Let $f$ be a non-negative function defined on the unit interval. It is well known that $N(p) := \left(\int\_0^1 f^p(t) dt\right)^{\frac{1}{p}} $ converges to $\operatorname{esssup}\_{[0,1]} f$ when $p \to \infty$.


I am interested in the case when $\operatorname{esssup}\_{[0,1]} f =+\infty$ but $f \in L^p$ for all $p \in [1,\infty)$. One can show that the function $p \to N(p)$ is increasing and continuous, using the Hölder inequality.


Examples suggest to me that the growth of $N(p)$ is polynomial as $p \to \infty$ (subexpontential would suffice for me). For example, if $f(x) = \lvert\ln(x)\rvert$ then $N(p) \sim p e$, where $e$ is the Euler constant.


Of course this is hard to believe, but I was wondering if there are results/theory available about the growth of $N(p)$ as $p \to \infty$.


Any chunk of information is appreciated.



Growth of $L^p$ norms as $p \to \infty$
$N(p)$ can grow arbitrarily quickly. Given a sequence $a\_m \downarrow 0$ with $a\_0=1$ and $a\_m<a\_{m-1}/2$ for all $m$, define
$f(x)=x^{-1/m}$ for all $x \in (a\_m,a\_{m-1}]$ and $m \ge 1$. Then $N(p)<\infty$ for all $p<\infty$,
but for $p>2m$, we have
$$\int\_0^1 f^p \,dx \ge \int\_{a\_m}^{2a\_m} x^{-p/m} \ge \frac{1}{2a\_m} \,.$$


Given a function $\psi(p) \uparrow \infty$, choose $a\_m<\frac12 \psi(3m)^{-3m}$.
For $p>6$, find an integer $m \in (p/3,p/2)$ to see that
$N(p)>\psi(p)$.


