2018 JC Ferrero Challenger Open – Doubles
# 2018 JC Ferrero Challenger Open – Doubles

This was the first edition of the tournament.

Wesley Koolhof and Artem Sitak won the title after defeating Guido Andreozzi and Ariel Behar 6–3, 6–2 in the final.

## Seeds

* Wesley Koolhof / Artem Sitak (champions)
* Andre Begemann / Divij Sharan (first round)
* Jonathan Eysseric / Hugo Nys (first round)
* Guido Andreozzi / Ariel Behar (final)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | W Koolhof A Sitak | 6 | 6 | | | | | | | | | | | | | | | |
| | Í Cervantes D Marrero | 4 | 1 | | 1 | W Koolhof A Sitak | w/o | | | | | | | | | | | |
| Alt | A Arnaboldi A Giannessi | 7 | 7 | | Alt | A Arnaboldi A Giannessi | | | | | | | | | | | | |
| | R Junaid G Oliveira | 5 | 5 | | | | | | | 1 | W Koolhof A Sitak | 5 | 6 | [10] | | | | |
| 3 | J Eysseric H Nys | 2 | 4 | | | | | | | WC | P Martínez D Vega Hernández | 7 | 4 | [5] | | | | |
| WC | P Martínez D Vega Hernández | 6 | 6 | | WC | P Martínez D Vega Hernández | 6 | 4 | [10] | | | | | | | | | |
| WC | A de Minaur S Gutiérrez Ferrol | 2 | 4 | | | Y Shyla A Vasilevski | 4 | 6 | [8] | | | | | | | | | |
| | Y Shyla A Vasilevski | 6 | 6 | | | | | | | | | | | | 1 | W Koolhof A Sitak | 6 | 6 |
| WC | Carlos Boluda-Purkiss M Vilella Martínez | 6 | 6 | | | | | | | | | | | | 4 | G Andreozzi A Behar | 3 | 2 |
| | K de Schepper E López Pérez | 4 | 2 | | WC | C Boluda-Purkiss M Vilella Martínez | 3 | 1 | | | | | | | | | | |
| | T Bednarek G Panfil | 2 | 6 | [8] | 4 | G Andreozzi A Behar | 6 | 6 | | | | | | | | | | |
| 4 | G Andreozzi A Behar | 6 | 3 | [10] | | | | | | 4 | G Andreozzi A Behar | 6 | 6 | | | | | |
| | A Motti S Travaglia | 6 | $7^7$ | | | | | | | | A Motti S Travaglia | 0 | 2 | | | | | |
| | Z Kolář A Siljeström | 1 | $6^3$ | | | A Motti S Travaglia | 6 | 6 | | | | | | | | | | |
| | S Clayton D Pel | 6 | 5 | [10] | | S Clayton D Pel | 3 | 2 | | | | | | | | | | |
| 2 | A Begemann D Sharan | 4 | 7 | [6] | | | | | | | | | | | | | | |
