## College Algebra (10th Edition)

$(x+1)^2+(y+2)^2=1$
RECALL: The standard form of a circle's equation is given as: $(x-h)^2+(y-k)^2=r^2$ where $r$ = radius and $(h, k)$ is the center. Thus, a circle with center at $(-1, -2)$ and $r=1$ has the equation: $[(x-(-1)]^2+[y-(-2)]^2=1^2 \\(x+1)^2+(y+2)^2=1$