2015 Irving Tennis Classic – Singles
# 2015 Irving Tennis Classic – Singles

Lukáš Rosol was the defending champion, but withdrew because he was still playing in Indian Wells this year.

Aljaž Bedene won the title, defeating Tim Smyczek in the final, $7–6^{(7–3)},$ 3–6, 6–3.

## Seeds

* Jérémy Chardy (second round)
* Gilles Müller (semifinals)
* Benjamin Becker (quarterfinals)
* Dominic Thiem (second round)
* Sergiy Stakhovsky (second round)
* Jerzy Janowicz (second round)
* Marcos Baghdatis (quarterfinals)
* Diego Schwartzman (second round)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Finals

| Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - |
| Q | Kyle Edmund | $6^1$ | 1 | | | | |
| | Aljaž Bedene | $7^7$ | 6 | | | | |
| | Aljaž Bedene | $7^7$ | 6 | Aljaž Bedene | $7^7$ | 3 | 6 |
| | | | | Tim Smyczek | $6^3$ | 6 | 3 |
| | Tim Smyczek | 6 | $7^{10}$ | Tim Smyczek | $6^3$ | 6 | 3 |
| 2 | Gilles Müller | 4 | $6^8$ | | | | |

### Top half

| First round | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1/WC | J Chardy | 6 | 6 | | | | | | | | | | | | | | |
| Q | M Cecchinato | 3 | 2 | | 1/WC | J Chardy | 3 | 6 | 3 | | | | | | | | |
| | S Darcis | 6 | 6 | | | S Darcis | 6 | 4 | 6 | | | | | | | | |
| | J Ward | 4 | 4 | | | | | | | | S Darcis | $6^5$ | 2 | | | | |
| Q | K Edmund | 6 | 6 | | | | | | | Q | K Edmund | $7^7$ | 6 | | | | |
| | T Kamke | 4 | 4 | | Q | K Edmund | 3 | 6 | 6 | | | | | | | | |
| | G Elias | 3 | 6 | 2 | 8 | D Schwartzman | 6 | 3 | 1 | | | | | | | | |
| 8 | D Schwartzman | 6 | 3 | 6 | | | | | | | | | | Q | K Edmund | $6^1$ | 1 |
| 4 | D Thiem | 6 | 1 | 6 | | | | | | | | | | | A Bedene | $7^7$ | 6 |
| | D Sela | 3 | 6 | 3 | 4 | D Thiem | 4 | 6 | 2 | | | | | | | | |
| | A Bedene | 6 | 7 | | | A Bedene | 6 | 3 | 6 | | | | | | | | |
| | R Ram | 3 | 5 | | | | | | | | A Bedene | 6 | $7^7$ | | | | |
| | M Matosevic | $6^5$ | 6 | $6^5$ | | | | | | 7 | M Baghdatis | 3 | $6^5$ | | | | |
| | P-H Mathieu | $7^7$ | 1 | $7^7$ | | P-H Mathieu | 6 | $6^5$ | 1 | | | | | | | | |
| | D Brown | $6^6$ | $6^0$ | | 7 | M Baghdatis | 4 | $7^7$ | 6 | | | | | | | | |
| 7 | M Baghdatis | $7^8$ | $7^7$ | | | | | | | | | | | | | | |

### Bottom half

| First round | First round | First round | First round | First round | Second round | Second round | Second round | Second round | Second round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 5/WC | S Stakhovsky | 6 | 6 | | | | | | | | | | | | | | | |
| | T Bellucci | 4 | 4 | | 5/WC | S Stakhovsky | 5 | 6 | 3 | | | | | | | | | |
| | J-L Struff | $6^3$ | 2 | | | T Smyczek | 7 | 0 | 6 | | | | | | | | | |
| | T Smyczek | $7^7$ | 6 | | | | | | | | T Smyczek | 6 | 6 | | | | | |
| Q | Johannes Schretter | 1 | 0 | | | | | | | 3 | B Becker | 2 | 3 | | | | | |
| | D Džumhur | 6 | 6 | | | D Džumhur | 5 | 1 | | | | | | | | | | |
| | F Dustov | 3 | 3 | | 3 | B Becker | 7 | 6 | | | | | | | | | | |
| 3 | B Becker | 6 | 6 | | | | | | | | | | | | | T Smyczek | 6 | $7^{10}$ |
| 6 | J Janowicz | $7^7$ | 1 | 6 | | | | | | | | | | | 2 | G Müller | 4 | $6^8$ |
| WC | É Roger-Vasselin | $6^3$ | 6 | 2 | 6 | J Janowicz | 2 | $6^3$ | | | | | | | | | | |
| | A Zverev | 6 | 1 | 6 | | A Zverev | 6 | $7^7$ | | | | | | | | | | |
| Q | B Fratangelo | 4 | 6 | 1 | | | | | | | A Zverev | 2 | 6 | 4 | | | | |
| | D Kudla | 6 | $6^1$ | 6 | | | | | | 2 | G Müller | 6 | 3 | 6 | | | | |
| WC | M Russell | 4 | $7^7$ | 4 | | D Kudla | 4 | 0 | | | | | | | | | | |
| | P Andújar | $6^2$ | 4 | | 2 | G Müller | 6 | 6 | | | | | | | | | | |
| 2 | G Müller | $7^7$ | 6 | | | | | | | | | | | | | | | |
