2014 Franken Challenge – Doubles
# 2014 Franken Challenge – Doubles

Colin Ebelthite and Rameez Junaid were the defending champions, but decided not to compete.

Gerard Granollers and Jordi Samper Montaña won the title, defeating Adrián Menéndez-Maceiras and Rubén Ramírez Hidalgo in the final, $7–6^{(7–1)},$ 6–2.

## Seeds

* Frank Moser / Alexander Satschko (quarterfinals)
* Ruben Gonzales / Roberto Maytín (quarterfinals)
* Ariel Behar / Vahid Mirzadeh (semifinals)
* Lee Hsin-han / Zhang Ze (first round)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Draw

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | F Moser A Satschko | 6 | 6 | | | | | | | | | | | | | | |
| WC | A Kapaś B Koniusz | 3 | 4 | | 1 | F Moser A Satschko | 6 | 4 | [2] | | | | | | | | |
| | G Granollers JS Montaña | 6 | 3 | [10] | | G Granollers JS Montaña | 1 | 6 | [10] | | | | | | | | |
| | A Haider-Maurer M Neuchrist | 2 | 6 | [7] | | | | | | | G Granollers JS Montaña | 6 | 0 | [11] | | | |
| 3 | A Behar V Mirzadeh | $7^7$ | 4 | [10] | | | | | | 3 | A Behar V Mirzadeh | 2 | 6 | [9] | | | |
| | G Elias A Ghem | $6^4$ | 6 | [4] | 3 | A Behar V Mirzadeh | 6 | 6 | | | | | | | | | |
| | G Clezar H Laaksonen | $6^5$ | 6 | [10] | | G Clezar H Laaksonen | 2 | 2 | | | | | | | | | |
| WC | J Härteis M Marterer | $7^7$ | 2 | [5] | | | | | | | | | | | G Granollers JS Montaña | $7^7$ | 6 |
| WC | Steven Moneke P Torebko | 6 | 6 | | | | | | | | | | | | A Menéndez-Maceiras RR Hidalgo | $6^1$ | 2 |
| PR | G Burquier O Charroin | 4 | 4 | | WC | S Moneke P Torebko | 5 | 3 | | | | | | | | | |
| | K Krawietz P Marx | 7 | 6 | | | K Krawietz P Marx | 7 | 6 | | | | | | | | | |
| 4 | H-h Lee Z Zhang | 5 | 2 | | | | | | | | K Krawietz P Marx | $7^7$ | 5 | [4] | | | |
| | A Menéndez-Maceiras RR Hidalgo | 6 | 6 | | | | | | | | A Menéndez-Maceiras RR Hidalgo | $6^5$ | 7 | [10] | | | |
| PR | IC Huegun S Diez | 1 | 2 | | | A Menéndez-Maceiras RR Hidalgo | 4 | 6 | [10] | | | | | | | | |
| | A Martin W Odesnik | 3 | $7^7$ | [7] | 2 | R Gonzales R Maytín | 6 | 4 | [3] | | | | | | | | |
| 2 | R Gonzales R Maytín | 6 | $6^5$ | [10] | | | | | | | | | | | | | |
