1. waterineyes

Firstly, $\huge x^{-\frac{a}{b}} \implies \sqrt[b]{x^{-a}}$ and: $\huge x^{-a} = \frac{1}{x^a}$

So I have to find the radical first then, place it in a form without the negative exponent?

3. waterineyes

Yep...

4. waterineyes

Or you can leave it in negative form in the radical also, there is no harm..

6. waterineyes

You tell me first, I will check it for you..

Is it $\frac{ 1 }{ \sqrt[5]{9} }$

8. waterineyes

Oh sorry, YES IT IS RIGHT..