I want my Python code not to error out if it runs into an error and to follow a different line of code. How do I make it do that?
I want my Python code not to error out if it runs into an error and to follow a different line of code. How do I make it do that?
user
One way you can accomplish that is by using a Try Except statement. This type of statement will separate your code into two blocks, a Try block and an Except block. The Try block will run the code, and if it raises an exception, it will execute the Except block. If no exception is raised, only the Try block will run. Here is an example:

def divide_numbers(x, n):
    try:
        quotient = x // n
        print("Answer:", quotient)
    except:
        print("Cannot perform division.")

This will run the Try block and divide x by n. If there are no errors, it will print the answer. However, if it encounters an error, it will instead print "Cannot perform division." For example:

divide_numbers(6, 3)
# Output:
# Answer: 2

divide_numbers(2, 0)
# Output:
# Cannot perform divsion.

You can also specify the exception in the Except statement like this:

def divide_numbers(x, n):
    try:
        quotient = x // n
        print("Answer:", quotient)
    except ZeroDivisionError:
        print("Cannot perform division by zero.")

This way, the Except block will only run if ZeroDivisionError is raised. Does this help?
assistant