Let $M$ be a compact symplectic manifold and $H$ a time independent Hamiltonian on $M$. Let $\alpha$ be a solution to Floer's equation 


$$ u(t,s): S^1 \times \mathbb{R} \to M$$


$$(du+X\_H\otimes dt)^{0,1}=0$$ 


Suppose that at $s=\infty,$ the solution is asymptotic to some constant orbit $p$ of $X\_H$. We can then try to extend u to a map $\bar{u}$ from $\mathbb{C} \to M$ by mapping the origin $\mathfrak{o}$ to $p$. This map should be continuous. 


Question: Under what conditions on $H$ can we say anything about the regularity of this map $\mathbb{C} \to M$? It seems possible that even though the one form $dt$ doesn't extend to $\mathbb{C}$, the fact that $X\_H$ tends to zero may sometimes allow for some smooth extension with a critical point at $z=0$. 



A question about solutions to Floer's equation which are asymptotic to a stationary point
I don't have a complete answer, but the regularity of this map depends on the Hessian of $H$ at $p$.


I will see $u$ as a solution on the cylinder $\mathbb{R} \times S^1$, where $s$ is the coordinate on $\mathbb{R}$ and $t \in \mathbb{R}/\mathbb{Z}$.
You want to extend $u$ across $-\infty$ by seeing $u(s,t) = U(\operatorname{e}^{2\pi(s+it)})$ for a function $U$ on $\mathbb{C}$.
The solution $u$ has an asymptotic series expansion in terms of eigenfunctions of the asymptotic operator. In the special case that $M = \mathbb{C}^n$, $J = i$, $p = 0 \in \mathbb{C}^n$, the asymptotic operator is given by 
$A := -( i \frac{d}{dt} + D^2H(0) )$, acting on maps from $S^1 \to \mathbb{C}^n$.
(Where $D^2H(0)$ is the Hessian of $H$ at $0$.) See this as an unbounded self-adjoint operator on $L^2(S^1, \mathbb{C}^n)$. If you have an eigenvalue $\lambda$ for this operator and a corresponding eigenvector $v(t)$, then the leading order term in the asymptotic expansion for $u$ has a term $\operatorname{e}^{\lambda s} v(t)$. Now, if $U$ were $C^1$, say, it would have a Taylor expansion, notably meaning that the first order term has an integer power. In particular then, if this $0 > \lambda > -2\pi$, your map $U$ won't be $C^1$, but will instead be Hölder continuous for some exponent related to this $\lambda$. I haven't done the computations carefully, but it seems to me that if you assume that $H$ is locally $H(z\_1, \dots, z\_n) = c( |z\_1|^2 + \dots + |z\_n|^2)$, the condition on $c$ that $0$ be a non-degenerate periodic orbit precisely rules out the cases when the eigenvalues are in $2\pi \mathbb{Z}$. I suspect this is a more general phenomenon, but I don't see why at the moment. 


This type of expansion is discussed in several places. I like the exposition in Robbin-Salamon, *Asymptotic behaviour of holomorphic strips*. The improvement of the leading order term to higher order terms is done in Siefring *Relative asymptotics of pseudoholomorphic half-cylinders*. 


