###### Question

Which reaction has a minimum increase in the rate of reaction for a 10^@ increase in temperature?

• Backward Reaction
• Forward Reaction
###### Solution

We know:
k = Ae^(-E/(RT)) where E is energy of activation.

This can be written as ln k = ln A - (E/(RT))

lnk_2-lnk_1=E/R(1/T_1-1/(T_1+10))

E_("forward")>E_("backward")

E_("forward")/R(1/T_1-1/(T_1+10))>E_("backward")/R(1/T_1-1/(T_1+10))

lnk_("forward 2")-lnk_("forward 1") > lnk_("backward 2")-lnk_("backward 1")

Thus, rate constant of backward reaction increases less than rate constant of forward reaction. Hence, answer is backward reaction.