Let $R$ be a reduced finite type $\bar{k}$-algebra, a projective morphism $\pi \colon V \rightarrow \mathrm{Spec}(R)$ and ideals $I, J \subseteq R$. Assume there is a split $s\_{IJ} \colon \mathrm{Spec}(R/IJ) \rightarrow V \times\_{\mathrm{Spec}(R)} \mathrm{Spec}(R/IJ)$ of $\pi$ and that the sections $s\_{J} \colon \mathrm{Spec}(R/J) \rightarrow V \times\_{\mathrm{Spec}(R)} \mathrm{Spec}(R/J)$, $s\_{I} \colon \mathrm{Spec}(R/I) \rightarrow V \times\_{\mathrm{Spec}(R)} \mathrm{Spec}(R/I)$ and $s\_{I+J} \colon \mathrm{Spec}(R/I+J) \rightarrow V \times\_{\mathrm{Spec}(R)} \mathrm{Spec}(R/I+J)$ lift to sections $\hat{s}\_{J} \colon \mathrm{Spec}(\hat{R}\_J) \rightarrow V \times\_{\mathrm{Spec}(R)} \mathrm{Spec}(\hat{R}\_J)$, $\hat{s}\_{I} \colon \mathrm{Spec}(\hat{R}\_I) \rightarrow V \times\_{\mathrm{Spec}(R)} \mathrm{Spec}(\hat{R}\_I)$ and $\hat{s}\_{I+J} \colon \mathrm{Spec}(\hat{R}\_{I+J}) \rightarrow V \times\_{\mathrm{Spec}(R)} \mathrm{Spec}(\hat{R}\_{I+J})$ on the completions. Does then $s\_{IJ}$ lift to a morphism $\hat{s}\_{IJ}$? 
Or shorter said: given a morphism such that every section over an irreducible closed affine subscheme lifts to a section on its completion, does then every section over an arbitrary closed affine subscheme lift to a section on its completion?



Lifting sections to completion of closed subschemes
No. Take $R=k[x, y]$ and $I = (x)$ and $J = (y)$. Then let $V$ be the glueing of two copies of $\text{Spec}(R)$ at $0 = (0, 0)$. Let $s\_{IJ}$ be the morphism which sends $V(I)$ into the first copy and $V(J)$ into the second. Then $\hat s\_{IJ}$ does not exist but $\hat s\_I$ and $\hat s\_J$ do (and therefore also $\hat s\_{I + J}$).


To make a positive statement you need to assume something better than just assuming that $\hat s\_{I + J}$ exists (which is automatic from the existence of either $\hat s\_I$ or $\hat s\_J$), but it seems a bit hard to say exactly what it is.


