Assume we are given a smooth manifold $M$ and let $TM^{\otimes r}, r>1,$ be some
tensor power of its tangent bundle. 


Is there any general observation/result
saying when there exists a manifold $N$ and a smooth map $f: M \rightarrow N$ such that the pull back bundle $f^\*TN$ is isomorphic to
$TM^{\otimes r}$?


This question is just a result of curiosity.



Classifying tensor powers of tangent bundles as pullbacks of appropriate tangent bundles
the idea is the folk fact that the universal space and universal stable \*\* bundle can be taken to be a manifold and its tangent bundle [see proof below ]


take r=3 and let M have dim d
then N should have dimension 3d


any [stable] bundle [like the tensor power] over a d dim space [like M] can be induced by a map into the universal space by a map which goes into the d skeleton of the universal space


the d skeleton of the universal space can be embedded in R^2d and thickened to a manifold nghd to obtain a parallizable manifold


the universal bundle over the d skeleton can be reduced to a d dim bundle using obstruction theory


the total space of this bundle pulled back to the thickened nghd will be the N of dim 3d


its tangent bundle is isomorphic to the universal bundle [because they are stably isomorphic]


the classifying map pulls the tangent bundle back to the required bundle


this proof works for r bigger but not immediately for r=2 [but mazur thickening theory should do this case]


dennis sullivan 


\*\*stable here means fibre dim bigger than dim base


