2018 Sarasota Open – Doubles
# 2018 Sarasota Open – Doubles

Scott Lipsky and Jürgen Melzer were the defending champions but only Lipsky chose to defend his title, partnering Donald Young. Lipsky lost in the first round to Christian Harrison and Peter Polansky.

Evan King and Hunter Reese won the title after defeating Harrison and Polansky 6–1, 6–2 in the final.

## Seeds

* Ken Skupski / Neal Skupski (quarterfinals)
* Scott Lipsky / Donald Young (first round)
* Andre Begemann / Antonio Šančić (semifinals)
* Jeevan Nedunchezhiyan / Purav Raja (quarterfinals)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | K Skupski N Skupski | 6 | 6 | | | | | | | | | | | | | | |
| LL | F Coria JP Sorgi | 1 | 4 | | 1 | K Skupski N Skupski | 6 | $6^1$ | [7] | | | | | | | | |
| | E King H Reese | 6 | 6 | | | E King H Reese | 4 | $7^7$ | [10] | | | | | | | | |
| WC | D Baughman M Mmoh | 2 | 3 | | | | | | | | E King H Reese | 6 | 7 | | | | |
| 4 | J Nedunchezhiyan P Raja | 6 | 3 | [10] | | | | | | | L Bambridge J O'Mara | 4 | 5 | | | | |
| WC | R Galloway M Krueger | 3 | 6 | [7] | 4 | J Nedunchezhiyan P Raja | 5 | 2 | | | | | | | | | |
| WC | A Arnaboldi Sathi Reddy Chirala | 2 | 1 | | | L Bambridge J O'Mara | 7 | 6 | | | | | | | | | |
| | L Bambridge J O'Mara | 6 | 6 | | | | | | | | | | | | E King H Reese | 6 | 6 |
| | M Kecmanović B Rola | 3 | 3 | | | | | | | | | | | | C Harrison P Polansky | 1 | 2 |
| Q | M Cuevas H Dellien | 6 | 6 | | Q | M Cuevas H Dellien | 1 | 6 | [7] | | | | | | | | |
| | R Opelka M Polmans | $7^7$ | 3 | [4] | 3 | A Begemann A Šančić | 6 | 3 | [10] | | | | | | | | |
| 3 | A Begemann A Šančić | $6^5$ | 6 | [10] | | | | | | 3 | A Begemann A Šančić | 7 | 3 | [5] | | | |
| | T Daniel E López Pérez | $6^4$ | $6^3$ | | | | | | | | C Harrison P Polansky | 5 | 6 | [10] | | | |
| | G Clezar A Siljeström | $7^7$ | $7^7$ | | | G Clezar A Siljeström | $6^5$ | 3 | | | | | | | | | |
| | C Harrison P Polansky | 1 | 6 | [10] | | C Harrison P Polansky | $7^7$ | 6 | | | | | | | | | |
| 2 | S Lipsky D Young | 6 | 3 | [5] | | | | | | | | | | | | | |
