# How do you find 2p^2 + 3p - 4 less - 2p^2 - 3p + 4?

Jun 10, 2015

$2 {p}^{2} + 3 p - 4$ less $- 2 {p}^{2} - 3 p + 4$ is
$2 \left(2 {p}^{2} + 3 p - 4\right)$.
The expression you wrote means $2 {p}^{2} + 3 p - 4 - \left(- 2 {p}^{2} - 3 p + 4\right) =$
$2 {p}^{2} + 3 p - 4 + 2 {p}^{2} + 3 p - 4 =$
$4 {p}^{2} + 6 p - 8 =$
$2 \left(2 {p}^{2} + 3 p - 4\right)$.