Note: Here all functions are $\mathbb R \to \mathbb R$. $Id$ denotes the identity function.


Let $g\_i$ be a family of functions indexed by some (potentially uncountable) index set $I$. Given a function $f$, we say $g\_i$ are **uniformly $o(f)$** if for every $e > 0$ there exists some $d > 0$ such that $|g\_i(x)| \le |ef(x)|$ for all $i$ in $I$ and $x$ in $B\_d (0)$.


Call a function $f$ **uniformly differentiable** if for every $x$ in $\mathbb R$, $f(x+h) = f(x) + L\_x (h) + r\_x (h)$ for some linear functions $L\_x$ and some uniformly $o(Id)$ functions $r\_x$.


When is a differentiable function uniformly differentiable?



Uniformly differentiable functions
At first, we should have $L\_x(h) =f'(x) h$ (this is the definition of the derivative, if we forget the uniformness.) 


I claim that $f'$ must be uniformly continuous (seen from summing up the relations for $(x, h) $ and $(x+h, - h) $), and this is enough (seen from Lagrange intermediate value theorem $f(x+h) =f(x) +h f'(z) $, with some $z$ between $x$ and $x+h $). 


