limx→2π 
(x^3 + π^2x − 5π^3);
To evaluate the limit of the given equation as x approaches 2π, we simply substitute 2π into the equation:\n\nlim (x→2π) (x^3 + π^2x - 5π^3)\n\n= (2π)^3 + π^2(2π) - 5π^3\n= 8π^3 + 2π^3 - 5π^3\n\nNow we just need to simply the expression:\n\n= (8 + 2 - 5)π^3\n= 5π^3\n\nSo the limit of the equation as x approaches 2π is 5π^3.