2015 Stockholm Open – Doubles
# 2015 Stockholm Open – Doubles

Eric Butorac and Raven Klaasen were the defending champions, but Klaasen chose not to participate. Butorac played alongside Scott Lipsky, but lost in the semifinals to Nicholas Monroe and Jack Sock.

Nicholas Monroe and Jack Sock went on to win the title, defeating Mate Pavić and Michael Venus in the final, 7–5, 6–2

## Seeds

* Jérémy Chardy / Robert Lindstedt (quarterfinals, withdrew)
* Nicholas Monroe / Jack Sock (champions)
* Eric Butorac / Scott Lipsky (semifinals)
* Jonathan Marray / Aisam-ul-Haq Qureshi (quarterfinals)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Draw

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | J Chardy R Lindstedt | 6 | 6 | | | | | | | | | | | | | |
| | B Becker A Zverev | 2 | 1 | | 1 | J Chardy R Lindstedt | | | | | | | | | | |
| | J Erlich P Petzschner | 6 | 6 | | | J Erlich P Petzschner | w/o | | | | | | | | | |
| | M Baghdatis T Kokkinakis | 4 | 2 | | | | | | | J Erlich P Petzschner | 3 | 3 | | | | |
| 4 | J Marray A-u-H Qureshi | 6 | 3 | [10] | | | | | | M Pavić M Venus | 6 | 6 | | | | |
| WC | J Brunström J Nieminen | 1 | 6 | [7] | 4 | J Marray A-u-H Qureshi | 4 | $6^4$ | | | | | | | | |
| | F Delbonis L Mayer | 6 | 4 | [5] | | M Pavić M Venus | 6 | $7^7$ | | | | | | | | |
| | M Pavić M Venus | 1 | 6 | [10] | | | | | | | | | | M Pavić M Venus | 5 | 2 |
| | M Fyrstenberg S González | 4 | 3 | | | | | | | | | | 2 | N Monroe J Sock | 7 | 6 |
| | M Daniell M Demoliner | 6 | 6 | | | M Daniell M Demoliner | $6^4$ | 5 | | | | | | | | |
| | C Fleming G Müller | $6^6$ | 4 | | 3 | E Butorac S Lipsky | $7^7$ | 7 | | | | | | | | |
| 3 | E Butorac S Lipsky | $7^8$ | 6 | | | | | | 3 | E Butorac S Lipsky | 4 | $6^3$ | | | | |
| WC | I Arvidsson F Simonsson | 1 | $7^7$ | [5] | | | | | 2 | N Monroe J Sock | 6 | $7^7$ | | | | |
| | C Guccione A Sá | 6 | $6^3$ | [10] | | C Guccione A Sá | 4 | 4 | | | | | | | | |
| | A Begemann A Sitak | $6^6$ | 1 | | 2 | N Monroe J Sock | 6 | 6 | | | | | | | | |
| 2 | N Monroe J Sock | $7^8$ | 6 | | | | | | | | | | | | | |
