Recall that an integral domain $R$ is **atomic** if every nonzero nonunit admits at least one factorization into irreducible elements. (Indeed, hard-core factorization theorists have replaced the word "irreducible" by "atom".)


From prior reading, I happen to know that there exist atomic integral domains $R$ such that the univariate polynomial ring $R[t]$ is not atomic. This is a somewhat surprising pathology, because the implication is true if both instances of "atomic" are replaced by "UFD", "Noetherian" or "Ascending Chain Condition on Principal Ideals".


But I don't know a precise example or a reference, and I would like one for an expository article I'm writing. Of course, the chronologically earlier and logically simpler the example, the better. 



Example sought of an atomic domain R such that R[t] is not atomic
According to the book "Non-Noetherian commutative ring theory" by S.T. Chapman and S. Glaz the question was first asked in "Factorization of integral domains" by D.D. Anderson, D.F. Anderson, M. Zafrullah, Journal of Pure and Applied Algebra 69 (1990) 1-19 (question 1). An answer was given [here](http://www.sciencedirect.com/science?_ob=ArticleURL&_udi=B6V0K-45FCX7K-1G&_user=10&_coverDate=07%2F02%2F1993&_rdoc=1&_fmt=high&_orig=search&_sort=d&_docanchor=&view=c&_searchStrId=1340527568&_rerunOrigin=google&_acct=C000050221&_version=1&_urlVersion=0&_userid=10&md5=349d97d14c6369afb3bb28819cfd4e90) by M. Roitman.


There it was conjectured that $R[X]$ atomic $\implies$ $R[X,Y]$ is also atomic.


