For the projective space, we have the very well known Euler sequence
$$0 \to \Omega\_{P^n\_k} \to \mathcal{O}\_{P^n\_k}(-1)^{n+1} \to \mathcal{O}\_{P^n\_k} \to 0.$$
Are there any generalizations to other rational homogeneous spaces?



Euler Sequence on Homogeneous Spaces
Here is how it works for the (complex) Grassmannian. I will leave you the pleasure to extend this point of view to others homogeneous spaces (for instance complete and incomplete flag manifolds).


Firs of all, let me give a slightly different point of view for the Euler exact sequence on the projective space. Let $V$ be a complex vector space of dimension $n+1$ and $P(V)$ its corresponding projective space of lines. Call $\underline V=P(V)\times V$ the trivial rank $n+1$ vector bundle with fiber $V$ on $P(V)$. Then you have the short exact sequence
\begin{equation}
0\to\mathcal O(-1)\to\underline V\to H\to 0,
\end{equation}
where $\mathcal O(-1)$ is the tautological line bundle on $P(V)$ and $H$ is the quotient rank $n$ vector bundle $\underline V/\mathcal O(-1)$.


Now, looking at the differential $d\pi\_x\colon V\to T\_{P(V),[x]}$ of the projection $\pi\colon V\setminus\{0\}\to P(V)$, it is straightforward to see that it defines a canonical isomorphism
$$
T\_{P(V)}\simeq H\otimes\mathcal O(1).
$$
Tensoring the short exact sequence above by $\mathcal O(1)$ and using this canonical isomorphism you get the Euler exact sequence
$$
0\to \mathcal O\to\underline V\otimes\mathcal O(1)\to T\_{P(V)}\to 0
$$
(to get your version just notice that $\underline V\otimes\mathcal O(1)\simeq\mathcal O(1)^{\oplus(n+1)}$, then take the dual exact sequence).


Now, let $V$ be of dimension $d$ and $G\_r(V)$ be the Grassmannian of $r$-codimensional vector subspaces of $V$. Consider the tautological subbundle $S\subset \underline V=G\_r(V)\times V$ and the associated short exact sequence
$$
0\to S\to\underline V\to Q\to 0,
$$
where $Q=\underline V/S$. Similarly as before, it is straightforwardly seen that there is a canonical isomorphism
$$
T\_{G\_r(V)}\simeq S^\*\otimes Q\simeq\operatorname{Hom}(S,Q).
$$ 
Tensoring by $S^\*$, you get your Euler sequence for the Grassmannian, that is
$$
0\to S^\*\otimes S\to\underline V\otimes S^\*\to T\_{G\_r(V)}\to 0.
$$ 
Of course, it reduces to the standard one whenever $r=d-1$, and playing with the short exact sequence you can give it your favorite shape (taking duals, tensoring with other vector bundles...).


Observe finally that 
$$
\det S^\*\simeq\det Q
$$
is the (very) ample line bundle on $G\_r(V)$ which gives the Plücker embedding into projective space and whose first Chern class generates $H^2(G\_r(V),\mathbb Z)$. 


