# Find the equations of the lines, which cut-off intercepts on the axes whose sum and product are 1 and – 6, respectively

$\begin {array} {1 1} (A)\;2x-3y+6=0\: and \: 3x-2y-6=0 & \quad (B)\;2x+3y-6=0 \: and \: 3x+2y+6=0 \\ (C)\;2x-3y-6=0 \: and \: 3x-2y+6=0 & \quad (D)\;2x-3y-6=0 \: and \: 3x-2y-6=0 \end {array}$

• Equation of a line whose intercepts $a$ and $b$ cuts the $x$ and $y$ axis respectively is $\large\frac{x}{a}$$+\large\frac{y}{b}$$=1$
Given that $a+b=1 \: and \: ab=-6 \Rightarrow b =-\large\frac{6}{a}$
let us solve for $a$ and $b$