## Area of the region

Find the area of the region inside the circle

$$r=24 cos \theta$$ and to the right of the vertical line $$r=6 sec \theta$$

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• R=24 cos theta
R=6 sec theta
24 cos theta =6 sec theta
cos theta=1/2
theta=60 degree
Hence using this put in formula

A = ? [b,a] (1/2)((r_1)^2 - (r_2)^2) dx