What is the length of the shortest word $w\in F\_2$ such that $w(x,y)$ is trivial for every $x,y\in S\_n$?


There is a simple argument showing that we must have $\ell(w)\geq n$. See [here](https://mathoverflow.net/questions/20471/why-are-free-groups-residually-finite/20485#20485) for instance. It seems likely however that $\ell(w)$ must be super-polynomial in $n$.


What is the state of the art for lower bounds?


(As for upper bounds, the paper "Identical relations in symmetric groups and separating words with reversible automata" by Gimadeev and Vyalyi finds an upper bound of $\exp(\sqrt{n}\log n)$.)



What is the length of the shortest law of $S_n$?
As far as I know, the state of the art gives some improvements to those bounds, but they are not huge. For a better lower bound: given a nontrivial element $w \in F\_2$ of word length $\ell$, using a result of Buskin (*Economical separability in free groups*, Sib. Math. J., 50 (2009), 603-608) there exists a subgroup, $H$, of index $\ell/2+2$ that does not contain $w$. By looking at the action of $F\_2$ on $F\_2/ H$ we get a representation of $F\_2$ into $S\_{\ell/2+2}$, that does not kill $w$. Therefore, in order for $w$ to be trivial in any representation of $F\_2$ into $S\_n$ we must have that $n \leq \ell /2 + 2$, or $2(n-2) \leq \ell$.


There are also better upper bounds known (see, for instance, *Asymptotic growth and least common multiples in groups* (me and Ben McReynolds), Bulletin of the LMS (2011)).


Your question is equivalent to quantifying residual finiteness of free groups (the non-normal case), for which the precise answer is still unknown (the best known bounds are from the papers above).


