Price distribution: Negative values? In their equation (5), Kaplan and Menzio claim that the price distribution in their Burdett-Judd market is given by

$$ F(p, u) = \{u \cdot A_1 \left[1 - \left(1 - B_1(u)\right)\frac{(r-c)p}{(p-c)r}y_u\right] \\
+ (1-u) \cdot A_2 \left[1 - (1 - B_2(u))\frac{(r-c)p}{(p-c)r}*w(u)\right]
 \}/C$$

For positive $A_i$, $B_i$, $C$, where $u$ denotes the unemployment rate and $p$ denotes the price. They continue claiming that


$F$ is continuous
has connected support


$c$ is the households outside option, $r$ is the reservation price, hence the distribution should only give positive mass to prices between $[c, r]$.

$$ B_1(u) = 2\nu(u)\frac{\psi_u}{1+\psi_u}$$

where $\nu(\sigma(u)) = \frac{s}{b} = \frac{1-u}{1+u(\psi_u - \psi_e)}$. In their calibration: $\psi_e = 0.02$, $\psi_u = 0.27$. Hence

$$ B_1(u) = 2\frac{1-u}{1+0.25u}\frac{0.27}{1+0.27}$$

The Issue

For example, at an unemployment rate of $0.05$, we have $B_1(0.05) = .38$. However, for $p = c + \epsilon$ (for small $\epsilon$), the denominator $p-c$ becomes very small small.

This means that the product of $1-B_1(0.05)\cdot (r-c)\cdots$ becomes very  large. One minus that is an very large negative number. The denominator $C$ is positive. A similar phenomenon happens with $B_2(0.05)$.

They call $F(p, u)$ the distribution. I assume this means the pdf. Can a pdf have negative values? Or what am I missing here?
In Lemma 1 they say that the support $\left[\underline{p}_t, \bar{p}_t \right]$ is such that $ c &lt; \underline{p}_t $.
So even though the support is connected, it does not extend to $c$, hence the $p \to c$ problem never arises.