[Question]Three schools organized a science fair competition and invited students from all the schools to develop ideas and present them before a panel of judges selected by all the schools competing in the science fair. There were 50 students from Know It All High School at the competition, 3/5 times as many students from Karen High as Know It All High School, and twice the combined number of students from the first two schools that came were from Novel Corona High School. Calculate the total number of students at the competition?
[Answer]If 50 students came from Know It All High School, then Karen High, which had 3 / 5 times as many students as Know It All High School, had 3 / 5 * 50 = 30 students at the fair. The total number of students from Know It All and Karen high schools is 50 + 30 = 80 students. If Novel Corona had twice the combined number of students from Know It All and Karen high schools, then it had 2 * 80 = 160 students at the competition. The total number of students at the competition is 80 + 160 = 240. The answer is 240.
Q: Mr. Willson worked on making his furniture for 3/4 an hour on Monday. On Tuesday, he worked for half an hour. Then he worked for 2/3 an hour on Wednesday and 5/6 of an hour on Thursday. If he worked for 75 minutes on Friday, how many hours in all did he work from Monday to Friday?
A: Since there are 60 minutes in an hour, then Mr. Willson worked for 60 minutes x 3 / 4 = 45 minutes on Monday. He worked for 60 minutes / 2 = 30 minutes on Tuesday. He worked for 60 minutes x 2 / 3 = 40 minutes on Wednesday. He worked for 60 minutes x 5 / 6 = 50 minutes on Thursday. So Mr. Willson worked for 45 + 30 + 40 + 50 + 75 = 240 minutes. In hours, it is equal to 240 / 60 = 4 hours. The answer is 4.
Question: Morgan goes to the drive-thru and orders his lunch. He gets a hamburger for $4, onion rings for $2 and a smoothie for $3. If he pays with a $20 bill, how much change does he receive?
Answer: Morgan’s lunch cost $4 + $2 + $3 = $9. If he pays with a $20 bill, he will receive change of $20 - $9 = $11. The answer is 11.
[Question]Josiah is three times as old as Hans. Hans is 15 years old now. In three years, what is the sum of the ages of Josiah and Hans?
[Answer]Josiah is 15 x 3 = 45 years old now. In three years, Josiah will be 45 + 3 = 48 years old. Hans will be 15 + 3 = 18 years old in three years. So, the sum of their ages in three years is 48 + 18 = 66 years old. The answer is 66.
Q: One hundred chips were divided by Ian and Lyle in the ratio 4:6. What percentage of the chips did Lyle have?
A: The chips were divided into 4 + 6 = 10 parts. Each part has 100 / 10 = 10 chips. Since Lyle owns 6 parts, then he has 6 x 10 = 60 chips. This is 60 / 100 x 100 = 60% of the entire chips. The answer is 60.
Question: Amy, Jeremy, and Chris have a combined age of 132. Amy is 1/3 the age of Jeremy, and Chris is twice as old as Amy. How old is Jeremy?
Answer:

Show your work and conclude with the exact phrasing "Therefore, the final answer is [answer]." where [answer] is just the final number or expression that solves the problem.
user
Let x represent the age of Jeremy. Amy:(1 / 3)x. Chris:2(1 / 3)x = (2 / 3)x. Total:x + (1 / 3)x + (2 / 3)x = 132. 2x = 132. x = 66 years old. The answer is 66.