I am studying an example of symplectic Lefschetz fibrations. As far as I know, given a Weinstein manifold $F$ and a collection $V\_1,\ldots,V\_k$ of exact framed Lagrangian spheres of $F$, there exists a unique up to deformation Lefschetz fibration $f:W\rightarrow\mathbb{C}$ whose regular fiber is $F$ and whose vanishing cycles are $V\_1,\ldots,V\_k$. 


Now if we apply this fact to the case where the fiber $F$ is the plumbing of a collection of $T^\*S^n$ according to any tree $T$ and the collection $V\_1,\ldots,V\_k$ are the zero sections, then we get the corresponding Lefschetz fibration $f:W\rightarrow\mathbb{C}$.


My question is: Is it possible to write $W$ as an explicit complex affine variety (i.e. defined by some polynomials that we can write down) and $f$ as a map defined on the ambient space $\mathbb{C}^N$ (e.g. linear map)?


I have been looking at the example where our tree is $A\_k$. I know the fiber is $F=A\_k^{2n}=\{x\_1^2+\cdots+x\_n^2+t^{k+1}-1=0\}$, but I think we cannot take $f$ to be $\mathbb{C}^{n+1}\rightarrow\mathbb{C}:(\mathbf{x},t)\mapsto x\_1^2+\cdots+x\_n^2+t^{k+1}-1$ because it is not Morse. I don't know if we can perturb this polynomial so that it becomes Morse, but then will the fiber still be $A\_k$? 


Thanks in advance.



Describing a Lefschetz fibration whose fiber is plumbing of $T^*S^n$
Yes, it's possible for the specific case that you are looking at. For $k=1$, this is obvious. For $k\geq2$, such a Lefschetz fibration can be constructed by applying a standard construction to the standard Lefschetz fibration on $\mathbb{C}^{n+1}$, which is called stabilization. Concretely, a stabilization to a Lefschetz fibration $\pi$ means to replace the smooth fiber of $\pi$ by attaching a critical handle along an unknot (in this case, a standard Legendrian $S^{n-1}$ on the boundary of the unit cosphere bundle), and then adding a critical point to the base. Notice that after attaching a critical value to the $T^\ast S^n$ you get an $A\_2$ Milnor fiber since this amounts to attaching a critical handles to $D^{2n}$ along the Legendrian hopf link in $S^{2n-1}$. You can also start with the standard Lefschetz fibration on $\mathbb{C}^2$, so as to reduce the higher-dimensional stabilization construction to its original definition in four dimensions, and then viewing $\mathbb{C}^{n+1}$ as the result of a sequence of stabilizations applied to $\mathbb{C}^2$ (which means adding quadratic terms to the defining equation, which is linear, of $\mathbb{C}^2$).


In conclusion, for any $k$, there is a Lefschetz fibration on $\mathbb{C}^{n+1}$ whose fiber is symplectomorphic to the $A\_k$ Milnor fiber. It's easy to generalize the above construction to other sphere plumbings. I hope this answers your question.


