How to make a star chart from entries in a Bright Star Catalogue? I know very little in astronomy, but I want to use the data in a Bright Star Catalogue to create star map projections for a specific time and place. 

For example one line is

{ "Dec": "-33° 31′ 46″", "HR": "13", "K": "4850", "RA": "00h 08m 03.5s", "V": "5.68" },


How would I convert this to an $x, y$ point on a printed star chart that could be used for viewing the sky at a specific time and place?
Here is a tentative answer based on your comment that you want to make a star chart. I'm not an expert in this but I used answers to RA/dec to Alt/Az program or method which link to http://www.stargazing.net/kepler/altaz.html

You have the star's position on the celestial sphere, convert it to decimal degrees:

     item              original             conversion                  decimal degrees
Declination:      -33°  31′   46″    -33 - 31/60. -  46/3600.         =   -33.529444  
Right Ascension   00h  08m  03.5s   (  0 +  8/60. + 3.5/3600.) x 15   =     2.014583


You have the time $UTC$ and longitude $LON$, convert it to $LST$ (local sidereal time). From the question Local Sidereal Time and @DavidHammen's answer:

$$LST = 100.46 + 0.985647 d + LON + 15 UT $$

where 


$LST$ is local sidereal time in degrees
$d$ is the number of days from J2000, including the fraction of a day
$UT$ is the universal time in decimal hours
long is your longitude in decimal degrees, East positive.


You have $RA$ and $LST$, get $HA$ (Hour Angle)

$$HA = LST - RA$$

You have $DEC$ and $HA$, get altitude and azimuth

$$ALT = \arcsin\left( \sin(DEC) \sin(LAT) + \cos(DEC) \cos(LAT) \ cos(HA) \right)$$

$$AZ = \arccos \left( \frac{\sin(DEC) - \sin(ALT) \sin(LAT)}{\cos(ALT) cos(LAT)} \right)$$

From there you have to decide how you want to plot altitude and azimuth on your map.

If you want to plot it on a circle of radius $R$ then use

$$X = R (1 - ALT/90) \cos(AZ)$$

$$Y = R (1 - ALT/90) \sin(AZ)$$

assuming $ALT$ is in degrees. In this map "top" or $X, Y = 0, R$ will be north and $X, Y = R, 0$ will be East. You will have to decide if that's the best way to plot it or if you want to mirror East-West.