-2(x-5)-(16-x)=4(2x-1)+7

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Solution for -2(x-5)-(16-x)=4(2x-1)+7 equation:

-2(x-5)-(16-x)=4(2x-1)+7
We move all terms to the left:
-2(x-5)-(16-x)-(4(2x-1)+7)=0
We add all the numbers together, and all the variables
-2(x-5)-(-1x+16)-(4(2x-1)+7)=0
We multiply parentheses
-2x-(-1x+16)-(4(2x-1)+7)+10=0
We get rid of parentheses
-2x+1x-(4(2x-1)+7)-16+10=0

We calculate terms in parentheses: -(4(2x-1)+7), so:
4(2x-1)+7
We multiply parentheses
8x-4+7
We add all the numbers together, and all the variables
8x+3
Back to the equation:
-(8x+3)

We add all the numbers together, and all the variables
-1x-(8x+3)-6=0
We get rid of parentheses
-1x-8x-3-6=0
We add all the numbers together, and all the variables
-9x-9=0
We move all terms containing x to the left, all other terms to the right
-9x=9
x=9/-9
x=-1

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