Let $\Omega \subset \mathbb{R}^n$ be a bounded Lipschitz set, and let $W^{k,p}(\Omega)$ denote the usual Sobolev space with $k \in \mathbb{N}$ being the order of the derivatives and $p \in [1, \infty)$ the rate of integrability. I know that there exists a result of this type: fix $\varepsilon >0$, then
$$\Vert f\Vert\_{W^{k-1,p}(\Omega)} \leq \varepsilon \Vert f\Vert\_{W^{k,p}(\Omega)} + c(\varepsilon) \Vert f\Vert\_{L^1(\Omega)}$$
for any function $f \in W^{k-1,p}(\Omega)$, where the constant $c(\varepsilon)>0$ depends on $\varepsilon$ but not on $f \in W^{k-1,p}(\Omega)$.


Do you know how to prove it, or have any reference to a book/paper where I can find the proof of this result?



Interpolated Sobolev norm inequality
This can be proved by contradiction. Let $\epsilon > 0$ be given, and $(f\_j \mid j \in \mathbf{N})$ be a sequence of functions in $W^{k,p}(\Omega)$ with $\lvert f\_j \rvert\_{k-1,p} \geq \epsilon \lvert f\_j \rvert\_{k,p} + j \lvert f\_j \rvert\_{0,1}$. Rescale these functions to have $\lvert f\_j \rvert\_{k-1,p} = 1$ for all $j$. Then $\lvert f\_j \rvert\_{k,p} \leq \epsilon^{-1}$ and one can extract a subsequence that converges weakly in $W^{k,p}(\Omega)$ and strongly in $W^{k-1,p}(\Omega)$. Let $f \in W^{k,p}(\Omega)$ be their limit. At the same time $\lvert f\_j \rvert\_{0,1} \leq j^{-1}$, so that $f\_j \to 0$ in $L^1(\Omega)$. Therefore $f = 0$, but this is absurd because the convergence in $W^{k-1,p}(\Omega)$ means that $\lvert f \rvert\_{k-1,p} = 1$.


