## Essential University Physics: Volume 1 (4th Edition)

We know that $Q=mc\Delta T$ We plug in the known values to obtain: $Q=(0.330)(4184)(100-10)$ $Q=124300J$ Now we can find the time as $t=\frac{Q}{P}$ $t=\frac{124300}{900}$ $t=140s = 2.3 min$