In this old question of mine


<https://math.stackexchange.com/questions/1651906/spheres-as-symplectic-homogeneous-spaces>


the presentation of spheres as symplectic group homogeneous spaces was discussed very well, giving
$$
S^{4n-1} \simeq Sp(n)/Sp(n-1).
$$


Going us back now to the presentation of the spheres most clear in all our minds:
$$
S^{2n-1} \simeq SU(n)/SU(n-1) \simeq U(n)/U(n-1).
$$
We can recall that this gives to the sphere $S^{2n-1}$ a canaonical $U(1)$-action. Moreover, the invariant space of this $U(1)$-action is the complex projective space, i.e.
$$
\mathbb{CP}^{n-1} \simeq S^{2n-1}/U(1).
$$


So we can now see what my question is! Does there exist a $U(1)$-action on 
$S^{4n-1}$ given from its presentation as $Sp(n)/Sp(n-1)$? If yes, then what is the quotient $S^{4n-1}/U(1)$? Maybe it is just $\mathbb{CP}^{2n-1}$? 



Torus actions on $Sp(n)$-spheres
The presentation $\mathbb{S}^{2n-1} = \mathit{U}\_n/\mathit{U}\_{n-1}$ is tantamount to considering $\mathbb{S}^{2n-1}$ as the unit sphere in $\mathbb{C}^n$ (as $\mathit{U}\_n$ is the group of $\mathbb{C}$-linear maps of $\mathbb{C}^n$, acting, say, from the right, preserving the Hermitian inner product and $\mathit{U}\_{n-1}$ is the stabilizer of a given vector). Now $\mathbb{C}^n$ has the structure of a $\mathbb{C}$-vector space, so you can quotient out by complex numbers of unit norm, $\mathit{U}\_1$, getting, as you say, $\mathbb{P}^{n-1}(\mathbb{C})$ as $\mathbb{S}^{2n-1}/\mathit{U}\_1 = \mathit{U}\_n/(\mathit{U}\_{n-1}\times \mathit{U}\_1)$. In other words, the $(2n-1)$-sphere is fibered in circles with base $\mathbb{P}^{n-1}(\mathbb{C})$ (for $n=2$, noting that $\mathit{SU}\_2$ is isomorphic to $\mathit{Spin}\_3$, this is the classical Hopf fibration $\mathbb{S}^1 \hookrightarrow \mathbb{S}^3 \to \mathbb{S}^2$).


The analogous description of $\mathbb{S}^{4n-1} = \mathit{Sp}\_n/\mathit{Sp}\_{n-1}$ is to consider $\mathbb{S}^{4n-1}$ as the unit sphere in the space $\mathbb{H}^n$ of quaternionic vectors with the standard Hermitian inner product, so that $\mathit{Sp}\_n$ is the group of $\mathbb{H}$-linear maps (acting on the right, say, and where $\mathbb{H}$ acts on the left) preserving the product in question and $\mathit{Sp}\_{2n-1}$ is the point stabilizer. This time we can quotient out by quaternions of unit norm, $\mathit{Sp}\_1$, and this describes $\mathbb{P}^{n-1}(\mathbb{H})$ as $\mathbb{S}^{4n-1}/\mathit{Sp}\_1 = \mathit{Sp}\_n/(\mathit{Sp}\_{n-1}\times \mathit{Sp}\_1)$. In other words, the $(4n-1)$-sphere is fibered in $3$-spheres with base $\mathbb{P}^{n-1}(\mathbb{H})$ (for $n=2$, noting that $\mathit{Sp}\_2$ is isomorphic to $\mathit{Spin}\_5$, and $\mathit{Sp}\_1 \times \mathit{Sp}\_1$ to $\mathit{Spin}\_3 \times \mathit{Spin}\_3 = \mathit{Spin}\_4$, this is the Hopf fibration $\mathbb{S}^3 \hookrightarrow \mathbb{S}^7 \to \mathbb{S}^4$).


(Of course you can also quotient $\mathbb{S}^{4n-1}$ by $\mathit{U}\_1$ if you want, but I don't see how that can be a question since $\mathbb{S}^{4n-1}$ is already a $\mathbb{S}^{2m-1}$ for $m=2n$ so you already have the answer.)


And before you ask, there is also a Hopf fibration $\mathbb{S}^7 \hookrightarrow \mathbb{S}^{15} \to \mathbb{S}^8$ which makes it look like $\mathbb{S}^8 = \mathbb{P}^1(\mathbb{O})$ should be the quotient of an action of "the group of octonions of unit norm" on the unit sphere in $\mathbb{O}^2$ but, alas, there is no such thing as "the group of octonions of unit norm", and while it makes some sense to think of $\mathit{Spin}\_9$ as the "octonionic $U\_2$" in the description of $\mathbb{P}^1(\mathbb{O}) = \mathbb{S}^8$ as $\mathit{Spin}\_9/\mathit{Spin}\_8$, there is no way to decompose $\mathit{Spin}\_8$ as the product of two "octonionic $U\_1$" factors. Furthermore, while $\mathbb{P}^2(\mathbb{O}) = F\_4/\mathit{Spin}\_9$ can be defined (where $F\_4$ can be thought of as some kind of "octonionic $U\_3$"), there does not exist a fibration of $\mathbb{S}^{23}$ with base $\mathbb{P}^2(\mathbb{O})$ and fiber $\mathbb{S}^7$, so the analogies stop there.


