It is well-known in geometric analysis that one can use curve-shortening flow to prove the isoperimetric inequality (where the general result requires curve-shortening flow for non-convex curves).


I was wondering if it might be possible to also prove such an inequality using Ricci flow (given hypotheses on convexity at the boundary and total curvature constraints if necessary).



Ricci flow proof of isoperimetric inequality
Anthony Manning proved that the [volume entropy decreases under volume normalized Ricci flow on surfaces of negative curvature](https://doi.org/10.1017/S0143385703000415). Question 4 at the end of his paper asks whether the Cheeger isoperimetric constant is a strictly increasing function of Ricci flow. So it looks like this is an open question. 


There is a curious sort of [topological isoperimetric inequality in three dimensions.](https://doi.org/10.1090/S0894-0347-07-00564-4) Starting with a hyperbolic metric on an acylindrical 3-manifold with minimal boundary, one may run Ricci flow on the doubled manifold normalized by the minimum of the scalar curvature. Then this normalized volume is minimized by the hyperbolic metric with maximal area (totally geodesic) of the boundary. So the ratio of area to volume with sectional curvature at least $-1$ and minimal boundary is minimized in the totally geodesic case. 


This is proved by monotonicity formulas of Hamilton and Perelman. 
Let $\lambda(g)$ be the minimal eigenvalue of the operator 
$-4\Delta\_g + R$, where $R$ is the scalar curvature and $\Delta\_g$ is the Laplacian. Define the quantity
$$V\_{\lambda}(g) = Vol(M,g)(-\frac16 \min\{\lambda(g),0\})^{\frac32}$$
(there is a similar formula holding in any dimension). 
Then $V\_{\lambda}(g)$ is monotonically decreasing in dimension
3 for Ricci flow with surgery (the analogous quantity in dimension
2 will also be monotonic). One can actually see that
all of the normalized eigenvalues are monotonic. 
In particular, if $R(g\_0)$ is constant, then the first
eigenvalue $\lambda\_1(g\_0)$ will be determined by $R(g\_0)$
and the second eigenvalue of $-4\Delta\_g+R$. For a
surface of negative curvature, one also has monotonicity
of 
$$V\_R(g) = V(M,g) (-\frac16 \min\{R\_{min}(g),0\})^{\frac32}.$$
As $t\to \infty$, $g\_t$ will approach a constant curvature
metric, so I think this should give a relation between
the eigenvalue of the Laplacians for the initial and final
metrics. In turn, the first eigenvalue of the Laplacian is
related to the Cheeger constant by the Cheeger and Buser
inequalities. But this is probably not the sort of relation you're looking for. 


