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## lirffej Group Title from a quartic equation with rational coefficients having 3-sq.root of 2 and 1+2 sq.root of 2 as roots..plzz..help one year ago one year ago

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1. Vinayak_G_P

Since you have to roots, you can write the equation as $(x-(3-\sqrt{2}))*(x-(1+2\sqrt{2}) = 0$ Multiplying the terms $x^2 - x * (1+2\sqrt{2}) - x * (3-\sqrt{2}) - ((3-\sqrt{2})*(1+2\sqrt{2})) = 0$ Simplify the terms and you have your answer.