
\]


## CALCULAR INTEGRAIS 


```python
a, b, c = sp.symbols('a b c')
```


```python
d = a**2 + b*a
f = sp.integrate (d,a)
f
```




$\displaystyle \frac{a^{3}}{3} + \frac{a^{2} b}{2}$




```python
%%render sympy
a = 5
b = 10
x = f
```


\[
\begin{aligned}
a &= 5 \; 
\\[10pt]
b &= 10 \; 
\\[10pt]
x &= \frac{ \left( a \right) ^{ 3 } }{ 3 } + \left( a \right) ^{ 2 } \cdot \frac{ b }{ 2 }  = \frac{ \left( 5 \right) ^{ 3 } }{ 3 } + \left( 5 \right) ^{ 2 } \cdot \frac{ 10 }{ 2 } &= 166.667  
\end{aligned}
\]


35b0accf82dc63c9af34ca2b8e18b0e6df4a40bf
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Jupyter Notebook
MATHEMATICS/calculos.ipynb
EricOliveira17/analise-de-dados-semi-estruturados-
ec93d6c6018bd15b2097cc810e9433651fc59b1d
MIT
2020-05-19T01:50:15.000Z
2020-05-19T01:50:15.000Z
MATHEMATICS/calculos.ipynb
EricOliveira17/analise-de-dados-semi-estruturados-
ec93d6c6018bd15b2097cc810e9433651fc59b1d
MIT
2021-03-01T18:30:52.000Z
2021-03-04T03:02:14.000Z
MATHEMATICS/calculos.ipynb
EricOliveira17/analise-de-dados-semi-estruturados-
ec93d6c6018bd15b2097cc810e9433651fc59b1d
MIT
2020-10-14T00:46:20.000Z
2020-10-14T00:46:20.000Z
Qwen/Qwen-72B
1. YES
2. YES