East of this agonic line, the magnetic North Pole is to the west of the geographic North Pole and a correction must be applied to a compass indication to get a true direction. A dip circle is taken to geomagnetic equator. Then the angle of dip is (a) 0° (b) 30° (c) 45° (d) 90° A magnetic field B is applied perpendicular to the plane of the sample. The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be 2 sec. The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be 2 seconds. The time period of vibration is found to be 2 seconds. An electron with charge -e and mass m travels at a speed v in a plane perpendicular to a magnetic field of magnitude B. For a vertical plane other than magnetic meridian $\alpha>0$ or $\cos \alpha<1$ so $\theta^{\prime}>\theta$ In a vertical plane other than magnetic meridian angle of dip is more than in magnetic meridian. When the plane of the coil is normal to the magnetic meridian, a neutral point is observed at the centre of the coil. A voltage measured perpendicular to the plane is indicative of the CME of hot electrons. Real dip theta=40.9^@ Let the vertical component of earth's magnetic field be V and its horizontal component at magnetic meridian be H. Then the angle of dip theta at magnetic meridian will be given by tantheta=V/H.....[1] When the dip needle is suspended at an angle of 30^@ to the earth magnetic meridian then it makes an angle 45^@ with the horizontal. The electron follows a circular path of radius R. In a time, t, the electron travels halfway around the circle. Illustration of a thin-film CME measurement geometry in the presence of a strong in-plane electric field (E). Click hereto get an answer to your question ️ A vertical circular coil of radius 0.1 m and having 10 turns carries a steady current. The needle is allowed to move in a vertical plane perpendicular to the magnetic meridian. A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 22° with the horizontal. The horizontal component of the earth’s magnetic field at the place is known to be 0.35 G. Determine the magnitude of the earth’s magnetic field at … Textbook Solutions 6926. Maharashtra State Board HSC Science (Electronics) 11th. Here the needle and vertical scale are in a plane perpendicular to the magnetic meridian. Important Solutions 17 ... perpendicular to the magnetic axis of Earth. This sets the needle and vertical scale exactly in magnetic meridian. The time period of vibration is found to be 2 sec. Magnetic meridian is the plane . The needle will stay (a) in horizontal direction only (b) in vertical direction only (c) in any direction except vertical and horizontal (d) in the direction it is released To get the true heading, you need to first read the magnetic compass, then either add an Easterly, or subtract a Westerly, magnetic variation; based on the isogonic lines. If BH = 0.314 × 10^-4 T , the current in the coil is : Reuse & Permissions × Another magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at with the horizontal . Then the angle of dip is The box is then rotated through 90 o position on the horizontal circular scale. A magnetic field is directed perpendicular to the plane of a circular coil of area 0.2 m² and 250 turns. The magnitude of the horizontal component of the earth ' magnetic field at the place is known to be . A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. 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