2020 ATP Finals – Doubles
# 2020 ATP Finals – Doubles

Wesley Koolhof and Nikola Mektić defeated Jürgen Melzer and Édouard Roger-Vasselin in the final, 6–2, 3–6, [10–5] to win the doubles tennis title at the 2020 ATP Finals. It was their first ATP Tour title together.

Pierre-Hugues Herbert and Nicolas Mahut were the reigning champions, but did not qualify this year.

Mate Pavić and Bruno Soares clinched the year-end world No. 1 doubles team ranking after Rajeev Ram and Joe Salisbury lost to Melzer and Roger-Vasselin in the semifinals.

## Seeds

* Mate Pavić / Bruno Soares (round robin)
* Rajeev Ram / Joe Salisbury (semifinals)
* Kevin Krawietz / Andreas Mies (round robin)
* Marcel Granollers / Horacio Zeballos (semifinals)
* Wesley Koolhof / Nikola Mektić (champions)
* John Peers / Michael Venus (round robin)
* Jürgen Melzer / Édouard Roger-Vasselin (final)
* Łukasz Kubot / Marcelo Melo (round robin)

## Alternates

* Jamie Murray / Neal Skupski (Did not play)
* Max Purcell / Luke Saville (Did not play)

## Draw

### Finals

| Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - |
| 7 | Jürgen Melzer Édouard Roger-Vasselin | $6^4$ | 6 | [11] | | | | | |
| 2 | Rajeev Ram Joe Salisbury | $7^7$ | 3 | [9] | | | | | |
| 2 | Rajeev Ram Joe Salisbury | $7^7$ | 3 | [9] | 7 | Jürgen Melzer Édouard Roger-Vasselin | 2 | 6 | [5] |
| | | | | | 5 | Wesley Koolhof Nikola Mektić | 6 | 3 | [10] |
| 5 | Wesley Koolhof Nikola Mektić | 6 | 6 | | 5 | Wesley Koolhof Nikola Mektić | 6 | 3 | [10] |
| 4 | Marcel Granollers Horacio Zeballos | 3 | 4 | | | | | | |

### Group Bob Bryan

| | | Pavić Soares | Granollers Zeballos | Peers Venus | Melzer Roger-Vasselin | RR W–L | Set W–L | Game W–L | Standings |
| - | - | - | - | - | - | - | - | - | - |
| 1 | Mate Pavić Bruno Soares | | $6–7^{(4–7)},$ $7–6^{(7–4)},$ [8–10] | $6–7^{(2–7)},$ 6–3, [10–8] | $6–7^{(6–8)},$ 6–1, [10–4] | 2–1 | 5–4 (55%) | 39–32 (55%) | 3 |
| 4 | Marcel Granollers Horacio Zeballos | $7–6^{(7–4)},$ $6–7^{(4–7)},$ [10–8] | | $7–6^{(7–2)},$ 7–5 | $6–6^{(0–1)}$ ret. | 2–1 | 4–3 (57%) | 34–30 (53%) | 2 |
| 6 | John Peers Michael Venus | $7–6^{(7–2)},$ 3–6, [8–10] | $6–7^{(2–7)},$ 5–7 | | 6–2, $6–7^{(4–7)},$ [10–12] | 0–3 | 2–6 (25%) | 33–37 (47%) | 4 |
| 7 | Jürgen Melzer Édouard Roger-Vasselin | $7–6^{(8–6)},$ 1–6, [4–10] | $6–6^{(1–0)}$ ret. | 2–6, $7–6^{(7–4)},$ [12–10] | | 2–1 | 5–3 (63%) | 24–31 (44%) | 1 |

* 1 2 Melzer/Roger-Vasselin's retirement victory over Granollers/Zeballos counted as a 2–0 set win.

### Group Mike Bryan

| | | Ram Salisbury | Krawietz Mies | Koolhof Mektić | Kubot Melo | RR W–L | Set W–L | Game W–L | Standings |
| - | - | - | - | - | - | - | - | - | - |
| 2 | Rajeev Ram Joe Salisbury | | $7–6^{(7–5)},$ $6–7^{(4–7)},$ [10–4] | $6–7^{(5–7)},$ 0–6 | 7–5, 3–6, [10–5] | 2–1 | 4–4 (50%) | 31–37 (46%) | 2 |
| 3 | Kevin Krawietz Andreas Mies | $6–7^{(5–7)},$ $7–6^{(7–4)},$ [4–10] | | $7–6^{(7–3)},$ $6–7^{(4–7)},$ [7–10] | 6–2, $7–6^{(7–5)}$ | 1–2 | 4–4 (50%) | 39–36 (52%) | 3 |
| 5 | Wesley Koolhof Nikola Mektić | $7–6^{(7–5)},$ 6–0 | $6–7^{(3–7)},$ $7–6^{(7–4)},$ [10–7] | | 4–6, $7–6^{(7–2)},$ [8–10] | 2–1 | 5–3 (63%) | 38–32 (54%) | 1 |
| 8 | Łukasz Kubot Marcelo Melo | 5–7, 6–3, [5–10] | 2–6, $6–7^{(5–7)}$ | 6–4, $6–7^{(2–7)},$ [10–8] | | 1–2 | 3–5 (38%) | 32–35 (48%) | 4 |

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, then percentage of games won, then head-to-head records; 5. ATP rankings.

