Deriving indifference curves I have been trying to work this out for quite a while now, but I can't seem to understand how to solve these kind of questions. Any help (or hint) would be highly appreciated. 

Professor Goodheart's colleague Dr. Kremepu gives 3 midterm exams. He drops the lowest and gives each student her average score on the other two exams. Polly Sigh is taking his course and has a 60 on her first exam. Let $x_2$ be her score on the second exam and $x_3$ be her score on the third exam. If we draw her indifference curves for scores on the second and third exams with $x_2$ represented by the horizontal axis and $x_3$ represented by the vertical axis, then her indifference
curve through the point ($x_2; x_3$) = (50; 70) is:


L-shaped with a kink where $x_2 = x_3$.
three line segments, one vertical, one horizontal, and one running from (70; 60) to (60; 70).
a straight line, running from (0; 120) to (120; 0).
three line segments, one vertical, one horizontal, and one running from (70; 50) to (50; 70).
a V-shaped curve with its point at (50; 70).
The Utility function here is the average score that Polly gets i.e.

$U(x_2,x_3)=\frac{max\{x_2,x_3,60\}+max^2\{x_2,x_3,60\}}{2}\\$

Where: $max^2\{.\}$ stands for second highest number.
Now this utility function can be rewritten as:

$U(x_2,x_3)= \begin{cases}\frac{x_2+x_3}{2}, &amp; \text{ if } x_2,x_3\geq 60,\\ \frac{60+x_3}{2}, &amp; \text{ if } x_2&lt;60, x_3&gt;x_2,\\ \frac{60+x_2}{2}, &amp; \text{ if } x_3&lt;60,x_3&lt;x_2,\\ \frac{60+k}{2}, &amp; \text{ if } k&lt;60,x_3=x_2=k.\\ 
\end{cases}$

Plotting its level curve i.e. the IC for utility level $c$ would be a horizontal line from point $(0,2c-60)$ to $(60,2c-60)$, a vertical line from point $(2c-60,0)$ to $(60,2c-60)$ and a line from $(60,2c-60)$ to $(2c-60,60)$.

So if $(x_2,x_3)=(50,70)$ option 2 satisfies the IC's description.