Let $M$ be a manifold, $P$ a closed subset and sub-manifold of $M$, and $j : (M,\emptyset) \to (M,P)$ the injection (I note $f : (M,P) \to (N,Q)$ a smooth map $M \to N$ such that $f(P) \subset Q$). The pullback $j^\* : \Omega\_{dR,c}(M,P) \to \Omega\_{dR,c}(M)$ is just $\alpha \mapsto \alpha$ for a form $\alpha$ null on $P$, and is clearly injective. It induced in de Rham cohomology with compact support $\bar{j}^\* : H\_{dR,c}(M,P) \to H\_{dR,c}(M)$.


But is $\bar{j}^\*$ injective too ?


If $\alpha \in Z\_{dR,c}(M,P)$ is such that $[\alpha]\_M = 0$, $\alpha = d\,\beta$ for $\beta \in \Omega\_{dR,c}(M)$, but there is no reason why $\beta$ should be null on $P$. Is it always possible to find $\beta' \in \Omega\_{dR,c}(M,P)$ such that $d\,\beta' = d\,\beta$ ? I have a big doubt...



Relative de rham cohomology with compact support
Not necessarily. For simplicity, let's assume a closed manifold $M$ and a closed submanifold $P$. Then all forms automatically have closed support and the de Rham cohomology is isomorphic to singular cohomology with real coefficients (my preferred way of thinking about cohomology). Then your map $\bar j^\*$ is just the map $H^i(M,P)\to H^i(M)$ in the long exact sequence of the pair $$\cdots\to H^{i-1}(P)\to H^i(M,P)\to H^i(M)\to H^i(P)\to H^{i+1}(M,P)\to\cdots$$(coefficients suppressed). From there it's not difficult to come up with examples. For example, choose $M$ to be a large sphere but $P$ to be a submanifold in some middle dimension with non-trivial homology. Then you force $H^i(M,P)\cong H^{i-1}(P)\neq 0$ for some $i$ but the map $H^i(M,P)\to H^i(M)$ will be trivial but not injective.


You might have a look at something like Bott and Tu for the general theory.


