## College Algebra (10th Edition)

$y=\frac{2}{3}x+8$
We find a line with a slope of $2/3$ that passes through $(-6,4)$ using the point-slope form: $y-y_{1}=m(x-x_{1})$ $y-4=\displaystyle \frac{2}{3}(x- -6)$ $y-4=\displaystyle \frac{2}{3}(x+6)$ $y-4=\frac{2}{3}x+4$ $y=\frac{2}{3}x+8$