## Intermediate Algebra (12th Edition)

$18k^4+12k^3+6k^2$
Using $a(b+c)=ab+ac$ or the Distributive Property, the product of the given expression, $6k^2(3k^2+2k+1) ,$ is \begin{array}{l}\require{cancel} 6k^2(3k^2)+6k^2(2k)+6k^2(1) \\\\= 18k^4+12k^3+6k^2 .\end{array}