Are there other integers $n$ than even perfect numbers such that $\sigma(n)=\omega(n)n$ and $\omega(n)\vert n$?  

Thanks in advance.



Integers n such that sigma(n)=omega(n)n and omega(n) divides n
For $n=120$ we have $\omega(120)=3$ and $\sigma(120)=360=3\cdot 120=\omega(120)\cdot 120$
with $\omega(120)\mid 120$. This is not an even perfect number.


