Let $1\leq p<\infty$. We say that an operator $T:X\rightarrow Y$ is unconditionally $p$-converging if $T$ takes a weakly $p$-summable sequence to a norm null sequence. 


Question: Is every unconditionally $p$-converging operator $T$ from $L\_{1}[0,1]$ to every Banach space $Y$ weakly compact?


It is known that this question is false for $p=1$. But I do not know whether it is true for $1<p<\infty$.


Thank you!



Unconditionally $p$-converging operators on $L_{1}[0,1]$
No. Take a projection $P$ from $L\_1$ onto a subspace isometrically isomorphic to $\ell\_1$ and use the fact that $\ell\_1$ has the Schur property.


