Prove that the profits of the firm weakly decreases with input prices Prove that the profits of the firm weakly decreases with input prices. More formally, suppose that
the firm has a production function f, so that its profit function is
π(p, w) = max(x≥0) $pf(x) − w · x$,
where p denotes the output price and w denotes the input price vector. Then show that if $w$ and $w'$ are two input price vectors such that $w'_j$ = $w_j$ for all $j \neq i$ and $w'_i$ &gt; $w_i$
, then $π(p, w') ≤ π(p, w)$
I know that as input prices decrease, the toal costs for the firm decrease as well. Due to the decrease in TC, the firm then produces more output at the same cost. However, due to the increase in supply, the price of the output falls to a new equilibrium, causing profits to fall as well unless the increase in q is proportionate to the decrease in price that would prevent profits from dropping.
However, I am unsure on how to start the proof using $\pi (p, w)$. Since it is $w$ that is changing, would I hold price of output fixed at $p$?
Then I would assume that $x'$ is profit maximizing at:
$$pf(x) − w'· x ≤ pf(x') − w'· x'$$
and $x$ is profit maximizing at:
$$pf(x) − w · x \geq pf(x') − w· x'$$
Then I would multiply the second equation by -1, getting
$$-pf(x) + w · x \leq -pf(x') + w· x'$$
I would then add that to the first equation getting:
$$ (− w'· x) + (w \cdot x) ≤ (− w'· x') + (w \cdot x')$$
which simplifies to:
$$ (w - w') (x - x') \leq 0 $$
Since all components of $w'− w$ are 0 except the ith
$$ (w_i - w_i') (x_i - x_i') \leq 0 $$
We are left with:
$$(x_i - x_i') \leq 0 $$
$$ x_i \leq x_i' $$
Leaving us with the fact that factor input demands at $x' \geq x$ therefore we assume that the demand for output is greater, causing prices to fall.
However, I have no idea how to prove that $π(p, w') ≤ π(p, w)$ if $w'_j$ = $w_j$ for all $j \neq i$ and $w'_i$ &gt; $w_i$.
I understand that the idea is based on the fact that $w'_j$ = $w_j$ and $w'_i$ &gt; $w_i$, $w' &gt; w $, that means that the $w' \cdot x$ in the profit function is greater than $w \cdot x$. Since the cost is greater in $\pi (p, w')$, that means that $π(p, w') ≤ π(p, w)$. However, I am confused as to how I can approach this proposition using the given profit function.
From FOC, we know that:
\begin{align}
\nabla_x\pi(\mathbf{x},\mathbf{w})=p\nabla f(\mathbf{x})-\mathbf{w}=\mathbf{0} \tag{1}
\end{align}
This will be true at equilibrium, i.e. for any given $\mathbf{w}$, the input vector $\mathbf{x}$ will adjust so that the above holds.
Now consider $d\pi(\mathbf{x},\mathbf{w})/d w_i$ (and using $(1)$):
\begin{align}
\frac{d\pi(\mathbf{x},\mathbf{w})}{d w_i} &amp;=\nabla_x\pi\cdot\nabla_{w_i} \mathbf{x} \, + \nabla_w\pi\cdot\nabla_{w_i} \mathbf{w} \\
&amp;=0 +\nabla_w\pi\cdot\nabla_{w_i} \mathbf{w} \tag{*}\\
&amp;=\nabla_w(pf(\mathbf{x})-\mathbf{w}\cdot \mathbf{x)} \cdot \nabla_{w_i} \mathbf{w} \\
&amp;= \Big(p\nabla_wf(\mathbf{x})-\nabla_w(\mathbf{w}\cdot \mathbf{x)}\Big)\cdot \nabla_{w_i} \mathbf{w} \\
&amp;= \Big(p \frac{\partial\mathbf{x}}{\partial\mathbf{w}}\nabla f(\mathbf{x})-\frac{\partial\mathbf{x}}{\partial\mathbf{w}}\mathbf{w} - \mathbf{x}\Big)\cdot \nabla_{w_i} \mathbf{w}\\
&amp;= \mathbf{J}(p\nabla f(\mathbf{x})-\mathbf{w})\cdot \nabla_{w_i} \mathbf{w}  -\mathbf{x} \cdot \nabla_{w_i} \mathbf{w} \\
&amp;= \mathbf{J} \nabla_x\pi(\mathbf{x},\mathbf{w})\cdot \nabla_{w_i} \mathbf{w}-\mathbf{x} \cdot \nabla_{w_i} \mathbf{w} \tag{**}\\
&amp;= -\mathbf{x} \cdot \nabla_{w_i} \mathbf{w} \\
&amp;= -x_i 
\end{align}
where, in steps $(*), (**)$, FOC is used and $\mathbf{J}$ is the Jacobian matrix.
Since, $x_i \geq0$, we have:
$$\frac{d\pi(\mathbf{x},\mathbf{w})}{d w_i} \leq0$$