2019 New York Open – Doubles
# 2019 New York Open – Doubles

Max Mirnyi and Philipp Oswald were the defending champions, but Mirnyi retired from professional tennis at the end of 2018 and Oswald chose not to participate this year.

Kevin Krawietz and Andreas Mies won their first ATP Tour title, defeating Santiago González and Aisam-ul-Haq Qureshi in the final, 6–4, 7–5.

## Seeds

* Bob Bryan / Mike Bryan (first round)
* Ken Skupski / Neal Skupski (first round)
* Luke Bambridge / Jonny O'Mara (quarterfinals)
* Robert Lindstedt / Tim Pütz (semifinals)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Draw

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | B Bryan M Bryan | $6^9$ | 4 | | | | | | | | | | | | | | |
| Alt | T Sandgren J Withrow | $7^{11}$ | 6 | | Alt | T Sandgren J Withrow | $6^6$ | 6 | [8] | | | | | | | | |
| | R Albot J-P Smith | 1 | 6 | [8] | | A Mannarino H Nys | $7^8$ | 4 | [10] | | | | | | | | |
| | A Mannarino H Nys | 6 | 3 | [10] | | | | | | | A Mannarino H Nys | 4 | 6 | [10] | | | |
| 3 | L Bambridge J O'Mara | 6 | 6 | | | | | | | | S González A-u-H Qureshi | 6 | 3 | [12] | | | |
| | D Molchanov I Zelenay | 4 | 3 | | 3 | L Bambridge J O'Mara | $7^7$ | 4 | [5] | | | | | | | | |
| WC | B Evans J Isner | 3 | 2 | | | S González A-u-H Qureshi | $6^1$ | 6 | [10] | | | | | | | | |
| | S González A-u-H Qureshi | 6 | 6 | | | | | | | | | | | | S González A-u-H Qureshi | 4 | 5 |
| Alt | P Lorenzi P Polansky | 1 | 6 | [11] | | | | | | | | | | | K Krawietz A Mies | 6 | 7 |
| | R Harrison J Thompson | 6 | 3 | [13] | | R Harrison J Thompson | $7^7$ | 2 | [6] | | | | | | | | |
| WC | L Hewitt A Popyrin | 4 | 4 | | 4 | R Lindstedt T Pütz | $6^5$ | 6 | [10] | | | | | | | | |
| 4 | R Lindstedt T Pütz | 6 | 6 | | | | | | | 4 | R Lindstedt T Pütz | 2 | 4 | | | | |
| | M McDonald J Millman | 4 | 6 | [11] | | | | | | | K Krawietz A Mies | 6 | 6 | | | | |
| | S Johnson R Opelka | 6 | 4 | [9] | | M McDonald J Millman | 3 | 2 | | | | | | | | | |
| | K Krawietz A Mies | 7 | $7^7$ | | | K Krawietz A Mies | 6 | 6 | | | | | | | | | |
| 2 | K Skupski N Skupski | 5 | $6^3$ | | | | | | | | | | | | | | |
