For any Riemannian manifold are the exp and log maps (from a predetermined base) conformal? If not, are there some manifolds where they are and others where they aren't?



Are the exp and log maps of Riemannian geometry conformal
See Robert Bryant's answer to [Complex manifolds in which the exponential map is holomorphic](https://mathoverflow.net/questions/67903/complex-manifolds-in-which-the-exponential-map-is-holomorphic) in which he proves that the surfaces for which the exponential map is conformal are precisely the flat ones.


If the exponential map is conformal on some Riemannian manifold of dimension $\ge 3$, it is a conformal map on the intersection $P \cap B$ of any 2-plane $P\subset T\_m M$ in any tangent space with the ball $B\subset T\_m M$ of radius equal to the injectivity radius. So the curvature vanishes on $e^{P\cap B}$, i.e. the sectional curvature vanishes, so the Riemannian manifold is flat.


