So rank $1$ local Langlands is special in as that it is given by the Artin map
$$\text{GL}\_1(K)\to G\_K^{ab},$$
whereas in the higher rank (to the best of my knowledge) there doesn't exist a map
$$\text{GL}\_n(K)\to G\_K$$
which realizes the rank $n$ local Langlands. In fact, I think I've read that there exists a good reason that no such map can exist. I can't find a source claiming this though, so here I am.


Is there a reason that no "higher" Artin map can exist?



Non-existence of "higher" Artin map
There is no way of reformulating local Langlands for $n > 1$ in terms of such a map.


Local Langlands is a bijection between irreducible smooth representations of $\operatorname{GL}\_n(K)$, and $n$-dimensional Frobenius-semisimple Weil–Deligne representations. However, if $n > 1$ then an irreducible smooth $\operatorname{GL}\_n(K)$-rep will **almost always be infinite-dimensional**, so there's no way of getting it by composing a Galois representation with a map from $\operatorname{GL}\_n(K) \to G\_K$. (Moreover, the "irreducibility" constraint also trips you up: there are lots of $n$-dimensional Weil–Deligne reps which are not irreducible, but they still correspond to something irreducible on the $\mathrm{GL}\_n$ side, so they couldn't be given by composing a reducible representation with a map.)


