## Algebra 1

$(w^{3}+6w)(3w-2)$
$3w^{4}=3.w.w.w.w$ and $2w^{3}=2.w.w.w$ Hence, $GCF=$$w.w.w=w^{3} 18w^{2}=2.3.3.w.w and 12w=2.2.3.w Hence, GCF=$$2.3.w=6w$ After grouping : $=(3w^{4}-2w^{3})+(18w^{2}-12w)$ $=w^{3}(3w-2)+6w(3w-2)$ $=(w^{3}+6w)(3w-2)$ $=(w)(w^{2}+6)(3w-2)$