There are several well known classes of groups for which the word problem, conjugacy etc. are solvable in polynomial time (hyperbolic, automatic). 


Then there are several classes of groups like asynchronously automatic groups for which it is known that there is an exponential time algorithm to solve the word problem (and whether this can be improved to polynomial is open and conjectured as far as I'm aware).


Going several steps further, there is an algorithm to solve the word problem in one-relator groups in time not bounded by any finite tower of exponentials (and again it is open and conjectured whether this can be improved to P).


On the other, there are algorithms to solve word problems in pathological groups like the Baumslag-Gersten group:


$$G\_{(1,2)} = \langle a, b | a^{a^b}= a^2 \rangle$$


in polynomial time. So even though general algorithms can be very bad, it is unknown whether there are group-specific algorithms for every group in a given class that solve the word problem quickly.


So my question is, are there any groups in which it is known that the word problem (or any other computational problem) is at least exponential, but still solvable? Maybe exp-complete? What are the approaches to proving such a thing?



Are there any computational problems in groups that are harder than P?
An earlier reference for groups with this property is


J. Avenhaus and K. Madlener. Subrekursive Komplexität der Gruppen. I. Gruppen mit vorgeschriebenen Komplexität. Acta Infomat., 9 (1): 87-104, 1977/78.


There is a hierarchy of the recursive functions known as the (difficult to pronounce) *Grzegorczyk Hierarchy* $E\_0 \subset E\_1 \subset E\_2 \subset \cdots$, where (roughly) $E\_1$ contains the linearly bounded functions, $E\_2$ polynomially bounded functions, and $E\_3$ those functions that are bounded by iterated exponentials.


The above paper describes constructions of finitely presented groups $G\_n$ for $n \ge 3$, in which solving the word problem has time complexity bounded by a function $E\_n$ but not by any function in $E\_{n-1}$, 


