#include <iostream>
#include <cstdio>
#include <string>
#include <algorithm>
#include <math.h>
#include <vector>
#include <set>

using namespace std;
typedef long long LL;
static const double EPS = 1e-9;

#define FOR(i,k,n) for (int i=(k); i<(int)(n); ++i)
#define REP(i,n) FOR(i,0,n) 
/*
const int dx[4] = {-1,0,0,0};
const int dy[4] = {0,-1,0,0};
const int dx2[4] = {-1,0,1,0};
const int dy2[4] = {0,1,0,-1};
*/
static const int dx[4] = {1,0,-1,0};
static const int dy[4] = {0,1,0,-1};
int main(void){
  int d = 0;
  /*
  int a[5][4];
  int b[4][5];
  */
  int m[9][9];
  int x=0,y=0;
  string tmp;
  /*
  for(int i=0; i<4; i++){
    for(int j=0; j<4; j++){
      c = getchar();
      a[i][j] = c - '0';
    }
    getchar();
    for(int j=0; j<5; j++){
      c = getchar();
      b[i][j] = c - '0';
    }
    getchar();
  }
  for(int j=0; j<4; j++){
    c = getchar();
    a[4][j] = c - '0';
  }
  */
  for(int i=0; i<9; i++){
    cin>>tmp;
    int jbegin;
    if(i%2){
      jbegin=0;
    }else{
      jbegin=1;
    }
    for(int j=jbegin,k=0; j<9; j+=2,k++){
      m[i][j] = tmp[k];
    }
  }
  for(int time=0; time>-1; time++){
    for(int r=-1; r<3; r++){
      //printf("%d",(d+r+4)%4);
      if(y+dy[(d+r+4)%4]>=0&&y+dy[(d+r+4)%4]<=8
          &&x+dx[(d+r+4)%4]>=0&&x+dx[(d+r+4)%4]<=8&&
          m[y+dy[(d+r+4)%4]][x+dx[(d+r+4)%4]]=='1'){
        d = (d+r+4)%4;
        x += 2*dx[d];
        y += 2*dy[d];
        break;
      }
    }
    char out;
    switch(d){
      case 0:
        out = 'R';
        break;
      case 1:
        out = 'D';
        break;
      case 2:
        out = 'L';
        break;
      case 3:
        out = 'U';
        break;
    }
    putchar(out);
    //printf("%d,%d\n",x,y);
    if(x==0&&y==0) break;
  }
  cout<<endl;
  return 0;
}