Let T be a two-dimensional torus and Y be the one point
compactification of a two dimensional sphere ($S^2$) minus three points.
I have to prove:


1)they have the same fundamental group


2)they are homotopically equivalent


This is what i thought: i can see Y this way, let A,B,C three 
distinct points on the sphere and P a point not on the sphere,
Y is homotopically equivalent to $S^2\cup\overline{AP}\cup\overline{BP}\cup\overline{CP}$.
My hope for showing that they have the same fundamnetal group was to use 
van kampen theorem with open sets one $U$ homeomorphic to an open disk and the other one $V$ homotopically equivalent to a bouquet of 2 circles and $U\cap V$ 
homotopically equivalent to a circle. Now i would like to show that the generator of $\pi\_1(U\cap V)$ is sent by inclusion map to the commutator of the generators of $\pi\_1(V)$ but i can't see how.


For the homotopy equivalence i can't see the homotopy between these two spaces.


Please can anyone help?


Thank you in advance.



Question about the fundamental group and homotopy equivalence
I think Y is homotopy equivalent to $S^2\vee S^1\vee S^1$. Proof: $Y$ is homotopy equivalent to the homotopy cofiber or the map from $3$ point to $S^2$. This map is null-homotopic, so $Y$ is equivalent to the wedge sum of $S^2$ with the suspension of three points. Suspension of three points is equivalent to $S^1\vee S^1$. 


It is easy enough to construct the homotopy equivalence directly.


In conclusion: both (1) and (2) are false.


