Let S be any compact and denumerably infinite metric space and let d be the metric of S. We shall say that S satisfies condition C, if there exists at least one infinite sequence-------------p(1),p(2),.....,p(n),....of points of S such that (1) each point of S occurs once and only once in the sequence (2) the series d(p(1),p(2))+d(p(2),p(3))+.....+d(p(n),p(n+1))+....is convergent. If S satisfies condition C, an infinite version of the travelling salesman problem can be posed for the points of S. S always contains at least one limit point, since otherwise it could be covered by an infinite set of pairwise disjoint open balls, each containing a point of S-an impossibility if S is compact. It is easy to show that S cannot satisfy condition C if it contains more than one limit point. My question is: If S contains one and only one limit point, does S then necessarily always satisfy condition C?



A question about metric spaces that are compact and denumerably infinite
Let the space consist of a point $P$ and infinitely many other points $Q\_n$ for $n\in\mathbb N$. Let the distance from $P$ to $Q\_n$ be $1/n$. Let the distance from $Q\_n$ to $Q\_m$ for $m\neq n$ be $(1/n)+(1/m)$. This seems to be a counterexample for your question.


