I'm trying to figure this out but I'm totally stumped. Here's what I want:

If the user provides an integer input less than 1, it should alert the user that they must provide an integer value of at least 1.
If the user provides any other input that causes an error, it should give a generic output, "Invalid input detected. Please provide a positive integer input." That way the program could detect strings as an input or whatever else I guess. Here's the code I've got so far:

```Python
while True:
	try:
		user_input = int(input("Please enter a positive integer value: "))
		if user_input <= 0:
			raise ValueError("Please enter an integer value greater than 0.")
		break
	except ValueError:
		print("Invalid input detected. Please provide a positive integer input.")
```

So here's the problem. If I give an integer input, I want it to output the "enter an integer value greater than 0." message. But every time it displays the "Invalid input. Please enter a positive integer." message. That's good if I enter a string for example, but I want it to have two different messages and I can't figure it out :(
The issue you're experiencing is caused by the way the exception is being raised. When the user provides an invalid integer input, a value error is raised. However, this raised value error is not printed, and only the custom message in the except statement is printed. Here is one method of addressing the issue:

```Python
while True:
    try:
        user_input = int(input("Please enter a positive integer value: "))
        if user_input < 1:
            print("Please enter an integer value greater than 0.")
        else:
            break
    except ValueError:
        print("Invalid input detected. Please provide a positive integer input.")
```

In the revised version, the input is evaluated. If the input is an integer value less than 1, a message alerting the user is printed, and the loop restarts. If the input is a valid integer, the else statement is triggered, and the loop breaks. If any other value error is raised, the custom error message is printed.