# How do you solve log x^2 =2?

##### 1 Answer
Oct 5, 2015

$x = \pm 10$

#### Explanation:

Assuming that's the common log, take the base 10 exponential of both sides, that is, the "sideth" power of 10.

$\log \left({x}^{2}\right) = 2$
${x}^{2} = {10}^{2}$

Take the root

$x = \pm 10$

Since ${x}^{2}$ is positive for all values of $x$ the only value of $x$ we can't have is $0$, so both answers are okay.