1. ## Simultaneous Equation Help Please!

y=2x+3
x²+y²=2

i get

x²+(2x+3)=2 then,
x²+(2x+3)(2x+3)=2 then,
x²+4x²+12x+9=2

Then im stuck i realise it's a quadratic equation (4x²+12x+9) but i don't know where to go from here.

Help greatly appreciated x

2. Hello,

(4x²+12x+9)

this is equal to:

(2x)²+2*3*2x+3²

If a=2x and b=3

You have a²+2ab+b², which is (a+b)²

3. Move everything to one side:

$5x^{2} + 12x + 7 = 0$

Factor and see what you get

4. thanks