Rationale: I = (520*7*8)/100 = 291
The answer: (C)
Question: Find the simple interest on Rs.520 for 7 months at 8 paisa per month?
Options:
(A) 277
(B) 270
(C) 291
(D) 266
(E) 121
Reasoning: Purchase = 8748/(1-10/100^3) = 12000
Ans: (A)
Question: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was :
Options:
(A) 12000
(B) 10000
(C) 15000
(D) 20000
(E) 25000
Rationale: Circumference C is given by
C = 2πr = 2π*7 = 14 π cm
The answer: (E)
Question: Calculate the circumference of a circular field whose radius is 7 centimeters.
Options:
(A) 11 π cm
(B) 15 π cm
(C) 1 π cm
(D) 4 π cm
(E) 14 π cm
Reasoning: Number of times wheel moves in 1 hour = 20 * 60 = 1200
:. Distance moves = (1200*20) cms = 24000 cms
In metres = 240 metre
Ans: (C)
Question: A wheel rotates 20 times every minute and moves 20 cm during each rotation. How many metres does the wheel move in one hour?
Options:
(A) 4 metre
(B) 12 metre
(C) 240 metre
(D) 2400 metre
(E) 130 metre
Rationale: Overall, there can be 31 minuses. Tus, it is
The answer: (B)
Question: A certain league has two divisions. The respective divisions had 7 and 9 teams qualify for the playoffs. Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games -- in order to determine its champion. The four division champions then played in a single-elimination tournament -- where a team is eliminated upon losing one game -- in order to determine the overall league champion. Assuming that there were no ties and no forfeits, what is the maximum number of games that could have been played in order to determine the overall league champion?
Options:
(A)  30
(B)  31
(C)  34
(D)  36
(E)  38
Rationale: Correct Answer: (E)
Let’s go through each answer choice: (A) can never be true, since no negative is greater than a positive. (B) doesn’t have to be true – consider what would happen if x = -2 and y = 1. (C) can never be true, as x^3 must be negative, and y^2 must be positive. (D) can never be true, since if x < 0, -x is the same thing as |x|, and |x| > y. (E) can be manipulated by multiplying both sides by -1, which gives us –x > y. Remember that x < 0, so –x = |x|, and y is positive, so |y| = y. Thus –x > y is the same statement as |x| > |y|, and (D) must be true.
The answer: (D)

Show your work and conclude with the exact phrasing "Therefore, the final answer is [answer]." where [answer] is just the final number or expression that solves the problem.
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Question: If x<0, y>0, and |x| < |y|, which of the following must be true?
Options:
(A) x > y
(B) y^2 > x^2
(C) x^3 > y^2
(D) –x > y
(E) x < –y