(Ans). (C)
(Question). The no. of girls in a class are seven times the no. of boys, which value cannever be the of total students?
Options:
(A) 3
(B) 4
(C) 8
(D) 9
(E) 12
(CoT). Let the boys are X, then girls are 7X, total = X+7X = 8X
So it should be multiple of 8, 30 is not a multiple of 8.


(Ans). (C)
(Question). If P(A) = 2/15, P(B) = 4/15, and P(A ∪ B) = 6/15 Find P(A|B)
Options:
(A) 1/2
(B) 2/3
(C) 3/2
(D) 4/5
(E) 4/7
(CoT). P(A|B) = P(A ∪ B)/P(B)
P(A|B) = (6/15)/(4/15) = 3/2.


(Ans). (E)
(Question). There are 10 female and 15 male in a work place. In how many ways can a person can be selected?
Options:
(A) 20
(B) 15
(C) 18
(D) 40
(E) 25
(CoT). No of ways = 10+ 15 = 25


(Ans). (B)
(Question).

Show your work and conclude with the exact phrasing "Therefore, the final answer is [answer]." where [answer] is just the final number or expression that solves the problem.
user
What is theleast number should be added to 1056, so the sum of the number is completely divisible by 23?
Options:
(A) 1
(B) 2
(C) 3
(D) 5
(E) 6
(CoT). (1056 / 23) gives remainder 21
21 + 2 = 23, So we need to add 2