#include <stdio.h>

int main(){
int n,m,ans=0,total,a[1010];
  scanf("%d %d",&n,&m);
  for(int i=0;i<n;i++){
  	scanf("%d",&a[i]);
    total+=a[i];
  }
  for(int j=0;j<n;j++){
   if(a[j]>=(total*(1/4*m))){
    	ans++;
  }}
  if(ans==m){
  printf("Yes");
  }else{
  printf("No");
  }

}