Challenger de Hong Kong 2015 (dobles masculino)
# Challenger de Hong Kong 2015 (dobles masculino)

Hong Kong ATP Challenger :

| Campeones: | Hsieh Cheng-peng Yi Chu-huan | Hsieh Cheng-peng Yi Chu-huan | Hsieh Cheng-peng Yi Chu-huan | Hsieh Cheng-peng Yi Chu-huan | Hsieh Cheng-peng Yi Chu-huan | Hsieh Cheng-peng Yi Chu-huan | Hsieh Cheng-peng Yi Chu-huan | Hsieh Cheng-peng Yi Chu-huan | Hsieh Cheng-peng Yi Chu-huan |
| - | - | - | - | - | - | - | - | - | - |
| Subcampeones: | Saketh Myneni Sanam Singh | Saketh Myneni Sanam Singh | Saketh Myneni Sanam Singh | Saketh Myneni Sanam Singh | Saketh Myneni Sanam Singh | Saketh Myneni Sanam Singh | Saketh Myneni Sanam Singh | Saketh Myneni Sanam Singh | Saketh Myneni Sanam Singh |
| Resultado: | 6–4, 6–2 | 6–4, 6–2 | 6–4, 6–2 | 6–4, 6–2 | 6–4, 6–2 | 6–4, 6–2 | 6–4, 6–2 | 6–4, 6–2 | 6–4, 6–2 |
| Modalidades |||||||||||
| Individual | Masculino | | | |
| Dobles | Masculino | |

## Presentación previa

Por ser un torneo nuevo no tiene defensores de título.

Hsieh Cheng-peng y Yi Chu-huan ganaron el título tras derrotar en la final Saketh Myneni y Sanam Singh.

## Cabeza de serie

| Marcus Daniell / Artem Sitak (Primera ronda) Frank Moser / Divij Sharan (Cuartos de final) | Sanchai Ratiwatana / Sonchat Ratiwatana (Semifinales, baja) Gong Maoxin / Peng Hsien-yin (Primera ronda) |
| - | - |

## Cuadro

| Primera ronda | Primera ronda | Primera ronda | Primera ronda | Primera ronda | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Semifinales | Semifinales | Semifinales | Semifinales | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | M Daniell A Sitak | 4 | 5 | |
| | J Eysseric T Sandgren | 6 | 7 | |
| | J Eysseric T Sandgren | 6 | 7 | | | J Eysseric T Sandgren | 1 | 6 | [9] |
| | | | | | | S Myneni S Singh | 6 | 1 | [11] |
| | S Myneni S Singh | 4 | 6 | [10] | | S Myneni S Singh | 6 | 1 | [11] |
| | F Martin P Raja | 6 | 3 | [4] | | | | | |
| | F Martin P Raja | 6 | 3 | [4] | | | | | | | S Myneni S Singh | 6 | 6 |
| | | | | | | | | | | | N Desein M Ebden | 1 | 2 |
| 4 | M Gong H-y Peng | 1 | 4 | | | | | | | | N Desein M Ebden | 1 | 2 |
| | N Desein M Ebden | 6 | 6 | | | | | | | | | | |
| | N Desein M Ebden | 6 | 6 | | | N Desein M Ebden | 6 | 6 | | | | | |
| | | | | | | H-h Lee T-h Yang | 3 | 4 | | | | | |
| | H-h Lee T-h Yang | 6 | $7^7$ | | | H-h Lee T-h Yang | 3 | 4 | | | | | |
| | T Chen T Matsui | 3 | $6^5$ | | | | | | | | | | |
| | T Chen T Matsui | 3 | $6^5$ | | | | | | | | | | | | S Myneni S Singh | 4 | 2 |
| | | | | | | | | | | | | | | WC | C-p Hsieh C-h Yi | 6 | 6 |
| | R Albot J Thompson | 6 | 3 | [10] | | | | | | | | | | WC | C-p Hsieh C-h Yi | 6 | 6 |
| | S Devvarman D Wu | 3 | 6 | [5] | | | | | | | | | |
| | S Devvarman D Wu | 3 | 6 | [5] | | R Albot J Thompson | 0 | 4 | | | | | |
| | | | | | 3 | Sa Ratiwatana So Ratiwatana | 6 | 6 | | | | | |
| WC | P Petzschner Hong Kit Wong | 1 | $6^1$ | | 3 | Sa Ratiwatana So Ratiwatana | 6 | 6 | | | | | |
| 3 | Sa Ratiwatana So Ratiwatana | | $7^7$ | | | | | | | | | | |
| 3 | Sa Ratiwatana So Ratiwatana | | $7^7$ | | | | | | | 3 | Sa Ratiwatana So Ratiwatana | | |
| | | | | | | | | | | WC | C-p Hsieh C-h Yi | w/o | |
| WC | C-p Hsieh C-h Yi | 6 | 6 | | | | | | | WC | C-p Hsieh C-h Yi | w/o | |
| WC | Hei Yin Andrew Li J Wang | 4 | 3 | | | | | | |
| WC | Hei Yin Andrew Li J Wang | 4 | 3 | | WC | C-p Hsieh C-h Yi | 6 | 6 | |
| | | | | | 2 | F Moser D Sharan | 1 | 1 | |
| | L-c Huang Y Sugita | 5 | 1 | | 2 | F Moser D Sharan | 1 | 1 | |
| 2 | F Moser D Sharan | 7 | 6 | |
