2014 ATP Challenger China International – Nanchang – Doubles
# 2014 ATP Challenger China International – Nanchang – Doubles

This was the first edition of the tournament.

Chen Ti and Peng Hsien-yin won the title, defeating Jordan Kerr and Fabrice Martin in the final, 6–2, 3–6, [12–10].

## Seeds

* Chen Ti / Peng Hsien-yin (champions)
* Jordan Kerr / Fabrice Martin (final)
* Lee Hsin-han / Zhang Ze (semifinals)
* Ryan Agar / Huang Liang-chi (first round)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Draw

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | T Chen H-y Peng | 6 | 6 | | | | | | | | | | | | | | | |
| WC | R Hua S Liu | 3 | 4 | | 1 | T Chen H-y Peng | $7^7$ | 6 | | | | | | | | | | |
| | Y Bai D Wu | 6 | 6 | | | Y Bai D Wu | $6^2$ | 4 | | | | | | | | | | |
| | Gong Peng-Xiang Gong Xiao | 2 | 2 | | | | | | | 1 | T Chen H-y Peng | 6 | 6 | | | | | |
| 3 | H-h Lee Z Zhang | 6 | 7 | | | | | | | 3 | H-h Lee Z Zhang | 4 | 3 | | | | | |
| | N Kadchapanan D Udomchoke | 3 | 5 | | 3 | H-h Lee Z Zhang | 6 | 4 | [10 | | | | | | | | | |
| | S Balaji Shuichi Sekiguchi | 6 | 6 | | | S Balaji S Sekiguchi | 2 | 6 | [6] | | | | | | | | | |
| WC | Chen Long Wu Hao | 3 | 2 | | | | | | | | | | | 1 | T Chen H-y Peng | 6 | 3 | [12] |
| | M Gong H Kondo | $6^5$ | $7^7$ | [10] | | | | | | | | | | 2 | J Kerr F Martin | 2 | 6 | [10] |
| | N Meister J Nedunchezhiyan | $7^7$ | $6^2$ | [4] | | M Gong H Kondo | 2 | 7 | [10] | | | | | | | | | |
| | H Chung J-s Nam | 3 | $7^7$ | [10] | | H Chung J-s Nam | 6 | 5 | [7] | | | | | | | | | |
| 4 | R Agar L-c Huang | 6 | $6^5$ | [7] | | | | | | | M Gong H Kondo | 3 | 4 | | | | | |
| WC | Y Ning A Wang | 3 | 2 | | | | | | | 2 | J Kerr F Martin | 6 | 6 | | | | | |
| | D Matsukevich V Rudnev | 6 | 6 | | | D Matsukevich V Rudnev | w/o | | | | | | | | | | | |
| | T Matsui G Soeda | $6^5$ | 6 | [6] | 2 | J Kerr F Martin | | | | | | | | | | | | |
| 2 | J Kerr F Martin | $7^7$ | 3 | [10] | | | | | | | | | | | | | | |
