Let $y(z) = \sum\_k y\_k z^k$ be a holomorphic function in a vicinity of the point $z=0$. Define its Borel transform $By$ as a function $By(z) = \sum\_k \frac {y\_k}{k!} z^k$.


The well-know formula allows to reconstruct $y(z)$ from $By(z)$. It is given by an application of a simple integral operator. Namely
$$y(z) = \int\_{0}^\infty e^{-t} By(tz) dt.$$


I was wondering, if it is possible to construct a similar operator realizing the Borel transform ? A functional on the space of holomorphic functions, sending $z^k \mapsto \frac 1{k!}$ does the trick. So basically, I am interested in a realization of such a functional as an integral.



An operator realizing the Borel transform
Well, your formula is essentially a Laplace transform:
$$
F(p)=\int\_0^\infty f(y) e^{-yp} dy
$$
Change variables and write $p=1/z$, assuming $p>0$, to get
$$
\frac{1}{z}F\left(\frac{1}{z}\right) = \int\_0^\infty f(t z) e^{-t} dt
$$
So you need to look up the literature on the "inverse Laplace transform".


