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# Algebra Homework Help

Algebra is the branch of mathematics that concerns with the study of the rules  of operations and relations. Are you struggling hard with homework? Solve all problems with the help of TutorVista’s qualified tutors. Homework is no more a headache as our online tutors help you to understand and solve all problems promptly. TutorVista's Algebra Homework help service is very easy to use. Just upload your Algebra Homework on our website.

Our tutors will work on the problems and e-mail it to you with detailed step by step explanations Solve your Math problems as online tutoring is considered as an effective way of learning and teaching. TutorVista provides a convenient and efficient way for students to get the help they need with Math.

Listed below are topics that are covered within this study by our expert tutors:

• Framing of Formulas
• Expansions
• Indices
• Linear Equations
• Factorization and

 Related Calculators Algebra Help Calculator Algebra Help Equation Calculator Math Help Calculator Algebra Division

## Pre Algebra Homework Help

Get pre algebra homework help with TutorVista where the mutual interaction  between a teacher and a student is consistent. Besides help with homework, we also provide one-on-one tutoring. The online tutoring service offered is convenient and prompt, any assistance related to math is just a click away. TutorVista is an online math problem solver, where you can get help with a specific mathematics problem. Students can also connect with a tutor before an important test or exam and get direct help. There is also an extensive library of e- learning material like Algebra question banks, simulations and Algebra animations available to help the student ace the subject. TutorVista takes pride in having highly qualified and well experienced online tutors. Feel free to take their help and meet your goals.

Three easy steps to get an expert now:

Step 1: Register with us for an online tutoring program.

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## Intermediate Algebra Homework Help

Need Intermediate Algebra help? TutorVista offers a complete Intermediate Algebra Homework help featuring online tutoring with a personal math tutor. Intermediate Math problems can be challenging, especially when you are trying to get your way around real numbers, equations and inequalities, polynomials, system of equation etc. Free Intermediate Algebra questions and problems are presented along with answers and explanations from TutorVista.

Free worksheets can be downloaded which acts as the best way to try and solve various challenging problems.

### Solved Example

Question: One number is 12 more than another number. The sum of the smaller  number is more than two times the larger number which is 30. What are the two numbers?
Solution:
Let x be the smaller number.

Then, the larger number is 12 more = x + 12

The problem states,

x + 2(x + 12) = 30

=> x + 2x + 24 = 30

=> 3x + 24 = 30

Subtract 24 from both sides of the equation,

=> 3x + 24 - 24 = 30 - 24

=> 3x = 6

Divide both side by 3,

=> x = 2, is the smaller number.

So, the larger number is x + 12 = 2 + 12 = 14.

## College Algebra Homework Help

Learn Algebra from solving equations to logarithms and sketching graphs to  complex numbers. College Algebra covers a range of topics like linear equations, quadratic equations, matrices, logarithms and polynomials. Free online Algebra solvers are readily available and cover all the topics that are a part of the college syllabus. Students will gain an in-depth understanding of Algebraic principles and learn how to use them to solve problems. College Algebra equation solvers give step by step solutions to each problem and explain how each step leads to the next with the right operations or rules involved.

### Solved Example

Question: The base of a triangle is 7 m more than its altitude. If the area of the triangle is 15 square m. Find its altitude.
Solution:

Let the altitude of the triangle (AD) = x

therefore, base of the triangle (BC) = x + 7

Given, area of the triangle = 15

Step 1:

Area of the triangle = $\frac{1}{2}$ Base * Height

=> 15 = $\frac{1}{2}$ * (x + 7) * x

=> 15 * 2 = (x + 7) * x

=> 30 = x2 + 7x

x2 + 7x - 30 = 0

Step 2:

Solve for x, x2 + 7x - 30 = 0

=> x2 + 10x - 3x - 30 = 0

=> x(x + 10) - 3(x + 10) = 0

=> (x - 3)(x + 10) = 0

Step 3:

Either x - 3 = 0 or x + 10 = 0

=> x = 3 or x = - 10

Length must be positive. So, neglect x = - 10.

Hence, altitude of the triangle is 3 m.