What is the optimal value function of the scaled version of the reward function?

Consider the reward function $$r(s, a)$$ with optimal state-action value function $$q_*(s, a)$$. What would be the optimal state-action value function of $$c r(s, a)$$, for $$c \in \mathbb{R}$$? Would it be $$c q_*(s, a)$$?

The Bellman optimality equation is given by

$$q_*(s,a) = \sum_{s' \in \mathcal{S}, r \in \mathcal{R}}p(s',r \mid s,a)(r + \gamma \max_{a'\in\mathcal{A}(s')}q_*(s',a')) \tag{1}\label{1}.$$

If the reward is multiplied by a constant $$c > 0 \in \mathbb{R}$$, then the new optimal action-value function is given by $$cq_*(s, a)$$.

To prove this, we just need to show that equation \ref{1} holds when the reward is $$cr$$ and the action-value is $$c q_*(s, a)$$.

\begin{align} c q_*(s,a) &= \sum_{s' \in \mathcal{S}, r \in \mathcal{R}}p(s',r \mid s,a)(c r + \gamma \max_{a'\in\mathcal{A}(s')} c q_*(s',a')) \tag{2}\label{2} \end{align}

Given that $$c > 0$$, then $$\max_{a'\in\mathcal{A}(s')} c q_*(s',a') = c\max_{a'\in\mathcal{A}(s')}q_*(s',a')$$, so $$c$$ can be taken out of the $$\operatorname{max}$$ operator. Therefore, the equation \ref{2} becomes

\begin{align} c q_*(s,a) &= \sum_{s' \in \mathcal{S}, r \in \mathcal{R}}p(s',r \mid s,a)(c r + \gamma c \max_{a'\in\mathcal{A}(s')} q_*(s',a')) \\ &= \sum_{s' \in \mathcal{S}, r \in \mathcal{R}}c p(s',r \mid s,a)(r + \gamma \max_{a'\in\mathcal{A}(s')} q_*(s',a')) \\ &= c \sum_{s' \in \mathcal{S}, r \in \mathcal{R}} p(s',r \mid s,a)(r + \gamma \max_{a'\in\mathcal{A}(s')} q_*(s',a')) \\ q_*(s,a) &= \sum_{s' \in \mathcal{S}, r \in \mathcal{R}} p(s',r \mid s,a)(r + \gamma \max_{a'\in\mathcal{A}(s')} q_*(s',a')) \tag{3}\label{3} \end{align} which is equal to the the Bellman optimality in \ref{1}, which implies that, when the reward is given by $$cr$$, $$c q_*(s,a)$$ is the solution to the Bellman optimality equation. Consequently, in this case, the set of optimal policies does not change.

If $$c=0$$, then \ref{2} becomes $$0=0$$, which is true.

If $$c < 0$$, then $$\max_{a'\in\mathcal{A}(s')} c q_*(s',a') = c\min_{a'\in\mathcal{A}(s')}q_*(s',a')$$, so equation \ref{3} becomes

\begin{align} q_*(s,a) &= \sum_{s' \in \mathcal{S}, r \in \mathcal{R}} p(s',r \mid s,a)(r + \gamma \min_{a'\in\mathcal{A}(s')} q_*(s',a')) \end{align}

which is not equal to the Bellman optimality equation in \ref{1}.