Reasoning: A square and a rhombus on the same base are equal in are
Ans: (A)
Question: If a square and a rhombus stand on the same base, then the ratio of the areas of the square and the rhombus is?
Options:
(A) 1:1
(B) 1:2
(C) 1:9
(D) 1:6
(E) 1:4
Rationale: Each new number is the same as the last number with the adder growing by 1. This would yield 11.
The answer: (A)
Question: 1,2,4,7,_,16
Options:
(A) 11
(B) 9
(C) 10
(D) 12
(E) 13
Reasoning: The total of six numbers = 6X8 = 48
The total of first 2 and last 3 numbers is = 2 X 11+3 X 4 = 34
So, the middle number is (48 - 34 ) = 14
Ans: (D)
Question: The Average of six numbers is 8. The average of the first two is 11 and the average of the last three is 4. What is the middle number?
Options:
(A) A) 15
(B) B) 8
(C) C) 6
(D) D) 14
(E) E) 9
Rationale: Work done by X in 1 day = 1/24
Work done by Y in 1 day = 1/16
Work done by Y in 10 days = 10/16 = 5/8
Remaining work = 1 – 5/8 = 3/8
Number of days in which X can finish the remaining work = (3/8) / (1/24) = 9
The answer: (E)
Question: X can finish a work in 24 days. Y can finish the same work in 16 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work?
Options:
(A) 3
(B) 5
(C) 6
(D) 8
(E) 9
Reasoning: On first wheel there can be 10 digits. On the second wheel there will be one of the 9 digits and on the third wheel there will be 8 digits. Therefore, the number of numbers is
10 x 9 x 8 = 720
Ans: (A)
Question: A number lock on a suitcase has 3 wheels each labelled with 10 digits from 0 to 9. If opening of the lock is a particular sequence of three digits with no repeats, how many such sequences will be possible?
Options:
(A) 720
(B) 760
(C) 680
(D) 780
(E) 880
Reasoning: Number of ways of selecting 3 people out of 10 people = 10C3
In the three members George will always be there in the team. At this step we have vacancy for 2 more members and 9 members are available. Lina cannot be there in the team. So 2 members have to be selected and the number of available members = 9 - Nina = 8
Number of ways to form a 3 member team that includes George and excludes Nina = 8C2
Probability = 8C2/10C3 = 28/120
Ans: (C)

Show your work and conclude with the exact phrasing "Therefore, the final answer is [answer]." where [answer] is just the final number or expression that solves the problem.
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Question: From a Group of 10 People, Including George and Nina, 3 people are to be selected at random to work on a certain project. What is the probability that 3 people selected will include George but not Nina
Options:
(A) 5/56
(B) 9/56
(C) 28/120
(D) 21/56
(E) 25/56