Is the following true?


**CONJECTURE:** $\,$ Let $\ B\ C\subseteq\mathbb R^n\ $ be convex bodies in $\mathbb R^n$ such that $\ C\ $ is centrally symmetric, $\ B\subseteq C,\ $ and $\ t\!\cdot\! B\ $ cannot be isometrically embedded in $\ C,\ $ for no $\ t>1.\ $ Then the center $c(C)$ of $C$ must belong to $B$, $\ c(C)\in B$.




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> *Thank you Douglas Z. for pointing out the mess in my earlier formulation.*
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> *Sorry for a series of additional omissions. (Now the text is complete, I hope).*
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**EDIT** (*after solutions of the original conjecture, by katz and Wlodek K)*--As Wlodek Kuperberg has observed, an additional assumption about the n-dim volume (or area in 2-dim) of $B$ and $C$:


$$ |C|\ \le\ 2\cdot|B| $$


makes the conjecture true even without the earlier assumption about enlargement of $B$ (nor about symmetry).



The center of a minimal convex superbody
Let $C$ be a $3\times 1$ rectangle centered at the origin, and $B$ a $1\times 1$ square "filling" the left side of $C$. Then $tB$ cannot be embedded in $C$ if $t>1$ but $B$ does not contain the origin, disproving the conjecture.


