Suppose we have $\alpha \in \mathbb{R}$. Then we know that 


$$\sum\_{1 \leq n \leq X} e(n \alpha) \ll \min \{ X, \|\alpha\|^{-1} \}$$


where $\| \cdot \|$ is the distance to the nearest integer. 
I was wondering if we put von Mangoldt function as a weight and consider the exponential sum 


$$S(\alpha) = \sum\_{1 \leq n \leq X} \Lambda(n) e(n \alpha)$$


can we obtain an estimate similar to above in terms of $\| \alpha \|$ and $X$?


Thank you very much!


PS Here $\Lambda$ is the von Mangoldt function, $e(m) = e^{2 \pi i m}$.



Exponential sum (linear in the argument) over primes
It's a classical sum going back to Vinogradov, but the estimate is more complicated. Usually, it is phrased in terms of an approximation $a/q$ of $\alpha$, with $a$ coprime to $q$, such that $|\alpha-a/q|\leq 1/q^2$ as
$$S(\alpha)\ll ((Xq)^{1/2}+Xq^{-1/2}+X^{4/5})$$
(up to powers of $\log X$). This is explained in many places, e.g. in Vaughan's "Hardy--Littlewood method" if I remember right.


