Challenger de Drummondville 2017 (dobles masculino)
# Challenger de Drummondville 2017 (dobles masculino)

Challenger Banque Nationale de Drummondville :

| Campeones: | Sam Groth Adil Shamasdin | Sam Groth Adil Shamasdin | Sam Groth Adil Shamasdin | Sam Groth Adil Shamasdin | Sam Groth Adil Shamasdin | Sam Groth Adil Shamasdin | Sam Groth Adil Shamasdin | Sam Groth Adil Shamasdin | Sam Groth Adil Shamasdin |
| - | - | - | - | - | - | - | - | - | - |
| Subcampeones: | Matt Reid John-Patrick Smith | Matt Reid John-Patrick Smith | Matt Reid John-Patrick Smith | Matt Reid John-Patrick Smith | Matt Reid John-Patrick Smith | Matt Reid John-Patrick Smith | Matt Reid John-Patrick Smith | Matt Reid John-Patrick Smith | Matt Reid John-Patrick Smith |
| Resultado: | 6–3, 2–6, [10–8] | 6–3, 2–6, [10–8] | 6–3, 2–6, [10–8] | 6–3, 2–6, [10–8] | 6–3, 2–6, [10–8] | 6–3, 2–6, [10–8] | 6–3, 2–6, [10–8] | 6–3, 2–6, [10–8] | 6–3, 2–6, [10–8] |
| Modalidades |||||||||||
| Individual | Masculino | | | |
| Dobles | Masculino | |
| 2016 « Challenger de Drummondville » 2018 |||||||||||

## Presentación previa

James Cerretani y Max Schnur eran ellos defensores del título, decidieron no participar este año.

Sam Groth y Adil Shamasdin ganaron el título tras derrotar en la final Matt Reid y John-Patrick Smith.

## Cabeza de serie

| Sam Groth / Adil Shamasdin (Campeones) Matt Reid / John-Patrick Smith (Finalistas) | Riccardo Ghedin / Andreas Mies (Cuartos de final) Philip Bester / Luke Saville (Semifinales) |
| - | - |

## Cuadro

| Primera ronda | Primera ronda | Primera ronda | Primera ronda | Primera ronda | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Cuartos de final | Semifinales | Semifinales | Semifinales | Semifinales | Semifinales | Final | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| 1 | Sam Groth Adil Shamasdin | 6 | 6 | |
| | Isak Arvidsson Frederik Nielsen | 4 | 4 | |
| | Isak Arvidsson Frederik Nielsen | 4 | 4 | | 1 | S Groth A Shamasdin | w/o | | |
| | | | | | | M Neuchrist D Pel | | | |
| | Maximilian Neuchrist David Pel | 6 | 3 | [10] | | M Neuchrist D Pel | | | |
| | Jarryd Chaplin Ben McLachlan | 3 | 6 | [8] | | | | | |
| | Jarryd Chaplin Ben McLachlan | 3 | 6 | [8] | | | | | | 1 | S Groth A Shamasdin | $6^4$ | $7^7$ | [11] |
| | | | | | | | | | | | D O'Hare J Salisbury | $7^7$ | $6^4$ | [9] |
| 3 | Riccardo Ghedin Andreas Mies | 6 | 6 | | | | | | | | D O'Hare J Salisbury | $7^7$ | $6^4$ | [9] |
| | Peter Polansky Tennys Sandgren | 4 | 4 | | | | | | | | | | | |
| | Peter Polansky Tennys Sandgren | 4 | 4 | | 3 | R Ghedin A Mies | 6 | 2 | [9] | | | | | |
| | | | | | | D O'Hare J Salisbury | 3 | 6 | [11] | | | | | |
| WC | Filip Peliwo Brayden Schnur | 4 | 2 | | | D O'Hare J Salisbury | 3 | 6 | [11] | | | | | |
| | David O'Hare Joe Salisbury | 6 | 6 | | | | | | | | | | | |
| | David O'Hare Joe Salisbury | 6 | 6 | | | | | | | | | | | | 1 | S Groth A Shamasdin | 6 | 2 | [10] |
| | | | | | | | | | | | | | | | 2 | M Reid J-P Smith | 3 | 6 | [8] |
| | Austin Krajicek Jackson Withrow | $6^1$ | 6 | [10] | | | | | | | | | | | 2 | M Reid J-P Smith | 3 | 6 | [8] |
| | Maxime Authom Vincent Millot | $7^7$ | 3 | [3] | | | | | | | | | | |
| | Maxime Authom Vincent Millot | $7^7$ | 3 | [3] | | A Krajicek J Withrow | 6 | $6^5$ | [11] | | | | | |
| | | | | | 4 | P Bester L Saville | 3 | $7^7$ | [13] | | | | | |
| WC | Isade Juneau Samuel Monette | $6^3$ | 3 | | 4 | P Bester L Saville | 3 | $7^7$ | [13] | | | | | |
| 4 | Philip Bester Luke Saville | $7^7$ | 6 | | | | | | | | | | | |
| 4 | Philip Bester Luke Saville | $7^7$ | 6 | | | | | | | 4 | P Bester L Saville | 4 | $6^2$ | |
| | | | | | | | | | | 2 | M Reid J-P Smith | 6 | $7^7$ | |
| | Sekou Bangoura Edward Corrie | $7^7$ | 4 | [7] | | | | | | 2 | M Reid J-P Smith | 6 | $7^7$ | |
| WC | Félix Auger-Aliassime Denis Shapovalov | $6^2$ | 6 | [10] | | | | | |
| WC | Félix Auger-Aliassime Denis Shapovalov | $6^2$ | 6 | [10] | WC | F Auger-Aliassime D Shapovalov | $7^7$ | 1 | [8] |
| | | | | | 2 | M Reid J-P Smith | $6^5$ | 6 | [10] |
| | Hugo Nys Yannik Reuter | 4 | 4 | | 2 | M Reid J-P Smith | $6^5$ | 6 | [10] |
| 2 | Matt Reid John-Patrick Smith | 6 | 6 | |
