2019 Surbiton Trophy – Men's doubles
# 2019 Surbiton Trophy – Men's doubles

Luke Bambridge and Jonny O'Mara were the defending champions but only Bambridge chose to defend his title, partnering Marcus Daniell. Bambridge lost in the semifinals to Marcel Granollers and Ben McLachlan.

Granollers and McLachlan won the title after defeating Kwon Soon-woo and Ramkumar Ramanathan 4–6, 6–3, [10–2] in the final.

## Seeds

* Marcel Granollers / Ben McLachlan (champions)
* Marcelo Demoliner / Divij Sharan (first round)
* Luke Bambridge / Marcus Daniell (semifinals)
* Jonathan Erlich / Artem Sitak (quarterfinals)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | M Granollers B McLachlan | 6 | 6 | | | | | | | | | | | | | | | | |
| | S Balaji J Cerretani | 3 | 1 | | 1 | M Granollers B McLachlan | 6 | 6 | | | | | | | | | | | |
| | A de Minaur M Reid | 3 | 6 | [8] | WC | L Broady S Clayton | 3 | 4 | | | | | | | | | | | |
| WC | L Broady S Clayton | 6 | 4 | [10] | | | | | | 1 | M Granollers B McLachlan | 6 | $7^7$ | | | | | | |
| 3 | L Bambridge M Daniell | $7^{10}$ | 6 | | | | | | | 3 | L Bambridge M Daniell | 4 | $6^3$ | | | | | | |
| | P Polansky B Schnur | $6^8$ | 3 | | 3 | L Bambridge M Daniell | 1 | $7^7$ | [13] | | | | | | | | | | |
| | JC Aragone D Kudla | $6^4$ | $6^3$ | | | L Saville J-P Smith | 6 | $6^4$ | [11] | | | | | | | | | | |
| | L Saville J-P Smith | $7^7$ | $7^7$ | | | | | | | | | | | | 1 | M Granollers B McLachlan | 4 | 6 | [10] |
| | J Nedunchezhiyan P Raja | 4 | 3 | | | | | | | | | | | | | S-w Kwon R Ramanathan | 6 | 3 | [2] |
| | S-w Kwon R Ramanathan | 6 | 6 | | | S-w Kwon R Ramanathan | 6 | $7^7$ | | | | | | | | | | | |
| WC | L Hewitt J Thompson | 3 | $6^4$ | | 4 | J Erlich A Sitak | 2 | $6^5$ | | | | | | | | | | | |
| 4 | J Erlich A Sitak | 6 | $7^7$ | | | | | | | | S-w Kwon R Ramanathan | 6 | $6^3$ | [10] | | | | | |
| | D Köpfer T Paul | 3 | $7^7$ | [6] | | | | | | WC | D Evans L Glasspool | 4 | $7^7$ | [4] | | | | | |
| | T Kokkinakis N Kyrgios | 6 | $6^4$ | [10] | | T Kokkinakis N Kyrgios | $7^7$ | 4 | [4] | | | | | | | | | | |
| WC | D Evans L Glasspool | 7 | $6^5$ | [10] | WC | D Evans L Glasspool | $6^5$ | 6 | [10] | | | | | | | | | | |
| 2 | M Demoliner D Sharan | 5 | $7^7$ | [8] | | | | | | | | | | | | | | | |
