hat
Se poutèt sa, se sekans lan [2.0.0.0.2.1.1.1] jwenn. Nan egzanp lan sou bò dwat la, gen de spiroatoms, se konsa dispiro la kòmanse. Nan bag la tèminal an premye, gen de atòm, ki endike non dispiro la [2. Apre sa, gen yon sèl ak kat atòm nan bag la tèminal lòt ant de spiroatoms yo, revele non an de Molisk [2.1.3 5. Dezyèm spiroatom, konte 5, ki te ajoute kòm yon chemen ki pral rankontre kantite atòm yo apre kantite atòm nan bag tèminal la, dènye fwa a ajoute 9 ak atòm 10 ant 3 ak spiroatoms 5 Lè sa a, ajoute yon alkane ki gen menm kantite atòm nan konpoze an spiro, decane, namedispiro [2.1.3 5 .2 3] decane devwale pa non an.
eng
Therefore, the sequence [2.0.0.0.2.1.1.1] is obtained. In the example on the right, there are two spiroatoms, so the name dispiro starts. In the first terminal ring, there are two atoms, indicating the name dispiro[2. Next, there are one and four atoms in the other terminal ring between the two spiroatoms, revealing the name two snails [2.1.3 5 . The second spiroatom, numbered 5, has been added as a path that will encounter the number of atoms after the number of atoms in the terminal ring, the last time adding 9 and 10 atoms between 3 and 5 spiroatoms And then add an alkane having the same number of atoms of the spiro compound, decane, namedispiro [2.1.3 5 .2 3 ] decane revealed by the name.