Suppose I have the limit


$\lim\_{m\rightarrow \infty}\frac{\sum\_{k=0}^ma\_{k,m}}{\sum\_{k=0}^mb\_{k,m}}$.


When can I write this as


$\lim\_{n\rightarrow \infty}\lim\_{m\rightarrow \infty} \frac{\sum\_{k=0}^ma\_{k,n}}{\sum\_{k=0}^mb\_{k,n}}$?


To be specific, both sums converge to exponentials, which tend to zero as $n\rightarrow$. I'd like to take their ratio before letting $n$ tend to infinity.



splitting one limit into two?
The first (single) limit is totally blind to terms   $a\_{k\ n}\ \ b\_{k\ n}$   for all   $k > n$,   while the second (double) limit depends on them. Thus the two limits are hardly related at all.


In other words, the single limit considers finite segments, and the double limit the infinite segments. To compare these two there should be perhaps a relation given between the finite and infinite sums.


Also, something should be said about denominators staying reasonably away from $0$; well--something :-)


(I am surprised that the m-th sums in the single limit case have exactly m terms--I'd expect a more flexible situation).


