• # question_answer A Carnot engine working between 300 and 600 K has a work output of 800 joule per cycle. The amount of heat energy supplied from the source to engine in each cycle is A)  800 J                                     B)  1600 J C)  3200 J                                   D)  6400 J

The efficiency of Carnot engine is given by Given ${{T}_{1}}=600\,K,$ ${{T}_{2}}=300\,K$ $\therefore$  $n=1-\frac{300}{600}$ $\Rightarrow$               $n=1-\frac{1}{2}$ $\Rightarrow$               $n=\frac{1}{2}=50%$ Also,      $n=\frac{W}{Q}=\frac{800}{Q}=\frac{1}{2}$ Thus,     $Q=800\times 2=1600\,J$