# Question 0297a

Jan 9, 2017

${\text{Molarity"="0.4 mol"*"L}}^{-} 1$

#### Explanation:

$\text{Molarity"="Moles of solute"/"Volume of solution}$

=(2*"mol")/(0.500*"L")=0.4*"mol"*"L"^-1#.

So two questions for you:

(i) What is the concentration in ${\text{g"*"L}}^{-} 1$?

(ii) What are (i) the $\text{pOH}$, and (ii) the $\text{pH}$ of this solution?