For a CM elliptic curve $E$ and its Grössencharakter, their conductors are both supported on bad primes of $E$. Moreover, by comparing their functional equation, there should be some obvious relations. I think this is how to deduce the functional equation for a CM elliptic curve from the one for its Grössencharakter. 


So what's the exact relation between their conductors?


P.S. I guessed this should be easy to find, but it is not so.


P.P.S. By checking functional equations, I guess there should be a square relation. But this is not a proof.


P.P.P.S. Hey guys, I find a proof in the famous Serre-Tate [Good reduction of abelian varieties](http://wstein.org/papers/bib/Serre-Tate-Good_Reduction_of_Abelian_Varieties.pdf), theorem 12, Page 514. Indeed it is Theorem 6. And the relation should be exactly square



Conductor of a CM elliptic curve and its Grössencharacter
Here is a completely overkill explanation that nevertheless answers the question.


The question of the relation between the conductor of a CM elliptic curve and its associated Grössencharakter is related to something much stronger, namely automorphic induction.


Given a quadratic extension of number fields $E/F$ and a Hecke character $\chi$ of $E^{\times} \backslash \mathbb{A}\_E^{\times}$ such that $\chi$ does not factor through the global norm map $N\_{\mathbb{A}\_E / \mathbb{A}\_F} \colon \mathbb{A}\_E^{\times} \to \mathbb{A}\_F^{\times}$, there exists a cuspidal automorphic representation $\pi$ of $\mathrm{GL}\_2(\mathbb{A}\_F)$ that is automorphically induced from $\chi$. In particular, their $L$-functions are the same:
\[L(s,\pi) = L(s,\chi).\]
The central character of $\pi$ is given by $\omega\_{\pi} = \chi \vert\_{\mathbb{A}\_F} \omega\_{E/F}$, where $\omega\_{E/F}$ is the quadratic Hecke character of $F^{\times} \backslash \mathbb{A}\_F^{\times}$ of conductor $\mathfrak{d}\_{E/F}$, the discriminant of $E/F$, associated to the quadratic extension $E/F$ via global class field theory. In particular, if $\pi$ has trivial central character $\omega\_{\pi}$, then $\chi \vert\_{\mathbb{A}\_F} = \omega\_{E/F}$.


Via a purely local argument, one can describe the local components of $\pi$ in terms of the local components of $\chi$. In particular, if $\mathfrak{F}$ is the conductor of $\chi$ (viewed as an integral ideal of the ring of integers $\mathcal{O}\_E$ of $E$), then the conductor $\mathfrak{q}$ of $\pi$ (viewed as an integral ideal of $\mathcal{O}\_F$) is given by
\[\mathfrak{q} = \mathfrak{d}\_{E/F} N \_{E/F}(\mathfrak{F}),\]
where $N\_{E/F} \colon E^{\times} \to F^{\times}$ is the norm map. So if $\pi$ has trivial central character, then $\mathfrak{d}\_{E/F}$ divides $N \_{E/F}(\mathfrak{F})$, and consequently $\mathfrak{d}\_{E/F}^2$ divides $\mathfrak{q}$.


In the case of a CM elliptic curve, by the modularity theorem this corresponds to a cuspidal automorphic representation of $\mathrm{GL}\_2(\mathbb{A}\_{\mathbb{Q}})$ with the same conductor, so the above discussion shows the relation between the conductor of the associated Grössencharakter.


