2022 Challenger di Roseto degli Abruzzi II – Doubles
# 2022 Challenger di Roseto degli Abruzzi II – Doubles

Hugo Nys and Jan Zieliński were the defending champions but chose not to defend their title.

Franco Agamenone and Manuel Guinard won the title after defeating Ivan and Matej Sabanov $7–6^{(7–2)},$ $7–6^{(7–3)}$ in the final.

## Seeds

* Robin Haase / Andrea Vavassori (first round)
* Roman Jebavý / Philipp Oswald (first round)
* Ivan Sabanov / Matej Sabanov (final)
* Romain Arneodo / Szymon Walków (quarterfinals)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | R Haase A Vavassori | 4 | 4 | | | | | | | | | | | | | | | |
| | F Gaio A Pellegrino | 6 | 6 | | | F Gaio A Pellegrino | 6 | 4 | [10] | | | | | | | | | |
| | F Cabral D Vega Hernández | 6 | 6 | | | F Cabral D Vega Hernández | 4 | 6 | [8] | | | | | | | | | |
| | J Cerretani N Serdarušić | 2 | 2 | | | | | | | | F Gaio A Pellegrino | 4 | 6 | [5] | | | | |
| 4 | R Arneodo S Walków | 6 | 6 | | | | | | | | F Agamenone M Guinard | 6 | 4 | [10] | | | | |
| | R Brancaccio F Cobolli | 2 | 4 | | 4 | R Arneodo S Walków | 6 | 3 | [7] | | | | | | | | | |
| | F Agamenone M Guinard | 6 | 6 | | | F Agamenone M Guinard | 1 | 6 | [10] | | | | | | | | | |
| WC | Andrea Del Federico Giorgio Ricca | 2 | 2 | | | | | | | | | | | | | F Agamenone M Guinard | $7^7$ | $7^7$ |
| WC | F Maestrelli G Zeppieri | 6 | $6^2$ | [6] | | | | | | | | | | | 3 | I Sabanov M Sabanov | $6^2$ | $6^3$ |
| | M Bortolotti L Darderi | 4 | $7^7$ | [10] | | M Bortolotti L Darderi | 2 | 5 | | | | | | | | | | |
| | S Arends D Pel | 5 | 7 | [8] | 3 | I Sabanov M Sabanov | 6 | 7 | | | | | | | | | | |
| 3 | I Sabanov M Sabanov | 7 | 5 | [10] | | | | | | 3 | I Sabanov M Sabanov | 7 | 6 | | | | | |
| | A Martin T-S Weissborn | $6^4$ | 6 | [10] | | | | | | | A Martin T-S Weissborn | 5 | 4 | | | | | |
| | D Sharan C-h Tseng | $7^7$ | 2 | [2] | | A Martin T-S Weissborn | 6 | 6 | | | | | | | | | | |
| | J Nedunchezhiyan R Ramanathan | 6 | $6^1$ | [10] | | J Nedunchezhiyan R Ramanathan | 4 | 4 | | | | | | | | | | |
| 2 | R Jebavý P Oswald | 4 | $7^7$ | [4] | | | | | | | | | | | | | | |
