# How do you find domain and range for y=sqrt(x- 2)?

The domain is $x \ge 2$ or $D \left(f\right) = \left[2 , + \infty\right)$ and the range is
$y = \sqrt{x - 2} \ge 0 \implies y \ge 0$ or $R \left(f\right) = \left[0 , + \infty\right)$