This is from the beginning of the first section of the paper
"Second Chern class and Riemann-Roch for vector bundles on resolutions of surfaces singularities" by J. Wahl.


$C$ is a smooth projective curve over $\mathbb{C}$. $E$ is a vector bundle of degree $e$ and rank $n$ (I believe $n$ should be at least $2$). If $E$ is semi-stable, then $h^0(E) \leq e+n$; otherwise one can find a section of $E$ vanishing at more than $\frac{e}{n}$ points, producing a line subbundle of $E$ of slope $> \frac{e}{n}$.


So I think it means that if $h^0(E) > e+n$, then there is a divisor $D$ of degree $\frac{e}{n}$ such that $h^0(E \otimes \mathcal{O}(-D)) > 0$. I don't know how to show it. It seems that Riemann-Roch is not enough.



Vanishing of a section of a vector bundle at more than e/n points
Here's a possible way to see this.


One chooses the smallest integer $d$ such that $e-nd<0$. Note that $nd \le e+n$.


Then if $D$ is effective of degree $d$, $h^0(E(-D))=0$ since $E(-D)$ is semistable with negative degree.


Since $h^0(E)\le h^0(E(-D))+nd$ (by using the exact sequence $0\to \mathcal O(-D)\to \mathcal O \to \mathcal O\_D\to 0$ tensorized by $E$), the result follows from the inequality
$nd\le e+n$ observed above.


