
> 
> $A$ is a C$^\*\! $-algebra and $(x\_n)\_{n\in \mathbb{N}} \subseteq A $.
>  If $\ $ $yx\_n\to 0 $ for all $y\in A$, Is it true that $x\_n$ is weakly
>  convergent to $0$ ?
> 
> 
> 


For unitals this is trivial. For characters like 
$w\in \Omega (A)$ we have $w(x\_n)\to 0$ but if for all functionals, I don't know.



If $\ $ $yx_n\to 0 $ for all $y$ in a C$^*$-algebra, Is it true that $x_n$ is weakly convergent to $0$?
Yes, it's true. By the GNS construction, every bounded linear functional on $A$ is of the form $A\ni a\mapsto \langle \pi(a)\xi,\eta \rangle$ for some non-degenerate \*-representation $\pi$ on $H$ and $\xi,\eta\in H$. By the Cohen--Hewitt factorization theorem, $H=\pi(A)H$ (no need to take the closure). Consequently, $A\times A^\*\ni (a,\phi)\mapsto \phi(a,\,\cdot\,)\in A^\*$ is surjective. 


