Given a Riemann surface $S$, e.g. $\mathbb{P}^1(\mathbb{C})$, with complex conjugation on the coordinates and a holomorphic vector bundle $E$ over $S$.


The complex conjugation $f$ is not holomorphic, but $C^{\infty}$. So we can look at $f^\*E$ as a smooth real vector bundle. Since $f$ is an involution $E$ and $f^\*E$ are isomorphic as smooth real bundles (this is most likely wrong). But somehow there should be more structure on $f^\*E$. I mean $f$ is antiholomorphic, that should be useful somehow.


Is there a way to define a (canonical?) complex structure on $f^{\*}E$, such that for any point $p$ we have an antilinear isomorphism $E\_{p} \rightarrow f^{\*}E\_{p}=E\_{\overline{p}}$? 


I think we don't get a linear iso, since the complex conjugation itself is only antilinear.



Definition of a complex structure on a vector bundle
For any antiholomorphic Diffeomorphism $f\colon S\to S$ we get a canonical identification $f^\star\bar K=K,$ $ K $ and $\bar K$ being the canonical and anticanonical bundle of the Riemann surface. A holomorphic structure on a complex vectorbundle $E$ is the same as an complex operator
$D\colon\Gamma(E)\to\Gamma(\bar KE)$ satisfying the (Cauchy Riemann) Leibnitz rule. (holomorphic sections are exactly the one in the kernel of D). (For higher dimensions this is not true.) 


Now, $f^\* E$ has a natural complex structure (it's just i).
Therefore one gets an anti-holomorphic structure $\bar D\colon\Gamma(f^\star E)\to\Gamma(Kf^\* E)$ satisfying the antiholomorphic Cauchy Riemann equation.
But the complex conjugate bundle $\bar E$ also has a anti-holomorphic structure, since $\overline{\bar K E}=K\bar E.$ Therefore, $f^\* \bar E$ has a natural holomorphic structure.


These two holomorphic structures are not isomorphic in general:
In the case of a line bundle $L=E$ of degree $0$ one might see this as follows: every holomorphic structure $D$ gives rise to an unique unitary flat connection $\nabla$ such that
$D=1/2(\nabla+i\*\nabla).$ Then the anti-holomorphic structure on $\bar L$ is given by $1/2(\nabla-i\*\nabla)$ and, the unitary flat connection corresponding to the holomorphic structure on $f^\* L$ is the connection $f^\* \nabla.$ But this connection is not gauge equivalent to $\nabla$ in general: For example, on a square torus with f given by $z\mapsto \bar z$ the connection $d+c idx$ is not gauge equivalent to $d+ci dy$ for $c\in R\setminus 2\pi Z.$


