# Math Expressions Grade 5 Unit 1 Lesson 10 Answer Key Practice with Unlike Mixed Numbers

## Math Expressions Common Core Grade 5 Unit 1 Lesson 10 Answer Key Practice with Unlike Mixed Numbers

Math Expressions Grade 5 Unit 1 Lesson 10 Homework

Lesson 10 Practice with Unlike Mixed Numbers Math Expressions Grade 5 Unit 1 Question 1.

Explanation:
Perform Subtraction operation on 3 and the mixed number 1(2/5). First multiply 5 with 1 the product is 5. Add 5 with 2 the sum is 7. The mixed number 1(2/5) in fraction form as (7/5). Subtract (7/5) from 3 then the difference is (8/5). The fraction (8/5) can be written as the mixed number 1(3/5).

Practice with Unlike Mixed Numbers Math Expressions Grade 5 Unit 1 Lesson 10 Question 2.

Explanation:
Perform Addition operation on these two mixed numbers 2(7/10) and 2(4/5). First multiply 10 with 2 the product is 20. Add 20 with 7 the sum is 27. The mixed number 2(7/10) in fraction form as (27/10). Next multiply 5 with 2 the product is 10. Add 10 with 4 the sum is 14. The mixed number 2(4/5) in fraction form as (14/5). Add (27/10) with (14/5) then the sum is (55/10). The fraction (55/10) can be written as the mixed number 5(5/10).

Math Expressions Grade 5 Unit 1 Lesson 10 Answer Key Practice with Unlike Mixed Numbers Question 3.

Explanation:
Perform Subtraction operation on these two mixed numbers 7(5/9) and 3(2/15). First multiply 9 with 7 the product is 63. Add 63 with 5 the sum is 68. The mixed number 7(5/9) in fraction form as (68/9). Next multiply 15 with 3 the product is 45. Add 45 with 2 the sum is 47. The mixed number 3(2/15) in fraction form as (47/15).  Subtract (47/15) from (68/9) then the difference is (199/45). The fraction (199/45) can be written as the mixed number 4(19/45).

Question 4.

Explanation:
Perform Addition operation on these two mixed numbers 4(5/6) and (6/7). First multiply 6 with 4 the product is 24. Add 24 with 5 the sum is 29. The mixed number 4(5/6) in fraction form as (29/6). Add (29/6) with (6/7) then the sum is (239/42). The fraction (239/42) can be written as the mixed number 5(29/42).

Question 5.

Explanation:
Perform Subtraction operation on these two mixed numbers 5(1/8) and 4(1/5). First multiply 8 with 5 the product is 40. Add 40 with 1 the sum is 41. The mixed number 5(1/8) in fraction form as (41/8). Next multiply 5 with 4 the product is 20. Add 20 with 1 the sum is 21. The mixed number 4(1/5) in fraction form as (21/5). Subtract (21/5) from (41/8) then the difference is (37/40).

Question 6.

Explanation:
Perform Addition operation on these two mixed numbers 4(79/100) and 5(9/10). First multiply 100 with 4 the product is 400. Add 400 with 79 the sum is 479. The mixed number 4(79/100) in fraction form as (479/100). Next multiply 10 with 5 the product is 50. Add 50 with 9 the sum is 59. The mixed number 5(9/10) in fraction form as (59/10).  Add (479/100) with (59/10) then the sum is (1069/100). The fraction (1069/100) can be written as the mixed number 10(69/100).

Question 7.

Explanation:
Perform Addition operation on these two fractions (13/16) and (2/3). Add (13/16) with (2/3) then the sum is (71/48).

Question 8.

Explanation:
Perform Subtraction operation on these two mixed numbers 8(1/4) and 3(9/20). First multiply 4 with 8 the product is 32. Add 32 with 1 the sum is 33. The mixed number 8(1/4) in fraction form as (33/4). Next multiply 20 with 3 the product is 60. Add 60 with 9 the sum is 69. The mixed number 3(9/20) in fraction form as (69/20).  Subtract (69/20) from (33/4) then the difference is (96/20). The fraction (96/20) can be written as the mixed number 4(16/20).

Question 9.

Explanation:
Perform Addition operation on these two mixed numbers 7(8/9) and 9(7/8). First multiply 9 with 7 the product is 63. Add 63 with 8 the sum is 71. The mixed number 7(8/9) in fraction form as (71/9). Next multiply 8 with 9 the product is 72. Add 72 with 7 the sum is 79. The mixed number 9(7/8) in fraction form as (79/8).  Add (71/9) with (79/8) then the sum is (1279/72). The fraction (1279/72) can be written as the mixed number 17(55/72).

Solve.

Question 10.
The Taylors have four dogs. Molly eats 4$$\frac{1}{2}$$ cups of food each day, Roscoe eats 3$$\frac{2}{3}$$ cups, Milo eats 1$$\frac{3}{4}$$ cups, and Fifi eats cup. How much do the Taylors’ dogs eat each day altogether?
Molly eats 4(1/2) cups of food each day.
4(1/2) = (9/2)
Roscoe eats 3(2/3) cups.
3(2/3) = (11/3)
Milo eats 1(3/4) cups.
1(3/4) = (7/4)
Fifi eats 1 cup.
(9/2) + (11/3) + (7/4) + 1 = (131/12)
The Taylors’ dogs eat each day altogether (131/12).
Explanation:
Molly eats 4(1/2) cups of food each day, Roscoe eats 3(2/3) cups, Milo eats 1(3/4) cups and Fifi eats 1 cup. Add (9/2) with (11/3), (7/4) and 1 then the sum is (131/12). The Taylors’ dogs eat each day altogether (131/12).

Question 11.
Refer to Problem 10. How much more food does Molly eat each day than Roscoe?
Molly eats each day (9/2) cups of food.
Roscoe eats each day (11/3) cups of food.
(9/2) – (11/3) = (5/6)
Molly eats (5/6) cups of food each day than Roscoe.
Explanation:
Molly eats each day (9/2) cups of food. Roscoe eats each day (11/3) cups of food. Subtract (11/3) from (9/2) then the difference is (5/6). Molly eats (5/6) cups of food each day than Roscoe.

Question 12.
The vet told the Taylors (from Problem 10) to decrease the amount Molly eats by $$\frac{3}{4}$$ cup. After Molly’s food is adjusted, will she eat more or less than Roscoe each day? How much more or less?
(9/2) – (3/4) = (15/4)
After Molly’s food is adjusted Molly eats (15/4) cups of food.
Roscoe eats each day (11/3) cups of food.
(15/4) – (11/3) = (1/12)
Molly eats (1/12) cup more than Roscoe.
Explanation:
If we calculate the difference between Molly’s daily food and Roscoe’s daily food[(15/4) – (11/3) = (1/12)].
After decreasing the amount of food Molly eats per day, still Molly eats (1/12) cup more than Roscoe.

Math Expressions Grade 5 Unit 1 Lesson 10 Remembering

What mixed number is shown by each shaded part ?

Question 1.

_______
2(3/4)
The mixed number for the above shaded parts are 2(3/4).
Explanation:
In the above image we can observe three objects. In that two objects are completely shaded and one object is not completely shaded. So the mixed number for the above shaded parts are 2(3/4).

Question 2.

_______
1(1/2)
The mixed number for the above shaded parts are 1(1/2).
Explanation:
In the above image we can observe two objects. In that one object is completely shaded and one object is not completely shaded. So the mixed number for the above shaded parts is 1(1/2).

Question 3.

_______
3(1/3)
The mixed number for the above shaded parts is 3(1/3).
Explanation:
In the above image we can observe three objects. In that two objects are completely shaded and one object is not completely shaded. So the mixed number for the above shaded parts is 3(1/3).

Question 4.
How many cookies are there altogether? _____
In the above bar graph we can observe cookies. There are three cookies altogether. one is chocolate chip, second one is oatmeal, third one is peanut butter.

Question 5.
What fraction of the cookies are chocolate chip? _____
(20/(20+15+10) = (20/45) = (4/9)
The fraction (4/9)of the cookies are chocolate chips.
Explanation:
In the above bar graph we can observe three cookies. The chocolate chip is at 20 number. Add 20 with 15 and 10 then the sum is 45. (20/45) can be simplified as (4/9). (4/9) is the fraction of cookies that are chocolate chips.

Question 6.
What fraction of the cookies are oatmeal? _____
(15/(20+15+10) = (15/45) = (3/9)
The fraction (3/9) of the cookies are peanut butter.
Explanation:
In the above bar graph we can observe three cookies. The oatmeal is at the number 15. Add 20 with 15 and 10 then the sum is 45. (15/45) can be simplified as (3/9). (3/9) is the fraction of cookies that are oatmeal.

Question 7.
What fraction of the cookies are peanut butter? _____
(10/(20+15+10) = (10/45) = (2/9)
The fraction (2/9) of the cookies are peanut butter.
Explanation:
In the above bar graph we can observe three cookies. The peanut butter is at the number 10. Add 20 with 15 and 10 then the sum is 45. (10/45) can be simplified as (2/9). (2/9) is the fraction of cookies that are peanut butter.

Question 8.
Melanie baked 25 cookies. Did she bake more or less than half of the cookies? ____
How do you know?

Question 9.
Stretch Your Thinking Colby nailed together four wood boards as shown at the right. All four boards are 5$$\frac{1}{2}$$ inches wide.

a. Find the perimeter of the outside rectangle.
Perimeter of the rectangle is equal to 2(length + breadth).
Here length = 24(3/4) inches.
Length = (99/4) inches.
Breadth = 5(1/2) + 8(1/4) + 5(1/2)
Breadth = (11/2) + (33/4) + (11/2)
Perimeter of the outside rectangle = 2(length + breadth) = 2[(99/4) + (77/4)] = 2[(176/4)] = 88
Perimeter of the outside rectangle = 88 inches.
Explanation:
In the above image we can observe that length is equal to 24(3/4) inches. The fraction form of 24(3/4) is (99/4) inches. Breadth is equal to 5(1/2), 8(1/4), and 5(1/2). The fraction form is (11/2), (33/4), (11/2). Add (11/2) with (33/4) and (11/2) then the sum is (77/4) inches. We know that perimeter of the rectangle is equal to 2(length + breadth). Add length and breadth then the sum is 2(176/4) which is equal to 88 inches. Perimeter of the outside rectangle = 88 inches.

b. Find the perimeter of the inside rectangle.