Let $X$ be a smooth projective variety, and let $E=\mathcal{O}\oplus \mathcal{O}(1)$ be a vector bundle of rank $2$. Then $L=\wedge ^{2} E $ is a line bundle on $X$. Is $L(-2)$ $\mathbb{Q}$-linear to an effective divisor?



Effectiveness of a wedged bundle
The answer is no already for $X=\mathbb{P}^1$. Indeed $c\_1(L)=c\_1(\mathcal{O}(1))$ and so $c\_1(L(-2))=c\_1(\mathcal{O}(-1))$. Therefore $L(-2)$ is linearly equivalent to the tautological bundle, which is not $\mathbb{Q}$-effective. 


