Let $K$ be an algebraically closed field with characteristic $0$ and $V$ be a Lie sub-algebra of $M\_n(K)$, the $n\times n$ matrices over $K$. If $V$ is solvable, then, according to Lie's theorem, $V$ is triangularizable. Is this result still true, in other words does Lie's theorem remain true, if $K$ has characteristic $p$ where $p>n$ ? Does there exist some reference ? 


For instance, the Jacobson's lemma, related to nilpotent matrices, is valid if $p>n$.
More generally, what do you think about the following assertion: results related to Lie algebras, that are true in characteristic $0$, are true in characteristic $p$ provided we stick to vector spaces of dimension $n<p$?
I ask the question because, very often in linear algebra papers, the underlying field is $\mathbb{C}$; yet, quite often, these results can be generalized to fields of characteristic $0$ and even of characteristic $p$. In particular, the question arises whether an algorithm written for a field with $\mathrm{char}(K)=0$ can also apply when $\mathrm{char}(K)=p>0$. In general, when I ask authors I get no clear answer.



Lie's theorem in characteristic $p$
Lie’s theorem indeed still holds in positive characteristic provided the dimension of the vector space is less than the characteristic. For reference see, for example, the remark before example $81$ in <http://math.berkeley.edu/~reb/courses/261/11.pdf>, It is indeed often the case that results being true in characteristic zero, remain true for $p$ larger than the dimension of the vector space (or larger than the Coxeter number for simple Lie algebras). On the other hand there may be many results from the modular world where we need to be careful with such a statement. The classification of simple Lie algebras from characteristic zero does not remain true for large $p$.


