The [heuristic](http://www.jstor.org/stable/2152950) from circle method for integral points on diagonal cubic surfaces $x^3+y^3+z^3=a$ ($a$ is a cubic-free integer) seems to fit well with numerical computations by [ANDREAS-STEPHAN ELSENHANS AND JORG JAHNEL](http://www.ams.org/journals/mcom/2009-78-266/S0025-5718-08-02168-6/S0025-5718-08-02168-6.pdf). The only known exception is the surface $x^3+y^3+z^3=2$. Circle method predicts that the number of integral points $(x,y,z)$ with $\max(\vert x\vert,\vert y \vert,\vert z\vert)<N$ is $\approx 0.16\log N$. But parametric solutions $(1+6t^3,1-6t^3,-6t^2)$ are missing.


**Question:** Why the heuristic fails for $x^3+y^3+z^3=2$? 



Failing of heuristics from circle method
The heuristic fails for precisely the reason you state; there is a parametric family of solutions which makes it fail.


People often use heuristic arguments to predict the number of integral/rational solutions of bounded height to diophantine equations. These heuristics are often true, provided one allows a small margin of error given by ignoring possible parametric families of solutions which make things go wrong (often called "special subvarieties"). This is exactly what is happening here. 


This philosophy is present in many conjectures and research problems in the modern study of diophantine equations, such as Manin's conjecture, the Bombieri-Lang conjecture, the André–Oort conjecture,.....


The prediction from the circle method comes here from the major arc analysis. One hopes in general that the minor arcs are smaller than the major arcs, however this is sometimes not true and in such cases it is expected that there are special subvarieties which contribute to the minor arcs and make things go wrong. I expect this is what is happening in your case.


Another example close to my heart where this happens (and closely related to your case), is the case of cubic surfaces. Take for example the Fermat cubic surface.


$$x\_0^3 + x\_1^3 = x\_2^3 + x\_3^3.$$


Here the circle method predicts that there are around $N(\log N)^3$ primitive integral solutions of bounded height. However this is wrong, as there is a parametric family of "trivial" solutions
$$x\_0=x\_2, \quad x\_1=x\_3,$$
which yields around $N^2$ solutions of bounded height.


However, once one removes these trivial solutions, plus other obvious ones, it is expected that the circle method prediction should be right. This is a special case of the [Manin conjecture](http://en.wikipedia.org/wiki/Manin_conjecture). Unfortunately one does not know this for the Fermat cubic surface, but a lower bound of the correct order of magnitude in this case is a recent nice result of [Sofos](http://arxiv.org/abs/1402.0303).


