I have redone this question:


On $\mathbb R^n$ the Carleson Operator if defined by
 $$Cf(x) = \sup\_{R>0} \left \vert \int\_{B\_R(0)} e^{2\pi i x\cdot \xi} \widehat{f}(\xi) d \xi \right \vert. $$ (In the previous version I had an incorrect version of this written down which lead to some stupid conclusions).


* For $n=1$ Carleson proved that this operator is strong (p,p) which is equivalent $L^p(\mathbb R)$ convergence of $S\_Rf(x)=\int\_{B\_R(0)} e^{2\pi i x\cdot \xi}\widehat{f}(\xi)d\xi\to f(x)$ as $R\to \infty$. The modern proof uses boundedness of the Hilbert-Transform and the ``translation trick''
$$\chi\_{[-r,r]}(\xi)\widehat{f}(\xi) = \widehat{[\frac{i}{2}(m\_{-r}H m\_r - m\_r H m\_{-r})f] }(\xi).$$
* For $n>1$ Fefferman proved (using a Becosivitch set) that the transform $T$ defined by $$ \widehat{Tf}(\xi) = \chi\_{B\_1(0)}(\xi) \widehat{f}(\xi)$$ is unbounded in $L^p$ for $p\neq 2$. (There is no Hilbert Transform in higher dimensions, these become the Reisz Transform and the ``translation tricks'' to express $S\_R$ in terms of the Hilbert Transform don't work).
* The Bochner-Reisz conjecture is about boundedness of smoothened characteristic functions and an MO question about it can be found here [Recent progress on Bochner-Riesz conjecture](https://mathoverflow.net/questions/56697/recent-progress-on-bochner-riesz-conjecture)


I was originally thinking that $Cf(x)$ could be defined easily for locally compact abelian groups and compact groups and that perhaps a ``translation trick'' existed in some generality. This appears to not be the case for two reasons


1. The second bullet shows that it is not true in $\mathbb{R}^n$ for $n>1$.
2. The third bullet shows you that multiplier operator in $\mathbb{R}^n$ are delicate which makes the definition of a Carleson operator for general abelian groups difficult.


Is the operator $$Cf(x) = \sup\_{n\geq 0} \left \vert \int\_{\frac{1}{p^n}\mathbb{Z}\_p} e^{2\pi i \lbrace x \xi\rbrace } \widehat{f}(\xi) d \mu(\xi) \right \vert. $$
bounded as an operator $L^r(\mathbb Q\_p) \to L^r(\mathbb Q\_p)$. (I think one can define a similar operator on the Adeles no?). How does smoothness of multipliers effect the problem in more general groups? 


I'll make it a community wiki so people can fix it if it has errors.



Carleson's Theorem (on the Adeles and other exotic groups)
There is a p-adic analogue of Carleson's theorem. This was worked out by Hunt and Taibleson and you can find an exposition in Taibleson's book "Fourier analysis on local fields". (NB Taibleson did a lot of work extending Euclidean harmonic analysis results such as Carleson's theorem and boundedness of singular integrals to local fields.) I don't know if an adelic Carleson's theorem has been worked out.


The notion of smoothness in the p-adics is different than in real spaces since the p-adics are totally disconnected. Instead of say differentiability (which can be defined at least formally), one looks at locally constant functions. For more general groups, you need to have an appropriate notion(s) of smoothness to ask how changing the smoothness affects your problem.


