2018 Play In Challenger – Doubles
# 2018 Play In Challenger – Doubles

This was the first edition of the tournament.

Hugo Nys and Tim Pütz won the title after defeating Jeevan Nedunchezhiyan and Purav Raja $7–6^{(7–3)},$ 1–6, [10–7] in the final.

## Seeds

* Roman Jebavý / Antonio Šančić (quarterfinals)
* Jonathan Erlich / Ken Skupski (quarterfinals)
* Andre Begemann / Florin Mergea (first round, retired)
* Jeevan Nedunchezhiyan / Purav Raja (final)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | R Jebavý A Šančić | $7^8$ | 6 | | | | | | | | | | | | | | | |
| | Sa Ratiwatana So Ratiwatana | $6^6$ | 4 | | 1 | R Jebavý A Šančić | $6^4$ | 2 | | | | | | | | | | |
| | L Bambridge J Salisbury | 6 | 3 | [10] | | L Bambridge J Salisbury | $7^7$ | 6 | | | | | | | | | | |
| WC | N Desein Y Mertens | 3 | 6 | [5] | | | | | | | L Bambridge J Salisbury | $6^2$ | 4 | | | | | |
| 4 | J Nedunchezhiyan P Raja | 4 | 6 | [11] | | | | | | 4 | J Nedunchezhiyan P Raja | $7^7$ | 6 | | | | | |
| | S Arends T-S Weissborn | 6 | 1 | [9] | 4 | J Nedunchezhiyan P Raja | w/o | | | | | | | | | | | |
| WC | Q Halys U Humbert | $6^3$ | 6 | [10] | WC | Q Halys U Humbert | | | | | | | | | | | | |
| | A Behar G Oliveira | $7^7$ | 4 | [8] | | | | | | | | | | 4 | J Nedunchezhiyan P Raja | $6^3$ | 6 | [7] |
| | H Nys T Pütz | 6 | 6 | | | | | | | | | | | | H Nys T Pütz | $7^7$ | 1 | [10] |
| WC | D Descloix C Moutet | 4 | 3 | | | H Nys T Pütz | 6 | 6 | | | | | | | | | | |
| | B Mousley B Tomic | $7^8$ | 1 | | | B Mousley B Tomic | 3 | 1 | | | | | | | | | | |
| 3 | A Begemann F Mergea | $6^6$ | $0^r$ | | | | | | | | H Nys T Pütz | 6 | 6 | | | | | |
| | T Bednarek S Robert | 6 | 3 | [10] | | | | | | | T Bednarek S Robert | 2 | 3 | | | | | |
| | S Clayton D Pel | 3 | 6 | [2] | | T Bednarek S Robert | 4 | 7 | [10] | | | | | | | | | |
| | L Margaroli A Mies | 6 | 1 | [3] | 2 | J Erlich K Skupski | 6 | 5 | [7] | | | | | | | | | |
| 2 | J Erlich K Skupski | 4 | 6 | [10] | | | | | | | | | | | | | | |
