2014 Apia International Sydney – Men's doubles
# 2014 Apia International Sydney – Men's doubles

Bob Bryan and Mike Bryan were the defending champions, but lost in the quarterfinals to Lukáš Rosol and João Sousa. Daniel Nestor and Nenad Zimonjić won the title, defeating Rohan Bopanna and Aisam-ul-Haq Qureshi in the final, $7–6^{(7–3)},$ $7–6^{(7–3)}.$

## Seeds

* Bob Bryan / Mike Bryan (quarterfinals)
* Leander Paes / Radek Štěpánek (first round)
* Rohan Bopanna / Aisam-ul-Haq Qureshi (final)
* Mariusz Fyrstenberg / Marcin Matkowski (quarterfinals)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Draw

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Finals | Finals | Finals | Finals |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | B Bryan M Bryan | 6 | $7^7$ | | | | | | | | | | | | | | | |
| | Ł Kubot R Lindstedt | 3 | $6^5$ | | 1 | B Bryan M Bryan | 6 | 3 | [12] | | | | | | | | | |
| | J Janowicz M Mirnyi | 6 | $6^7$ | [9] | | L Rosol J Sousa | 3 | 6 | [14] | | | | | | | | | |
| | L Rosol J Sousa | 4 | $7^9$ | [11] | | | | | | | L Rosol J Sousa | 1 | 2 | | | | | |
| 3 | R Bopanna A-U-H Qureshi | $7^7$ | $6^2$ | [10] | | | | | | 3 | R Bopanna A-U-H Qureshi | 6 | 6 | | | | | |
| | J-J Rojer H Tecău | $6^5$ | $7^7$ | [3] | 3 | R Bopanna A-U-H Qureshi | $6^3$ | $7^7$ | [10] | | | | | | | | | |
| | P Andújar D Marrero | 4 | 3 | | | TC Huey D Inglot | $7^7$ | $6^5$ | [3] | | | | | | | | | |
| | TC Huey D Inglot | 6 | 6 | | | | | | | | | | | | 3 | R Bopanna A-U-H Qureshi | $6^3$ | $6^3$ |
| | M Llodra N Mahut | 6 | 4 | [9] | | | | | | | | | | | | D Nestor N Zimonjić | $7^7$ | $7^7$ |
| | D Nestor N Zimonjić | 2 | 6 | [11] | | D Nestor N Zimonjić | 6 | 3 | [10] | | | | | | | | | |
| | C Berlocq A Seppi | 5 | $7^7$ | [5] | 4 | M Fyrstenberg M Matkowski | 4 | 6 | [8] | | | | | | | | | |
| 4 | M Fyrstenberg M Matkowski | 7 | $6^2$ | [10] | | | | | | | D Nestor N Zimonjić | 4 | $7^7$ | [10] | | | | |
| WC | J Duckworth S Groth | $7^7$ | 6 | | | | | | | | J Benneteau É Roger-Vasselin | 6 | $6^5$ | [5] | | | | |
| Alt | M Elgin D Istomin | $6^5$ | 4 | | WC | J Duckworth S Groth | 4 | 6 | [6] | | | | | | | | | |
| | J Benneteau É Roger-Vasselin | 6 | 6 | | | J Benneteau É Roger-Vasselin | 6 | 1 | [10] | | | | | | | | | |
| 2 | L Paes R Štěpánek | 4 | 4 | | | | | | | | | | | | | | | |
