Let $H$ be a subgroup of a finite group $G$, and let $M$ be a $G$-module. Are there any simple conditions on $H,G$ and $M$ which would ensure that the transfer map $H^p(H,M)\to H^p(G,M)$ is the zero map? In my particular situation, $M$ is a trivial $[G:H]$-torsion module, does it buy me anything?



Transfer map in group cohomology
If it's the zero map, then it's the zero map for all conjugacy classes $gHg^{-1}$ (transfer/restriction maps are "invariant under conjugation"). 


The composition of transfer map and restriction map is $z\mapsto|G:H|z$, so the transfer map can't be zero unless $H^\ast(G,M)$ is annihilated by $|G:H|$, which you shouldn't expect for general $M$. In other words, you need the *exponent* of $H^\ast(G,M)$ to divide into $|G:H|$, and in general the exponent divides into $|G|$, and not much is known from the literature besides upper bounds.


So $M=\mathbb{Z}/|G:H|\mathbb{Z}$ allows us to continue. In this case, the transfer map is trivial on the image of the restriction map, so we look for when the restriction map is surjective. This was asked here, [Conditions for the restriction $H^i(G,A)\to H^i(H,A)$ being surjective](https://mathoverflow.net/questions/95036/conditions-for-the-restriction-hig-a-to-hih-a-being-surjective/95048#95048) (to which I replied), but we have to be careful due to the assumption on $M$. For example, if $|G:H|=p$ then the restriction map can't be an isomorphism (for then $H$ would be a Sylow $p$-subgroup).


One example I know of that works: $H\hookrightarrow G:=H\times\mathbb{Z}/p\mathbb{Z}$ for any prime $p$, with $M=\mathbb{Z}/p\mathbb{Z}$.


