Let $A$ be an abelian variety and $\hat A$ be the dual abelian variety. If $P$ is the (normalized) Poincare line bundle, then Mukai defines $R\hat S:D(A)\to D (\hat A)$ via $R\hat S(?)=Rp\_{\hat A,\*}(Lp\_A^\*(?)\otimes P)$ and $RS:D(\hat A)\to D(A)$ via $R S(?)=Rp\_{ A,\*}(Lp\_{\hat A}^\*(?)\otimes P)$. He then shows that $R\hat S\circ R\hat S =(-1\_A)^\*[-g]$ on $D^b\_{qcoh}(A)$ and $R\hat S\circ R\hat S =(-1\_{\hat A})^\*[-g]$ on $D^b\_{qcoh}(\hat A)$. The proof uses the projection formula which can fail for non-quasi coherent sheaves and hence for $D(A)$. My question is: Is there a counter example to $R\hat S\circ R\hat S =(-1\_A)^\*[-g]$ in $D(A)$? 



Fourier Mukai transform for non-quasi coherent sheaves
I think it is clear that $R\hat{S}$ is not an equivalence on the categories of all $O$-modules. Indeed, if it were an equivalence, it would send product to product, and also preserve quasi-coherence. Let $M\_x$ be a sky-scraper sheaf at $x\in A$; its image under $R\hat{S}$ is an invertible $O$-module on $A^\vee$ (up to a shift). However, an infinite product of copies of $M\_x$ is quasi-coherent, while the infinite product of invertible $O$-modules is not quasi-coherent.


