Q

# Solve it, - Chemical Bonding and molecular structure - NEET

The hybridization involved in complex $\left [ Ni \left ( CN \right )_{4} \right ]^{2-}$is.(At.No.Ni=28)

• Option 1)

$dsp^{2}$

• Option 2)

$sp^{3}$

• Option 3)

$d^{2}sp^{2}$

• Option 4)

$d^{2}sp^{3}$

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As we learnt in

Hybridisation -

The process of mixing of atomic orbitals belonging to the same atoms of slightly different energies so that a redistribution of energy takes place between them  resulting in the formation of new set of orbital of equivalent energies and shape is called hybridisation.

- wherein

The new orbitals thus formed are called hybrid orbitals

In $\left [ Ni(CN) _{4}\right ]^{2-}, N\:is\:in +2\ O.S.$

$Ni^{2+}:\left [ A_{r} \right ]3d^{8}48^0$

or we could write

Since, CN- is a strong field ligand, so the electrons will pair up and hybridisation will be dsp2

Option 1)

$dsp^{2}$

This solution is correct

Option 2)

$sp^{3}$

This solution is incorrect

Option 3)

$d^{2}sp^{2}$

This solution is incorrect

Option 4)

$d^{2}sp^{3}$

This solution is incorrect

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