Chapter 12 - Rotation of a Rigid Body - Exercises and Problems - Page 349: 20

$\tau_{net} = -0.94~N~m$

Work Step by Step

We can find the net torque about the axle as: $\tau_{net} = \sum \tau$ $\tau_{net} = (r_1\times F_1) + (r_2\times F_2)+(r_3\times F_3)+(r_4\times F_4)$ $\tau_{net} = -(0.10~m)(30~N)+(0.05~m)(30~N)~sin(45^{\circ})+(0.05~m)(20~N)+(0.05~m)(20~N)~sin(0^{\circ})$ $\tau_{net} = -0.94~N~m$

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