#include <stdio.h>
#include <string.h>
#include <math.h>

int main(void) {
	int n, m, a[1000];
	double sum = 0;
	scanf("%d %d", &n, &m);
	for (int i = 0; i < n; ++i) {
		scanf("%d", &a[i]);
		sum += a[i];
	}
	int count = 0;
	for (int i = 0; i < n; ++i) {
		if (a[i] >= sum * (1.0 / (4 * m))) {
			count += 1;
		}
	}

	printf(count>=m ? "Yes" : "No");

	return 0;
}
