G-a-s-t hat geschrieben:x' = (x-v1*t) / sqrt{1-v1^2} = 10 / sqrt{1-0,9801} = 70,88... und t' = (t-v1*x) / sqrt{1-v1^2} = -9,9 / sqrt{1-0,9801} = -70,17... Nun: t' = (t-v1*x) / sqrt{1-v1^2} = (t-v1*(10-v2*t)) / sqrt{1-v1^2} = 0 t = 10*v1 / (1+v1*v2) x' = (x-v1*t) / sqrt{1-v1^2} = (10-v2*t-v1*t) / sqrt{1-v1^2} = (10-(v1+v2)*t) / sqrt{1-v1^2} = 10*(1-(v1+v2)*(v1/(1+v1*v2))) / sqrt{1-v1^2} = 1,177... .