# The ratio of modulus of rigidity to young’s modulus is 0.40. What will be the Poisson’s ratio?

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The ratio of modulus of rigidity to young’s modulus is 0.40. What will be the Poisson’s ratio?
1. 0.55
2. 0.45
3. 0.25
4. 0.35

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Correct Answer - Option 3 : 0.25

Concept:

Relation between modulus of rigidity (G), young’s modulus (E) & Poisson’s ratio (μ) is

E=2G(1+μ)

Calculation:

Given:

$\frac {{G}}{{E}}$ = 0.4

E = 2G (1 + μ)

$\frac {{E}}{{G}}$ = 2 (1 + μ)

$\frac {{1}}{{0.4}}$ = 2 (1 + μ)

1.25 = 1 + μ

μ = 0.25

Other relations between elastic constants

E = $\frac {{9KG}}{{3K+G}}$

E = 3K (1 - 2μ)