Question

# Two capacitors $$C_{1}$$ and $$C_{2}$$ are charged to 120 $$V$$ and 200 $$V$$ respectively. It is found that by connecting them together the potential on each one can be made zero. Then,

A
3C1=5C2
B
3C1+5C2=0
C
9C1=4C2
D
5C1=3C2

Solution

## The correct option is A $$3C_{1}=5C_{2}$$Potential can be made zero only if they have same charge. $$\implies 120 C_{1}=200C_{2}$$$$\therefore 6C_{1}=10C_{2}$$$$3C_{1}=5C_{2}$$PhysicsNCERTStandard XII

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