look at Problem14.12 of chapter3 of "Aliprantis-Burkinshaw-Principles of real analysis-3ed.1998" ; 12. Let A be the collection of all measurable subsets of X of finite measure. That is, A = {B in X: m(A) < oo}. a. Show that A is a semiring. b. Define a relation ~ on A by B ~ C if m(B \Delta C) = 0. Show that ~ is an equivalence relation on A. c. Let D denote the set of ail equivalence classes of A. For B in A let B\* denote the equivalence class of B in D. Now for B\*, C\* in D define d(B\*, C\*) = m(B \Delta C). Show that d is well defined and that (D, d) is a complete metric space. (For this part, see also Exercise [3] of Section [31].) 


Now let m be lebesgu measure on Real numbers and X be a subset of Real line, is (D,d) a connected space with topology induced with meter d?



Is P(X) a connected set for a set X with a $\sigma$-algebra P(X) and a measure function m on it to [0,$\infty$] when P(X) is equiped with meter d, that for every A,B in P(X), $d(A,B)=m(A \Delta B)$?
Note that to get a true distance, you have to restrict to measurable sets of finite measure, and to quotient over null sets. This way you get a closed subspace $M$ of $L^1(X)$ (the subset of binary functions). If the measure is atomless, then $M$ is even path-connected. A well-known result on atomless measures (essentially due to Sierpinski) is that for any measurable $A$, with measure $\alpha$, there exists a nested family of measurable sets $\{A\_t\} \_ {t\in[0,\alpha ]}$, such that $A\_ 0 = \emptyset$,$A\_\alpha=A$ and $m(A\_t)=t$ for all $t$. On the other hand, if there is an atom $A\in M$, then $M$ is the union of its non-empty open sets $\{B\in M\, : \, B\supset A\}$ and $\{B\in M\, : \, B\cap A=\emptyset \}$, so $M$ is not connected.


