Diminishing MRTS range So I was solving a question which says find the range in which MRTS is diminishing
$f(k,l) = 600k^2l^2-k^3l^3$ is the production function
I got the MRTS = $ -(1200kl^2-3k^2l^3) \over 1200k^2l-3k^3l^2$

Now, i'm getting $\frac{\partial f'(k,l)}{\partial k} = \frac{l}{k^2}$ then range is $l &lt;0 $ which doesn't seem to make sense. 
Is my answer correct or is there some mistake??
Fix the production function to a constant value $f_0$ so that

$$
f_0 = 600k^2l^2 - k^3 l^3 \tag{1}
$$

This is a figure for different values of $f_0$ (isoquants)



Note that with increasing $k$ the rate of change of $l$ becomes smaller for a given $f$ and a fixed change in $k$. We can show this more formally by taking the derivative w.r.t $l$ at both sides

$$
0 = 600\left(2kl^2 + 2k^2 l \frac{\partial l}{\partial k}\right) - \left(3k^2l^3 + 3k^3l^2\frac{\partial l}{\partial k}\right) \tag{2}
$$

You can further simplify this to

$$
0 = -3k l (-400 + k l)\left(l + k \frac{\partial l}{\partial k}\right) \tag{3}
$$

The solutions are $k = 0$, $l = 0$, $kl = 400$ or 

$$
\frac{\partial l}{\partial k} = -\frac{l}{k} \tag{4}
$$

Which confirms that that increasing $k$ decreases the MRTS, in other words, the range in which the marginal diminishes is $k &gt; 0$