# How do you find the slope that is perpendicular to the line 7x-6y=13?

May 14, 2017

$- \frac{6}{7}$

#### Explanation:

First of all solve for $y$

$7 x - 6 y = 13 \implies - 6 y = 13 - 7 x$

$y = \frac{13 - 7 x}{-} 6 = - \frac{13}{6} + \frac{7 x}{6}$

$\textcolor{red}{y = \frac{\textcolor{b l u e}{7}}{\textcolor{g r e e n}{6}} x - \frac{13}{6}}$

If the line is perpendicular to this line then its slope will be the negative reciprocal of the slope of is line

So the slope is $\textcolor{red}{-} \frac{\textcolor{g r e e n}{6}}{\textcolor{b l u e}{7}}$