# Slips System of BCC

We have been taught that there are 48 slip Systems in BCC. I need the miller indices of each slip plane and direction.

Out of 48 I got miller indices of 12 systems of $$\{110\}\ \left<111\right>$$ and 12 systems of $$\{112\}\ \left<111\right>$$ , but I am not getting remaining 24 slip Systems of $$\{123\}\ \left<111\right>$$.

I don't know how to find all 24 planes of $$\{123\}$$ family of planes.If anyone know how to do it, it will be helpful

• This is simple enumeration of the possibilities. There are more because there are no repeats of indices that are equivalent. – Jon Custer Apr 16 '16 at 15:40

How to find all 24 planes of $$\{123\}$$ family of planes?
For any of the $$\left<111\right>$$ directions, we have $$3!$$ i.e. $$6$$ $$\{123\}$$ slip planes. And we have $$4$$ $$\left<111\right>$$ slip directions for each plane. So in total $$6\times 4 = 24$$ slip systems.