2015 Australian Open – Men's legends' doubles
# 2015 Australian Open – Men's legends' doubles

Jonas Björkman and Thomas Johansson won the title emerging victorious over their compatriots Thomas Enqvist and Mats Wilander in the final in four sets.

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Finals

| Final | Final | Final | Final | Final | Final | Final |
| - | - | - | - | - | - | - |
| 1 | Jonas Björkman Thomas Johansson | $3^4$ | 4 | 4 | 4 | |
| 2 | Thomas Enqvist Mats Wilander | $4^6$ | 2 | 2 | 2 | |

### Group A

| | Woodbridge Woodforde | Leconte Philippoussis | Björkman Johansson | Chang Ferreira | RR W–L | Set W–L | Game W–L | Standings |
| - | - | - | - | - | - | - | - | - |
| Todd Woodbridge Mark Woodforde | | 2-4, $3-4^{(3-5)}$ | $3-4^{(2-5)},$ 1-4, $4-3^{(6-4)},$ $3-4^{(0-5)}$ | 4-2, $4-3^{(4-2)},$ $4-3^{(4-2)}$ | 1–2 | 4–5 | 28–31 | 3 |
| Henri Leconte Mark Philippoussis | 4-2, $4-3^{(5-3)}$ | | 2-4, 4-1, $3-4^{(1-5)},$ $3-4^{(3-5)}$ | $4-3^{(5-3)},$ $4-3^{(5-3)},$ $4-3^{(5-3)}$ | 2–1 | 6–3 | 32–27 | 2 |
| Jonas Björkman Thomas Johansson | $4-3^{(5-2)},$ 4-1, $3-4^{(4-6)},$ $4-3^{(5-0)}$ | 4-2, 1-4, $4-3^{(5-1)},$ $4-3^{(5-3)}$ | | $3-4^{(3-5)},$ 4-2, $3-4^{(4-6)},$ 4-2, $4-3^{(5-2)}$ | 3–0 | 9–4 | 46–38 | 1 |
| Michael Chang Wayne Ferreira | 2-4, $3-4^{(2-4)},$ $3-4^{(2-4)}$ | $3-4^{(3-5)},$ $3-4^{(3-5)},$ $3-4^{(3-5)}$ | $4-3^{(5-3)},$ 2-4, $4-3^{(6-4)},$ 2-4, $3-4^{(2-5)}$ | | 0–3 | 2–9 | 32–42 | 4 |

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

### Group B

| | Ivanišević Gimelstob | Bahrami Santoro | Arthurs Cash | Enqvist Wilander | RR W–L | Set W–L | Game W–L | Standings |
| - | - | - | - | - | - | - | - | - |
| Goran Ivanišević Justin Gimelstob | | $3-4^{(4-6)},$ 0-4, $4-3^{(5-3)},$ 0-4 | 1-4, $3-4^{(3-5)},$ 4-1, 2-4 | $3-4^{(4-6)},$ $3-4^{(4-6)},$ 4-2, $3-4^{(3-5)}$ | 0–3 | 3–9 | 30–42 | 4 |
| Mansour Bahrami Fabrice Santoro | $4-3^{(6-4)},$ 4-0, $3-4^{(3-5)},$ 4-0 | | $3-4^{(2-4)},$ 4-2, $3-4^{(4-6)},$ $3-4^{(4-6)}$ | $3-4^{(3-5)},$ 4-1, [4-10] | 1–2 | 5–6 | 35–27 | 3 |
| Wayne Arthurs Pat Cash | 4-1, $4-3^{(5-3)},$ 1-4, 4-2 | $4-3^{(4-2)},$ 2-4, $4-3^{(6-4)},$ $4-3^{(6-4)}$ | | $3-4^{(3-5)},$ 4-2, $3-4^{(2-5)},$ 4-2, $3-4^{(3-5)}$ | 2–1 | 8–5 | 44–39 | 2 |
| Thomas Enqvist Mats Wilander | $4-3^{(6-4)},$ $4-3^{(6-4)},$ 2-4, $4-3^{(5-3)}$ | $4-3^{(5-3)},$ 1-4, [10-4] | $4-3^{(5-3)},$ 2-4, $4-3^{(5-2)},$ 2-4, $4-3^{(5-3)}$ | | 3–0 | 8–5 | 36–37 | 1 |

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

