2018 Wimbledon Championships – Gentlemen's invitation doubles
# 2018 Wimbledon Championships – Gentlemen's invitation doubles

Lleyton Hewitt and Mark Philippoussis were the defending champions, but Hewitt accepted a wildcard to compete in the men's doubles main draw instead. Philippoussis played alongside Tommy Haas, and successfully defended his title, defeating Colin Fleming and Xavier Malisse in the final, $7–6^{(7–4)},$ 6–4.

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Final

| Final | Final | Final | Final | Final |
| - | - | - | - | - |
| A2 | Colin Fleming Xavier Malisse | $6^4$ | 4 | |
| B4 | Tommy Haas Mark Philippoussis | $7^7$ | 6 | |

### Group A

| | | Clément Maclagan | Fleming Malisse | Gimelstob Hutchins | Rusedski Santoro | RR W–L | Set W–L | Game W–L | Standings |
| - | - | - | - | - | - | - | - | - | - |
| A1 | Arnaud Clément Miles Maclagan | | $6–7^{(9–11)},$ 6–3, [3–10] | 2–6, 5–7 | 7–5, 6–3 | 1–2 | 3–4 | 32–32 | 2 |
| A2 | Colin Fleming Xavier Malisse | $7–6^{(11–9)},$ 3–6, [10–3] | | 7–5, $7–6^{(7–3)}$ | 6–4, 7–5 | 3–0 | 6–1 | 38–32 | 1 |
| A3 | Justin Gimelstob Ross Hutchins | 6–2, 7–5 | 5–7, $6–7^{(3–7)}$ | | 1–6, 4–6 | 1–2 | 2–4 | 29–33 | 4 |
| A4 | Greg Rusedski Fabrice Santoro | 5–7, 3–6 | 4–6, 5–7 | 6–1, 6–4 | | 1–2 | 2–4 | 29–31 | 3 |

### Group B

| | | Delgado Marray | Enqvist Johansson | González Grosjean | Haas Philippoussis | RR W–L | Set W–L | Game W–L | Standings |
| - | - | - | - | - | - | - | - | - | - |
| B1 | Jamie Delgado Jonathan Marray | | $6–7^{(3–7)},$ 3–6 | 6–4, 3–6, [7–10] | 3–6, 4–6 | 0–3 | 1–6 | 25–36 | 4 |
| B2 | Thomas Enqvist Thomas Johansson | $7–6^{(7–3)},$ 6–3 | | 5–7, 6–4, [10–4] | 2–6, $7–6^{(7–3)},$ [8–10] | 2–1 | 5–3 | 34–33 | 2 |
| B3 | Fernando González Sébastien Grosjean | 4–6, 6–3, [10–7] | 7–5, 4–6, [4–10] | | 3–6, 4–6 | 1–2 | 3–5 | 29–33 | 3 |
| B4 | Tommy Haas Mark Philippoussis | 6–3, 6–4 | 6–2, $6–7^{(3–7)},$ [10–8] | 6–3, 6–4 | | 3–0 | 6–1 | 37–23 | 1 |
