2018 Koser Jewelers Tennis Challenge – Doubles
# 2018 Koser Jewelers Tennis Challenge – Doubles

Sophie Chang and Alexandra Mueller were the defending champions, but lost in the first round to Luisa Stefani and Renata Zarazúa.

Ellen Perez and Arina Rodionova won the title, defeating Chen Pei-hsuan and Wu Fang-hsien in the final, 6–0, 6–2.

## Seeds

* Ellen Perez / Arina Rodionova (champions)
* Jamie Loeb / Sabrina Santamaria (first round)
* Lucie Hradecká / Arantxa Rus (first round)
* Anastasia Potapova / Vera Zvonareva (semifinals; retired)

## Draw

### Key

* Q = Qualifier
* WC = Wild card
* LL = Lucky loser
* Alt = Alternate
* SE = Special exempt
* PR = Protected ranking
* ITF = ITF entry
* JE = Junior exempt
* w/o = Walkover
* r = Retired
* d = Defaulted
* SR = Special ranking

### Draw

| First round | First round | First round | First round | First round | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Quarterfinals | Semifinals | Semifinals | Semifinals | Semifinals | Final | Final | Final | Final |
| - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - | - |
| | | | | | 1 | E Perez Ar Rodionova | 7 | 6 | | | | | | | | | |
| | S Chang A Mueller | 2 | 5 | | | L Stefani R Zarazúa | 5 | 4 | | | | | | | | | |
| | L Stefani R Zarazúa | 6 | 7 | | | | | | | 1 | E Perez Ar Rodionova | 3 | | | | | |
| 4 | A Potapova V Zvonareva | 6 | 6 | | | | | | | 4 | A Potapova V Zvonareva | $2^r$ | | | | | |
| | J Elie J Robinson | 2 | 2 | | 4 | A Potapova V Zvonareva | w/o | | | | | | | | | | |
| | O Govortsova N Kukharchuk | 5 | 4 | | | G Taylor E Webley-Smith | | | | | | | | | | | |
| | G Taylor E Webley-Smith | 7 | 6 | | | | | | | | | | | 1 | E Perez Ar Rodionova | 6 | 6 |
| | K Ahn A Kalinina | 6 | 0 | | | | | | | | | | | | P-h Chen F-h Wu | 0 | 2 |
| | H Dart K Dunne | 0 | $0^r$ | | | K Ahn A Kalinina | 2 | 6 | [10] | | | | | | | | |
| | N Dzalamidze V Savinykh | 6 | 3 | [13] | | N Dzalamidze V Savinykh | 6 | 1 | [7] | | | | | | | | |
| 3 | L Hradecká A Rus | 2 | 6 | [11] | | | | | | | K Ahn A Kalinina | 3 | 3 | | | | |
| | V Rodríguez O Tjandramulia | 3 | 2 | | | | | | | | P-h Chen F-h Wu | 6 | 6 | | | | |
| | H Carter E Shibahara | 6 | 6 | | | H Carter E Shibahara | 6 | 4 | [4] | | | | | | | | |
| | P-h Chen F-h Wu | 6 | $6^4$ | [10] | | P-h Chen F-h Wu | 3 | 6 | [10] | | | | | | | | |
| 2 | J Loeb S Santamaria | 3 | $7^7$ | [7] | | | | | | | | | | | | | |
