I have to simulate independent draws from a very complicated distribution. They only feasible way appears to be using MCMC. I was considering running thousands of chains in parallel, but that would slow things down from me considerably. So I am running one long MCMC chain. Assuming that MCMC chain run did converge nicely ( I realize even determining this is practically impossible in general). . Can I argue that the thinned sample obtained from selecting every 100th observation (or at a sufficiently high lag at which the observed autocorrelation function is close to 0) effectively approximates ,in some sense, a i.i.d draw from the desired distribution. If yes, any references would be greatly appreciated. 



near independence of markov chain observations at high lags
From talking to statisticians, it seems like the standard thing to do is assume a yes. For a specified sequence or thinning, one can create Markov chains which exhibit 0 autocorrelation but a 'very large' amount of dependence despite the thinning, but the idea is that this should be pretty pathological, and so you are probably 'pretty safe'. The examples that come to mind for me are chains like '$X\_{t}$ is iid 0-1 for t not divisible by a million, and equal to the sum of the previous 999,999 $X\_{s}$ mod 2 for t divisible by a million'


So, you won't get any sort of theoretical justification without telling us something about your chain, because there really are bad chains out there, where what you want fails badly... but in the real world, you can probably wave your hands. Note that just increasing your thinning isn't enough to get rid of this - for any finite amount of thinning, there are bad chains which horribly violate independence despite having 0 covariance.


There is a big world of convergence diagnostics out there. Gelman-Rubin, as pointed out, is a standard. Some other standards include the Geweke test, Mykland-Yu's Cusum test, Raftery-Lewis, and Heidelberg-Welch. There is a lot of literature on each of these, but with the slight exception of some easy calculations in Mykland-Yu, it is all extremely handwavey.


