OpenStudy (anonymous):

A rancher has 200 ft of fencing to enclose two adjacent rectangular corrals and run a strip of fencing down between them to separate the corrals. What dimensions should be used so that the inclosed area will be a maximum?

OpenStudy (anonymous):

@Hero or @lgbasallote

OpenStudy (anonymous):

guess and check?

OpenStudy (anonymous):

this is what ive got... $P=2x+2y~~~~~~~~~~~~~~A=xy$$200=2y+3x~~~~~~\implies~~~~~~y=100-{3\over2}~x~~~~~~and~~~~~~x={200\over3}~-{2\over3}~y$$A=\left(100-{3\over2}~x\right)\times\ x$ $\implies~~~~*plug~into~graphing~calculator~and~find~maximum~y-value*$$Max~Area~is~~ 1666~{2\over3}~ft~~~~~~\implies~~~~~~dimensions~are~~x=33{1\over3}~~and~~y=50{$

OpenStudy (anonymous):

$Max~Area~is~~ 1666~{2\over3}~ft~~~~~~\implies~~~~~~dimensions~are~~x=33{1\over3}~~and~~y=50$

OpenStudy (anonymous):

♥ I ROCK ^_^ ♥

OpenStudy (anonymous):

no you see there are 3 x's

OpenStudy (anonymous):

|dw:1351119771929:dw|

OpenStudy (anonymous):

|dw:1351119807736:dw|theres a STRIP GOING DOWN THE MIDDLE which is included in the fencing....so that added equals 200