This is probably a very simple question, but I can't seem to see the answer. Given a (Zariski) closed subset $Z$ in $\mathbb P^n$ of codimension $d$, we can always find a linear subspace $L \cong \mathbb P^{d-1}$ such that $L \cap Z = \varnothing $. I'm wondering if a similar statement can be said about Grassmannians.


Specifically, let $G= \mathbb G(1,n)$ be the Grassmannian of lines in $\mathbb P^n$ with $n \geq 3$. If $Z$ is a closed subset in $G$ of codimension $2$, can we always find a $\Sigma\_{x,P} \cong \mathbb P^1$ in $G$ with $\Sigma\_{x,P} \cap Z = \varnothing $, where $\Sigma\_{x,P}$ corresponds to the locus of lines through $x$ lying in a plane $P= \mathbb P^2 \subset \mathbb P^n$ containing $x$ ?


Similarly, if $Z$ is of codimension $3$ in $G$, can we always find a $\Sigma\_P \cong \mathbb P^2$ with $\Sigma\_P \cap Z = \varnothing $, where $\Sigma\_P$ corresponds to the locus of lines lying on a plane $P= \mathbb P^2 \subset \mathbb P^n$ ? 



Subvarieties of the Grassmannian of lines
Indeed much more is true. 


Suppose $X$ is an irreducible algebraic manifold admitting a transitive action
of a linear algebraic group $G$. If $Y$ and $Z$ are irreducible subvarieties of $X$ then
for a general $g \in G$ the intersection of $gY$ (the translate of $Y$ by $g$) and $Z$
is empty or equidimensional of dimension $\mathrm{dim}(Y) + \mathrm{dim}(Z) -\mathrm{dim}(X)$.


See Kleiman's "[The transversality of a general translate](http://www.numdam.org/item?id=CM_1974__28_3_287_0)".


