Why does a hot cloud need more mass to collapse? I was wondering why does a hot cloud need more mass to collapse than a cold cloud to form a protostar? Is it because there's a higher thermal pressure inside the hotter cloud than it is in a colder one?
It's more do do with having a higher pressure gradient than a higher pressure, though for a cloud of a set size, the two are equivalent.

For a cloud to be in equilibrium requires
$$ \frac{dP}{dr} = - G\frac{M\rho}{R^2},$$
where $dP/dr$ is the pressure gradient and $M$ and $R$ are the mass and radius of the cloud and $\rho$ is its density.

It we just make a rough approximation of a linear pressure gradient and that the pressure on the outside is zero, then
$$ P_c \simeq G\frac{M\rho}{R},$$
where $P_c$ is the central pressure, which is in turn, for a perfect gas $P_c = \rho k_B T_c/\mu$ where $T_c$ is the temperature and $\mu$ is the average mass of a particle in the cloud. 

In order to collapse, the RHS has to get bigger than the LHS.  For a given mass, radius and density, then this means the temperature of the cloud must be less than some critical value.  i.e.
$$ G \frac{M\rho}{R} &gt; \frac{\rho k_B Tc}{\mu}$$
$$ T_c &lt; \left(\frac{G\mu}{k_B}\right)\left( \frac{M}{R}\right)$$

Thus a hot cloud won't collapse and a cold one will. But one way to get the hotter cloud to collapse would be to increase $M$ (while keeping $R$ constant).