Where can I find a proof of the following scaled version of Harnack inequality?



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> Let $v$ be a non-negative solution of ${L}u = 0$ in $B\_1$, with $L$ a uniformly elliptic operator. Then, for $r<1$, there exist constants $c$ and $p$ such that 
>  $\sup\_{B\_r} v \le c\,(1-r)^{-p}\, \inf\_{B\_r} v.$
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Scaled Harnack inequality $\sup_{B_r} v \le c\,(1-r)^{-p}\, \inf_{B_r} v$
The usual Harnack inequality says that $C^{-1}u(x) \leq \inf\_{B\_{\rho/2}(x)}u \leq \sup\_{B\_{\rho/2}(x)} u \leq Cu(x)$ for any $B\_{\rho}(x) \subset B\_1$ and $C$ universal depending on the ellipticity constants, etc. of $L$. Applying this with $x = 0$ and $\rho = 1$ gives
$$C^{-1}u(0) \leq \inf\_{B\_{1-2^{-1}}}u \leq \sup\_{B\_{1-2^{-1}}} u \leq Cu(0).$$
Applying it again for all $x \in \partial B\_{1/2}$ and $\rho = 1/2$, and using the previous inequality, gives
$$C^{-2}u(0) \leq \inf\_{B\_{1-2^{-2}}}u \leq \sup\_{B\_{1-2^{-2}}}u \leq C^2u(0).$$
Proceeding inductively with $x \in \partial B\_{1-2^{-k}}$ and $\rho = 2^{-k}$ gives 
$$C^{-k}u(0) \leq \inf\_{B\_{1-2^{-k}}}u \leq \sup\_{B\_{1-2^{-k}}}u \leq C^ku(0),$$
so in particular
$$\sup\_{B\_{1-2^{-k}}}u \leq C^{2k} \inf\_{B\_{1-2^{-k}}}u.$$
For $r \in (0,\,1)$ choose $k \geq 1$ such that $1-2^{1-k} \leq r \leq 1-2^{-k}$, and let $p = 2\frac{\log C}{\log 2}$. Since $B\_r \subset B\_{1-2^{-k}}$ the previous inequality gives
$$\sup\_{B\_r} u \leq C^{2k} \inf\_{B\_r}u = 2^p(2^{1-k})^{-p} \inf\_{B\_r}u.$$
Since $1-r \leq 2^{1-k}$ the right side is bounded above by $2^p(1-r)^{-p}\inf\_{B\_r}u$, completing the proof.


