I wanted to know if it is possible to construct an indecomposable self-injective finite-dimensional algebra $\Lambda$ whose Auslander-Reiten quiver $\Gamma\_\Lambda$ is not connected. I'd love to see examples as well as construction methods, if they exist, since I may later want to obtain examples satisfying further properties.



In search of disconnected indecomposable self-injective finite-dimensional algebras
Probably any example you try (that is not of finite representation type) will work. It is conjectured that the Auslander-Reiten quiver of a finite dimensional algebra $A$ is never connected, and in fact has infinitely many connected components, unless $A$ has finite representation type. See (2) and (3) in the list of conjectures at the end of


*Auslander, Maurice; Reiten, Idun; Smalø, Sverre O.*, Representation theory of Artin algebras, Cambridge Studies in Advanced Mathematics. 36. Cambridge: Cambridge University Press. xiv, 423 p. (1995). [ZBL0834.16001](https://zbmath.org/?q=an:0834.16001).


For an algebra over an uncountable field with at least a one-parameter family of indecomposables, this is obviously true for unenlightening reasons: there are uncountably many indecomposable modules, but each component of the Auslander-Reiten quiver is countable.


If you want explicit examples, Benson gives details for some group algebras ($C\_2\times C\_2$, $A\_4$ and $D\_{2^n}$ in characteristic two) in Section 4.17 of


*Benson, D.J.*, Representations and cohomology. I: Basic representation theory of finite groups and associative algebras, Cambridge Studies in Advanced Mathematics, 30. Cambridge etc.: Cambridge University Press. xi, 224 p. (1991). [ZBL0718.20001](https://zbmath.org/?q=an:0718.20001).


