Can I simplify:


\begin{equation}
 \sum\_{x=x\_0}^{x\_1} \frac{1}{ax+b}
\end{equation}



Simplifying finite sum over 1/(ax+b)
Mathematica (or rather Wolfram Alpha) gives an answer in terms of the digamma function: [http://www.wolframalpha.com/input/?i=Sum[1%2F%28a+x%2Bb%29%2C{x%2Cx0%2Cx1}]](http://www.wolframalpha.com/input/?i=Sum[1%2F%28a%20x%2Bb%29%2C%7Bx%2Cx0%2Cx1%7D])


