Let $H$ be a cocommutative hopf algebra.
Let $M$ be the category of $H$-bimodules.
Does the category $M$ form a braided monoidal category with tensor product $\otimes\_{H}$ ?



Braided monoidal category, example
The answer is no in general.


Here is a counter example. Let us work over a ground field $k$, and let $ H = \oplus\_n k$ be the direct sum of $n$ copies of $k$, with $n \geq 2$. This is a commutative, cocommutative Hopf algebra. Of course, as others have commented, the monoidal category $({}\_H Mod\_H, \otimes\_H)$ only depends on the algebra structure of $H$.


The category of $H$-$H$-bimdoules with $\otimes\_H$ monoidal structure has a nice interpretation. An $H$-$H$-bimodule $M$ can be thought of as an $n \times n$-matrix of vector spaces. The $(i,j)$th entry of this matrix is obtained by multiplying $M$ by the $i$th minimal idempotent on one side and the $j$th minimal idempotent on the other side.


Under this identification the monoidal structure $\otimes\_H$ is easy to describe: it is "matrix multiplication", but where you replace the usual addition and multiplication operations with direct sum and tensor product of vector spaces.


However, now we see the problem emerge. For $n \geq 2$ matrix multiplication is not commutative, and it is impossible to equip $({}\_H Mod\_H, \otimes\_H)$ with a braiding.


For a concrete example we can set


$$ M = \begin{bmatrix}0 & V\\0 & 0\end{bmatrix}$$


$$ N = \begin{bmatrix}0 & 0\\0 & W\end{bmatrix}$$


Then $N \otimes\_H M = 0$, while


$$M \otimes\_H N = \begin{bmatrix}0 & V \otimes\_k W \\0 & 0\end{bmatrix}$$


There can be no isomorphism between $N \otimes\_H M$ and $M \otimes\_H N$.


