A charge of -2 C is at (-2 , 3 ) and a charge of -1 C is at (8,-2 ) . If both coordinates are in meters, what is the force between the charges?

May 19, 2016

$F = 1.44 \cdot {10}^{8} N$

Explanation:

$\text{ distance between "Q_1 " and "Q_1 } : r = \sqrt{{\left(- 2 - 3\right)}^{2} + {\left(8 + 2\right)}^{2}}$

$r = \sqrt{{\left(- 5\right)}^{2} + {10}^{2}} \text{ "r=sqrt(25+100)" "r=sqrt(125)" } {r}^{2} = 125$

$F = k \cdot \frac{{Q}_{1} \cdot {Q}_{2}}{r} ^ 2$

$F = 9 \cdot {10}^{9} \frac{\left(- 2\right) \cdot \left(- 1\right)}{125}$

$F = \frac{18 \cdot {10}^{9}}{125}$

$F = 1.44 \cdot {10}^{8} N$