Let $K$ be a field and let $n\geq 2$. If $n=2$, then the set of $K$-isomorphism classes of $PGL\_n$-torsors is in bijection with the $n$-torsion of the Brauer group of $K$.


Is this only for $n=2$?


Is there any relation between $H^1(G\_K,PGL\_n)$ and the Brauer group for $n>2$?



Do $PGL_n$-torsors induce elements of the Brauer group
Your first statement is not quite true. A $\mathrm{PGL}\_2$-torsor does indeed give an element of order $2$ in the Brauer group, but there can be elements of order $2$ in the Brauer group of a general field $K$ that are not represented by quaternion algebras, so do not come from $\mathrm{PGL}\_2$-torsors. What is true is that the image generates the $2$-torsion in the Brauer group: this follows from the Merkurjev-Suslin theorem. Part of the reason this is confusing is that $\mathrm{H}^1(K,\mathrm{PGL}\_n)$ is not a group, since $\mathrm{PGL}\_n$ is not commutative. Look up the *period-index problem* for more details.


That said, there is indeed a natural map $\mathrm{H}^1(K,\mathrm{PGL}\_n) \to \mathrm{Br}(K)$ for arbitrary $n$: it comes from the exact sequence in (non-Abelian) cohomology coming from the short exact sequence



> 
> $0 \to \mathbb{G}\_m \to \mathrm{GL}\_n \to \mathrm{PGL}\_n \to 0$
> 
> 
> 


of algebraic groups over $K$, together with the identification $\mathrm{Br}(K) = \mathrm{H}^2(K,\mathbb{G}\_m)$. To see that the image lands in the $n$-torsion, compare this with the corresponding sequence for $\mathrm{SL}\_n$ and use the Kummer sequence.


There are lots of references for this kind of stuff; an excellent one is *Central simple algebras and Galois cohomology* by Gille and Szamuely.


