This is a direct consequence of my previous question: [Extending group actions on varieties](https://mathoverflow.net/questions/36321/extending-group-actions-on-varieties)


In his answer, inkspot said that group actions can be extended if the variety has ample canonical class and is smooth, but mentions that canonical singularities can be allowed. Now, my situation doesn't involve a smooth variety, but instead I have an orbifold.


However, I know that for surfaces, the canonical singularities are the duVal singularities, and are all orbifold points (they're all $\mathbb{C}^2$ modulo a finite subgroup of $\mathrm{Sl}\_2$.)


Now, I've not studied general singular points of surfaces, so I could be wrong already with surfaces, but are orbifold singularities canonical?



Are orbifold singularities canonical?
For quotient singularities there is the so-called Reid-Tai criterion to check whether the singularity is canonical or not.
Suppose $G$ is a finite subgroup of $GL\_n(\mathbb{C})$ without quasi-reflections. Let $m=|G|$ and fix a primitive $m$-th root of unity $\zeta$. Let $g\in G$ and let $0\leq a\_i < m$ be such that $\zeta^{a\_1},\dots,\zeta^{a\_n}$ are the eigenvalues of $g$. Then the Reid-Tai sum of $g$ is defined as $\Sigma(g):=1/m(\sum a\_i)$. 


The Reid-Tai criterion states that $\mathbb{C}^n/G$ has a canonical singularity at 0 if and only if $\Sigma(g)\geq 1$ for all $g\in G, g\neq id$.


(Taking a quotient by quasi-reflections does not yield a singularity, the Reid-Tai sum depends on the choice of $\zeta$, the criterion does not.)


For more on this see e.g. M. Reid's Young person's guide to canonical singularities (Bowdoin 1985 proceedings).


