Considered the following inner products:


$(1)$ $\langle x,y \rangle = \sum\_{t=1}^{n}x\_{t}y\_{t}$


$(2)$ $\langle x,y \rangle\_{c} = \sum\_{t=1}^{n}x\_{t}\bar{y}\_{t}$


consider the following surfaces:


$\underline{Surface (a)}$: $\langle x, x \rangle = 1$


$\underline{Surface (b)}$: $\langle x, x \rangle = \mathbb{i} = \sqrt{-1}$


$\underline{Surface (c)}$: $\langle x, x \rangle\_{c} = 1$


In each of the above surfaces, how many points can one place so that the inner product (defined in both $(1)$ and $(2)$) between any pair of the points is purely imaginary of form $0 + \mathbb{i}r$ where $\mathbb{i}=\sqrt{-1}$ and $r \in \mathbb{R}$ and how many points are there so that the pairwise product is purely real of form $r \in \mathbb{R}$?


The case when we seek the pairwise inner product(both $(1)$ and $(2)$ to be purely real is infinite for surfaces $(a)$ and $(c)$ (Just restrict your sphere to have purely real coordinates and search among those points).


Likewise, the case when we seek the pairwise inner product(both $(1)$ and $(2)$ to be purely imaginary is infinite for surface $(b)$ (Just restrict your sphere to have purely imaginary coordinates and search among those points).


What happens in the following combinations?


$\underline{A}$:$(b)$ when we seek pure imaginary inner products (both $(1)$ and $(2)$).


$\underline{B}$:$(a)$ and $(c)$ when we seek pure real inner products (both $(1)$ and $(2)$).


$\underline{A}$ has been shown to have finitely many points ($O(n)$ atmost) by unknown(google) below.



Number of points on a complex sphere with pairwise inner product restriction
It's easy to see you can't have infinitely many points: there would be two that are within $\epsilon>0$ of each other, and thus would have inner product very close to $\langle z,z\rangle=1$ (which would then not be purely imaginary).


Since $\Re\langle u,v\rangle$ forms a genuine inner product on $\mathbb C^n$, two vectors whose inner product is purely imaginary would be orthogonal. Thus you can have at most $2n$ such vectors. In the other direction, it's easy to see that the following is a collection of $2n$ vectors where every pairwise inner product is purely imaginary:
$$
(1,0,\ldots,0),(i,0,\ldots,0),(0,1,0,\ldots,0),(0,i,0,\ldots,0),\ldots
$$


