Let $(\mathcal T, \otimes)$ be a tensor tringulated (tt-)category. Balmer defined a functor from the category of tt-categories to the category of locally ringed spaces, called the Balmer spectra or tt-spectra. He showed that the functor is not essentially injective if we set the target to be the category of topological spaces, but I am wondering if there is any known counter-example in our setting. In particular, when the Bamler spectra $X$ of $(\mathcal T, \otimes)$ is a qcqs scheme (or a smooth proper variety over a field if that makes a difference), is it true that we have $(\mathcal T, \otimes) \simeq (Perf X, \otimes\_{\mathcal O\_X}^{\mathbb L})$ as tt-categories? Thank you in advance.



"Essential injectivity" of Balmer spectra
No this is not true in general. In [Tensor Triangulated Categories in
Algebraic Geometry](https://www.math.uni-hamburg.de/home/sosna/diplom-online.pdf), Prop 4.0.9, Sosna shows that if X is a connected noetherian scheme then it is possible to put a tt-structure $\boxtimes$ on the derived category of $X\amalg X$ such that $Spc(D^{b}(X\amalg X),\boxtimes)\cong X$, yet $D^{b}(X\amalg X)\not\simeq D^{b}(X)$ so there cannot be an equivalence as tt-categories between $(D^{b}(X),\otimes\_{X}^{\mathbb{L}})$ and $D^{b}(X\amalg X,\boxtimes)$. This structure is just like a square zero extension for the $\otimes\_{X}^{\mathbb{L}}$ tt-structure on $D^{b}(X)$.


You need some more control on either the variety or the sort of tt-structure you want to put on the triangulated category. For example disregard spaces like $X\amalg X$ or fix some conditions on the unit.


