text: 
  def close(n, smallest=10, d=10):
      """ A sequence is near increasing if each element but the last two is smaller than all elements
      following its subsequent element. That is, element i must be smaller than elements i + 2, i + 3, i + 4, etc.
      Implement close, which takes a non-negative integer n and returns the largest near increasing sequence
      of digits within n as an integer. The arguments smallest and d are part of the implementation; you must
      determine their purpose. The only values you may use are integers and booleans (True and False) (no lists, strings, etc.).
      Return the longest sequence of near-increasing digits in n.
      >>> close(123)
      123
      >>> close(153)
      153
      >>> close(1523)
      153
      >>> close(15123)
      1123
      >>> close(11111111)
      11
      >>> close(985357)
      557
      >>> close(14735476)
      143576
      >>> close(812348567)
      1234567
      """
      if n == 0:
        return ______
      no = close(n//10, smallest, d)
      if smallest > ______:
          yes = ______
          return ______(yes, no)
      return ______
  
  # ORIGINAL SKELETON FOLLOWS
  
  # def close(n, smallest=10, d=10):
  #     """ A sequence is near increasing if each element but the last two is smaller than all elements
  #     following its subsequent element. That is, element i must be smaller than elements i + 2, i + 3, i + 4, etc.
  #     Implement close, which takes a non-negative integer n and returns the largest near increasing sequence
  #     of digits within n as an integer. The arguments smallest and d are part of the implementation; you must
  #     determine their purpose. The only values you may use are integers and booleans (True and False) (no lists, strings, etc.).
  #     Return the longest sequence of near-increasing digits in n.
  #     >>> close(123)
  #     123
  #     >>> close(153)
  #     153
  #     >>> close(1523)
  #     153
  #     >>> close(15123)
  #     1123
  #     >>> close(11111111)
  #     11
  #     >>> close(985357)
  #     557
  #     >>> close(14735476)
  #     143576
  #     >>> close(812348567)
  #     1234567
  #     """
  #     if n == 0:
  #       return ______
  #     no = close(n//10, smallest, d)
  #     if smallest > ______:
  #         yes = ______
  #         return ______(yes, no)
  #     return ______
  